Question 14 Marks
Read the passage given below and answer the following questions from 1 to 5. Beat The phenomenon of regular variation in intensity of sound with time at a particular position due to superposition of two sound waves of slightly different frequencies is called beats. For waves
$\therefore\text{y}=2\text{a}\cos\pi(\text{v}_1-\text{v}_2)\text{t}.\sin\pi(\text{v}_1-\text{v}_2)\text{t}$ is the required equation of beats. Beat frequency is given by $\text{v}_{\text{beat}}=\text{v}_1-\text{v}_2$ Beat period is given by
$\text{T}=\frac{1}{\text{Beat frequency}}=\frac{1}{\text{v}_1-\text{v}_2}$
$\therefore\text{y}=2\text{a}\cos\pi(\text{v}_1-\text{v}_2)\text{t}.\sin\pi(\text{v}_1-\text{v}_2)\text{t}$ is the required equation of beats. Beat frequency is given by $\text{v}_{\text{beat}}=\text{v}_1-\text{v}_2$ Beat period is given by
$\text{T}=\frac{1}{\text{Beat frequency}}=\frac{1}{\text{v}_1-\text{v}_2}$
- Which of the following phenomenon is used by the musicians to tune their musical instruments?
- Interference
- Diffraction
- Beats
- Polarisation
- The phenomenon of beats can take place
- For longitudinal waves only
- For transverse wave only
- For sound waves only
- For both longitudinal and transverse waves
- When two waves of almost equal frequencies $v_1$ and $v_2$ reach at a point simultaneously, the time interval between successive maxima is:
- $\text{v}_1+\text{v}_2$
- $\text{v}_1-\text{v}_2$
- $\frac{1}{\text{v}_1+\text{v}_2}$
- $\frac{1}{\text{v}_1-\text{v}_2}$
- Two turning forks of frequencies $n_1$ and $n_2$ produces n beats per second. If $n_2$ and n are known, $n_1$ may be given by:
- $\frac{\text{n}_2}{\text{n}}+\text{n}_2$
- $\text{n}_2\text{n}$
- $\text{n}_2\pm\text{n}$
- $\frac{\text{n}_2}{\text{n}}-\text{n}_2$
- P and Q are two wires whose fundamental frequencies are 256 Hz and 382 Hz respectively. How many beats in two seconds will be heard by the third harmonic of A and second harmonic of B?
- 4
- 8
- 16
- zero
Answer
The phenomenon of beats can take place for both longitudinal and transverse waves.
When two waves of almost equal frequencies $v_1$ and $v_2$ reach at a point simultaneously, beats are produced.
Beat frequency, $\text{v}_{\text{beat}}=\text{v}_1-\text{v}_2$ Time interval between successive maxima
$=\frac{1}{\text{v}_{\text{beat}}}=\frac{1}{\text{v}_1-\text{v}_2}$
Beat frequency = number of beats/sec.
$n = n_2 - n_1$ or $n_1 - n_2$
$\therefore\text{n}_1=\text{n}_2\pm\text{n}$
Beat frequency = $3v_1 - 2v_2 = 3 \times 256 - 2 \times 382 = 768 - 764 = 4 s^{-1}$
Number of beats produced in 2 seconds = 4 × 2 = 8
View full question & answer→- (c) Beats
- (d) For both longitudinal and transverse waves
The phenomenon of beats can take place for both longitudinal and transverse waves.
- (d) $\frac{1}{\text{v}_1-\text{v}_2}$
When two waves of almost equal frequencies $v_1$ and $v_2$ reach at a point simultaneously, beats are produced.
Beat frequency, $\text{v}_{\text{beat}}=\text{v}_1-\text{v}_2$ Time interval between successive maxima
$=\frac{1}{\text{v}_{\text{beat}}}=\frac{1}{\text{v}_1-\text{v}_2}$
- (c) $\text{n}_2\pm\text{n}$
Beat frequency = number of beats/sec.
$n = n_2 - n_1$ or $n_1 - n_2$
$\therefore\text{n}_1=\text{n}_2\pm\text{n}$
- (b) 8
Beat frequency = $3v_1 - 2v_2 = 3 \times 256 - 2 \times 382 = 768 - 764 = 4 s^{-1}$
Number of beats produced in 2 seconds = 4 × 2 = 8
