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Question 11 Mark
Express the number appearing in the statement in standard form. The earth has $1,353,000,000$ cubic km of sea water.
Answer
Given that,
Area of sea water on earth $=1,353,000,000$ cubic km
Thus, it can be expressed in standard form as,
$1,353,000,000=1.353 \times 10^9$ cubic km
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Question 21 Mark
Express the number appearing in the statement in standard form: $60,230, 000,000,000,000,000,000$ molecules are contained in a drop of water weighting $1.8 gm.$
Answer
Given that,
Total number of molecules in a drop of water weighing $1.8$ gram $= 60, 230, 000, 000, 000, 000, 000, 000 m$
Thus,
$60,230,000,000,000,000,000,000=6023 \times 10^{19}$ or, $6.023 \times 10^{22}$
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Question 31 Mark
Express the number appearing in the statement in standard form: The universe is estimated to be about $12,000,000,000$ years old.
Answer
Estimated age of universe $= 12, 000, 000, 000$ years
Thus, it can be expressed as,
$12,000,000,000=1.2 \times 10^{10}$ years
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Question 41 Mark
Express the number appearing in a statement in standard form. In a galaxy, there are on an average $100,000,000,000$ stars.
Answer
Given that,
Average number of stars in galaxy $= 100, 000, 000, 000$ stars
Thus, it can be expressed as,
$100,000,000,000=1 \times 10^{11}$ stars
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Question 51 Mark
Express the number appearing in the following statements in standard form. Diameter of the Sun is $1,400,000,000 m.$
Answer
Given that,
Diameter of Sun $= 1, 400, 000, 000 m$
Thus, it can be expressed as,
$1,400,000,000=1.4 \times 10^9 \mathrm{~m}$
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Question 61 Mark
Express the number appearing in the statement in standard form. Diameter of the Earth is $1,27,56,000 m.$
Answer
Given that,
Diameter of Earth $= 1, 27, 56, 000 m$
Thus it can be expressed as,
$1,27,56,000=12756 \times 10^3 \mathrm{~m}$
$=1.2756 \times 10^7 \mathrm{~m}$
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Question 71 Mark
Express the number appearing in a statement in standard form. Speed of light in vacuum is $300,000,000 m/s.$
Answer
Given that, Speed of light in vacuum $= 300, 000, 000 m/s$
Thus,
$300,000,000=3 \times 10^8 \mathrm{~m} / \mathrm{s}$
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Question 81 Mark
Express the number appearing in the statement in standard form: The population of India was about $1,027,000,000$ in March $2001.$
Answer
Given that,
Population of India in March $2001= 1, 027, 000, 000$
Thus, it can be expressed as,
$1,027,000,000=1.027 \times 10^9$
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Question 91 Mark
Express the number appearing in the statement in standard form. The distance between Earth and Moon is $384,000,000 m.$
Answer
It is given that,
Distance between Earth and Moon $=384,000,000 \mathrm{~m}$
Thus,
$384,000,000=3.84 \times 10^8 \mathrm{~m}$
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Question 161 Mark
Find the number from the expanded form: $9 \times 10^5+2 \times 10^2+3 \times 10^1$
Answer
$9 \times 10^5+2 \times 10^2+3 \times 10^1=900230$
$900000+00000+0000+200+30=900230$
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Question 171 Mark
Find the number from the expanded form: $3 \times 10^4+7 \times 10^2+5 \times 10^0$
Answer
$3 \times 10^4+7 \times 10^2+5 \times 10^0=30705$
$30000+0000+700+00+5=30705$
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Question 181 Mark
Find the number from the expanded form: $4 \times 10^5+5 \times 10^3+3 \times 10^2+2 \times 10^0$
Answer
$4 \times 10^5+5 \times 10^3+3 \times 10^2+2 \times 10^0=405302$
$400000+00000+5000+300+00+2=405302$
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Question 191 Mark
Find the number from the expanded form: $8 \times 10^4+6 \times 10^3+0 \times 10^2+4 \times 10^1+5 \times 10^0$
Answer
$8 \times 10^4+6 \times 10^3+0 \times 10^2+4 \times 10^1+5 \times 10^0=86045$
$80000+6000+000+40+5=86045$
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Question 201 Mark
Write the number in expanded form: $20068$
Answer
$20068=2 \times 10000+0 \times 1000+0 \times 100+6 \times 10+8 \times 1$
$=2 \times 10^4+0 \times 10^3+0 \times 10^2+6 \times 10^1+8 \times 10^0$
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Question 211 Mark
Write the number in expanded form: $120719$
Answer
$120719=1 \times 100000+2 \times 10000+0 \times 1000+7 \times 100+1 \times 10+9 \times 1$
$=1 \times 10^5+2 \times 10^4+0 \times 10^3+7 \times 10^2+1 \times 10^1+9 \times 10^0$
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Question 221 Mark
Write the number in expanded forms: $2806196$
Answer
$2806196=2 \times 1000000+8 \times 100000+0 \times 10000+6 \times 1000+1 \times 100+9 \times 10+6 \times 1$
$=2 \times 10^6+8 \times 10^5+0 \times 10^4+6 \times 10^3+1 \times 10^2+9 \times 10^1+6 \times 10^0$
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Question 231 Mark
Write the number in expanded form: $3006194$
Answer
$3006194=3 \times 1000000+0 \times 100000+0 \times 10000+6 \times 1000+1 \times 100+9 \times 10+4 \times 1$
$=3 \times 10^6+0 \times 10^5+0 \times 10^4+6 \times 10^3+1 \times 10^2+9 \times 10^1+4 \times 10^0$
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Question 241 Mark
Write the number in expanded form: 279404
Answer
$279404=2 \times 100000+7 \times 10000+9 \times 1000+4 \times 100+0 \times 10+4 \times 1$
$=2 \times 10^5+7 \times 10^4+9 \times 10^3+4 \times 10^2+0 \times 10^1+4 \times 10^0$
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Question 251 Mark
Using laws of exponents, simplify and write the answer in exponential form $\left(3^4\right)^3$
Answer
We have,
$\left(3^4\right)^3$
We know that, $\left(a^m\right)^n=a^{m n}$
Thus,
$\left(3^4\right)^3=3^{4 \times 3}=3^{12}$
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Question 261 Mark
Using laws of exponents, simplify and write the answer in exponential form $7^x \times 7^2$
Answer
Here,
$7^x \times 7^2$
We know that, $a^m \times a^n=a^{m+n}$
Thus,
$7^x \times 7^2=(7)^{x+2}$
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Question 271 Mark
Using laws of exponent, simplify and write the answer in exponential form: $a^3 \times a^2$
Answer
By the law of exponents, $x^m \times x^n=x^{m+n}$
By applying this law, $a^3 \times a^2=a^{3+2}=a^5$
Hence $a^3 \times a^2=a^5$
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Question 281 Mark
Using laws of exponent, simplify and write the answer in exponential form: $8^t \div 8^2$
Answer
By the law of exponenets we have $x^m \div x^n=x^{m-n}$
By applying this law, $8^{\mathrm{t}} \div 8^2=8^{\mathrm{t}-2}$
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Question 291 Mark
Simplify: $(-3) \times(-2)^3$
Answer
In order to find $(-2)^3$, we should multiply $(-2) 3$ times
$(-2)^3=(-2) \times(-2) \times(-2)=(-8)$
$(-3) \times(-2)^3=(-3) \times(-8)=24$
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Question 311 Mark
Simplify: $3^2 \times 10^4$
Answer
We have, $3^2 \times 10^4=3 \times 3 \times 10 \times 10 \times 10 \times 10=9 \times 10000=90000$
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Question 321 Mark
Simplify: $2^4 \times 3^2$
Answer
In order to find $2^4$, we should multiply $2$ four times
$2^4=2 \times 2 \times 2 \times 2=16$
In order to find $3^2$, we should multiply $3$ two times
$3^2=3 \times 3=9$
$2^4 \times 3^2=16 \times 9=144$
$2^4 \times 3^2=144$
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Question 331 Mark
Simplify: $5^2 \times 3^3$
Answer
To find $5^2$, multiply $5$ , two times
$5^2=5 \times 5=25$
To find $3^3$, multiply $3$ , three times
$3^3=3 \times 3 \times 3=27$
Hence, $5^2 \times 3^3=25 \times 27=675$
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Question 341 Mark
Simplify: $0 \times 10^2$
Answer
Any number multiplied by $'0'$ is $'0'$, however big the number is
Hence, $0 \times 10^2 = 0$
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Question 351 Mark
Simplify: $3 \times 4^4$
Answer
Here,
$3 \times 4^4$
$=3 \times 4 \times 4 \times 4 \times 4$
$=3 \times 256$
$=768$
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Question 361 Mark
Simplify: $2^3 \times 5$
Answer
In order to get $2^3$, multiply $2$ three times
$2^3=2 \times 2 \times 2=8$
$2^3 \times 5=8 \times 5=40$
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Question 371 Mark
Simplify: $7^2 \times 2^2$
Answer
In order to get $7^2$, multiply $7$ two times
$7^2=7 \times 7=49$
In order to get $2^2$, multiply $2$ two times
$2^2=2 \times 2=4$
Hence $7^2 \times 2^2=49 \times 4=196$
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Question 381 Mark
Simplify: $2 \times 10^3$
Answer
To expand $10^3$, multiply $10$ three times
$10^3=10 \times 10 \times 10=1000$
$2 \times 10^3=2 \times 1000=2000$
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Question 391 Mark
Express the number as a product of power of its prime factors: $405$
Answer
To get the prime factors, divide the number $405$ with the prime numbers ​
​​​​​​
$\therefore 405=3 \times 3 \times 3 \times 3 \times 5=3^4 \times 5$
It is the required prime factor product form.
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Question 401 Mark
Identify the greater number, if possible: $2^{10}$ or $10^2$
Answer
In order to find the greater number, we should expand and find the value of $2^{10}$ and $10^2$
$2^{10}=2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2=1024$
$10^2=10 \times 10=100$
Since $1024>100,2^{10}>10^2$
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Question 411 Mark
Express the number using exponential notation: $3125$
Answer
$3125$

We have,
$3125=5 \times 5 \times 5 \times 5 \times 5=5^5$
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Question 421 Mark
Express the number using the exponential notation: $343$
Answer
In order to express $343$ in exponential notation, we should find the prime factors of $343$ and express $343$ as the product of its prime factors

$\therefore 343=7 \times 7 \times 7=7^3$
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Question 431 Mark
Express in exponential form: $a \times a \times a \times c \times c \times c \times c \times d$
Answer
We have,
$a \times a \times a \times c \times c \times c \times c \times d$
$=a^{1+1+1} \times c^{1+1+1+1} \times d^1$ [Bases are same, powers are added] 
$=a^3 \times c^4 \times d$
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Question 441 Mark
Express in exponential form: $2 \times 2 \times a \times a$
Answer
We have,
$2 \times 2 \times a \times a$
$=2^{1+1} \times a^{1+1}$[ Bases are same, powers are added]
$=2^2 \times a^2$
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Question 451 Mark
Express in exponential form: $5 \times 5 \times 7 \times 7 \times 7$
Answer
We have,
$5 \times 5 \times 7 \times 7 \times 7$
$=5^{1+1} \times 7^{1+1+1}$ [Bases are same, powers are added] 
$=5^2 \times 7^3$
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Question 461 Mark
Express in exponential form: $b \times b \times b \times b$
Answer
We have,
$b \times b \times b \times b$
$=b^{1+1+1+1}$ [Bases are same, powers are added]
$=b^4$
 
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Question 471 Mark
Express in exponential form: $t \times t$
Answer
We have,
$t \times t$
$=t^{1+1}$ [Bases are same, powers are added]
$=t^2$
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Question 481 Mark
Express in exponential form: $6 \times 6 \times 6 \times 6$
Answer
We have,
$6 \times 6 \times 6 \times 6$
$=6^{1+1+1+1} $ [Bases are same, powers are added]
$=6^4$
 
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Question 491 Mark
Find the value of $5^4$
Answer
In order to get the value of $5^4$, we should multiply $5, 4$ timesHence $5^4=5 \times 5 \times 5 \times 5=625$.
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Question 501 Mark
Find the value of $11^2$
Answer
In order to find the value $11^2$, multiply $11,2$ timesHence $11^2=11 \times 11=121$
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