MATHS M.C.Q. [1 Marks Each]

$6\text{cm}=\frac{6}{100}\text{m}$
$=\frac{6}{100\times1000}\text{km}$
$=\frac{6}{100000}=0.00006\text{km}$

$0.04=\frac{104}{100}=\frac{26}{25}=1\frac{1}{25}$

We know that,
$1\text{ml}=\frac{1}{1000}\text{l}$
$\therefore\ 8\text{ml}=\frac{8}{1000}\text{l}$
$=0.008\text{l}$

Let the length of the platform be $x$ metres
Length of the platform $= 300\ m$
Speed of the train$ =\frac{300}{18}$
$ =\frac{50}{3}\text{m/s}$
$ \frac{50}{3}=\frac{X+ 300}{39}$
$ \text{50}\times{39}=3\text{x} + 900$
$ \text{1950}=3\text{x} + 900$
$ 3\text{x} = 1950 - 900$
$ 3\text{x} = 1050$
$ \text{x} = \frac{1050}{3}$
$ \text{x} = 350$
So, the length of of the platform, $x = 350\ m$

We have, $\frac{1}{3}\ \text{of}\ \frac{1}{6}=\frac{1}{3}\times\frac{1}{6}$
Note of represents multiplication$(×).$

 To write it as a decimal we divide the numerator from the denominator.
$\frac{9}{1000}= 0.009$
So, $0.009$ is the decimal representation for $\frac{9}{1000}.$

 Converting fraction to decimal $= \frac{3}{10} = 0.3$

In order to find the product, we first multiply $22$ by $2$
We have, $22 \times 2 = 44$
Now, $2.2$ has $1$ decimal place, $0.2$ has $1$ decimal place and $0.001$ has $3$ decimal places.
The sum of the decimal places is $1 + 1 + 3 = 5$
So, the product must contain 5 places of decimals.
$\therefore 2.2 \times 0.2 \times 0.001 = 0.00044$
Thus, the value of $2.2 \times 0.2 \times 0.001 is 0.00044$

Since we are given a mixed fraction so the resulting fraction will be: $ =\frac{(3\times10) +6 }{10}=\frac{36}{10}$

To write it as a decimal we divide the numerator with the denominator.
$\frac{78}{100}= 0.780.78$ is the decimal representation for $\frac{78}{100}.$

$2.73\div1.3=\frac{2.73}{1.3}$
$=\frac{273\times10}{13\times100}=\frac{273}{130}=\frac{21}{10}=2.1$

It is given that,
$14 × 4 = 56$
Now, $0.014$ has $3$ decimal places.
So, the required product must contain $3$ places of decimals.
$\therefore 0.014 × 4 = 0.056$

Given, $3\frac{3}{4}\div\frac{3}{4}$
$\because\ 3\frac{3}{4}=\frac{(3\times4)+3}{4}=\frac{12+3}{4}=\frac{15}{4}$
$\therefore3\frac{3}{4}\div\frac{3}{4}=\frac{15}{4}\times\frac{4}{3}=5$
$\bigg[\because\text{reciprocal of} \frac{3}{4}=\frac{4}{3}\bigg]$

$ 0.585=0.5 +0.08+0.005=\frac{5}{10}+\frac{8}{100}+\frac{5}{1000} $
$ 0.585=\frac{585}{1000}$

$2.08\div(0.16)=\frac{2.08}{0.16}=\frac{2.08\times100}{0.16\times100}$
$=\frac{208}{16}=13$

First, we will find the product $11 \times 1 \times 1$
i.e., $11 \times 1 \times 1 = 11 \times 1 = 11$
Sum of decimal places in the given decimals $= (1 + 1 + 2) = 4$
$1.1 \times 0.1 \times 0.01 = 0.0011 [4$ places of decimal$]$

 Here, $4$ is in tens place. Hence, its place value is $40.$

$1.008=\frac{1.008\times1000}{1\times1000}=\frac{1008}{1000}$
$=\frac{126}{125}=1\frac{1}{125}$

$0.23 \times 0.3 = 0.069$

 $=0.002\times0.5$
$=\frac{2}{1000}\times\frac{5}{10}$
$=\frac{2\times5}{1000\times10}$
$=\frac{10}{10000}$
$=\frac{1}{1000}$
$=0.01$

 To round $13.73$ to nearest tenth means to round the numbers so you only have one digit in the fractional part.
So, If the last digit in the fractional part of $13.73$ is less than $5,$ then we simply remove the last the digit of fractional part.

To convert a decimal to a fraction, write it over the appropriate power of $10$ and simplify:
$ 0.008=\frac{8}{1000}=\frac{1}{125}$

Multiplying the numerator and denominator by $10$ we get, $ 0.8=\frac{8}{10}$

$0.02 \times 30 = 0.60 = 0.6$

 Given,$ \frac{2}{3}\text{p - }\text{2}\frac{1}{2} = \text{3}\frac{1}{2}$
$\Rightarrow\frac{2}{3}\text{p = }$
$ \text{3}\frac{1}{2} + \text{2}\frac{1}{2}$
$\Rightarrow\frac{2}{3}\text{p = }\frac{7}{2} + \frac{5}{2}$
$\Rightarrow\frac{2}{3}$ $ \text{p} = \frac{12}{2}$
$\Rightarrow  \text{p} = \text{6}\times\frac{3}{2}$
$\Rightarrow\text{p} = {3} \times3 $
$\Rightarrow\text{p} = 9$

$ 0.25 × 0.8 = 0.200 = 0.2$