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Question 11 Mark
Five times a number increased by $7$ is $27.$
Answer
Let the number be $x.$ Then, five times of number be $5x.$
Since, it is increased by $7$ i.e. $5x + 7$ and it gives result $27.$
Hence, the equation formed is $5x + 7 = 27$
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Question 21 Mark
The length of a rectangle is two times its breadth. Its perimeter is $60\ cm.$
Perimeter in terms of $x$ is _______.
Answer
Perimeter of rectangle $= 2 ($Length $+$ Breadth$) = 2 (2x + x)$
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Question 31 Mark
________ is the solution of the equation $3x - 2 = 7.$
Answer
Solve the given equation for $x, 3x - 2 = 7$
$\Rightarrow 3x = 7 + 2 [$transponding $(-2)$ to $RHS]$
$\Rightarrow 3x = 9$
$\Rightarrow\frac{3\text{x}}{3}=\frac{9}{3} [$dividing both sides by $3]$
$\Rightarrow\text{x}=3$
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Question 41 Mark
In natural numbers, $x - 5 = -5$ has ________ solution.
Answer
Solve the given equation for $x, x - 5 = -5 $
$\Rightarrow x = -5 + 5 [$tranposing $(-5)$ to $RHS] $
$\Rightarrow x = 0$ Since, natural numbers do not contain zero, hence the equation has no solution.
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Question 51 Mark
In a test Abha gets twice the marks as that of Palak. Two times Abha's marks and three times Palak's marks make $280.$ The equation formed is ________.
Answer
Two times of Abha’s marks $= 2$
$(2x) = Ax$ and three times the Palak marks $= 3(x) = 3x$
Now, two times Abha’s marks and three times Palak’s marks make $280.$
So, the equation formed is $4x + 3x = 280.$
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Question 61 Mark
In a Mathematics quiz, $30$ prizes consisting of $1st$ and $2nd$ prizes only are to be given. $1st$ and $2nd$ prizes are worth $Rs. 2000$ and $Rs. 1000,$ respectively. If the total prize money is $Rs. 52,000$ then show that: The total value of prizes in terms of $x$ are ________.
Answer
Total value of prizes in terms of $x$ are $2000x + 1000(30 - x).$
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Question 71 Mark
If $3 - x = -4,$ then $x =$ _______.
Answer
Given that, $3 - x = -4$
$\Rightarrow -x = -4 - 3 [$transposing $3$ to $RHS]$
$\Rightarrow -x = -7$
$\Rightarrow x = 7 [$multiplying both sides by $(-1)]$
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Question 81 Mark
Any term of an equation may be transposed from one side of the equation to the other side of the equation by changing the _________ of the term.
Answer
Any term of an equation may be transposed from one side of the equation to the other side of the equation by changing the sign of the term. Solution: Any term of an equation may be transposed from one side of the equation to the other side of the equation by changing the sign of the term.
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Question 91 Mark
In a test Abha gets twice the marks as that of Palak. Two times Abha's marks and three times Palak's marks make $280.$ If Palak gets $x$ marks, Abha gets ________ marks.
Answer
If Palak gets $x$ marks, then Abha gets twice the marks as that of Palak, i.e. $2x,$
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Question 101 Mark
The solution of the equation $x + 15 = 19$ is _________.
Answer
Solve the equation for $x,$
$\Rightarrow x + 15 = 19$
$\Rightarrow x = 19 - 15 [$transposing $15$ to $RHS]$
$x = 4$ Hence, the solution of the given equation is $4.$
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Question 111 Mark
If $4x - 7 = 11,$ then $x = 4.$
Answer
Solve the equation for $x,\Rightarrow4\text{x}-7=11$
$\Rightarrow4\text{x}=11+7 [$transposing $(-7)$ to $RHS]$
$\Rightarrow4\text{x}=18$
$\Rightarrow\frac{4\text{x}}{4}=\frac{18}{4} [$dividing both sides by $4]$
$\text{x}=\frac{9}{2}$
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Question 121 Mark
In a bag there are $5$ and $2$ rupee coins. If they are equal in number and their worth is $Rs. 70,$ then The worth of $x$ coins of $Rs. 5$ each ________.
Answer
Number of coins of $Rs. 5 = x$
So, the worth of $Rs. 5$ of $x$ coins $= Rs. 5 $
$ x = Rs. 5x$
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Question 131 Mark
If $10$ less than a number is $65,$ then the number is _________.
Answer
Let the number be $x.$
Then, the equation will be $x - 10 = 65$
Now, solving the equation for $x,$
$\Rightarrow x 65 + 10 [$transposing $(-10)$ to $RHS]$
$\Rightarrow x = 75$
Hence, the number is $75.$
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Question 141 Mark
In natural numbers, $4x + 5 = -7$ has ________ solution.
Answer
Solve thr equation for $x,$
$4x + 5 = -7$
$\Rightarrow 4x = -7 - 5 [$transposing $5$ to $RHS]$
$\Rightarrow 4x = -12$
$\Rightarrow x = -3 [$dividing both sides by $3]$
Since, the value of $x$ is not natural number, hence the equation has no solution in natural numbers.
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Question 151 Mark
The sum of two numbers is $60$ and their difference is $30.$ The difference of numbers in term of $x$ is________.
Answer
Given, one number $= x[$from $(a)]$
Then, other number $= (60 - x)$
$\therefore$ Difference $= (60 - x) - x = 60 - 2x$
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Question 161 Mark
If $\frac{9}{5}\text{x}=\frac{18}{5},$ then $x =$ ______
Answer
Given that, $\frac{9}{5}\text{x}=\frac{18}{5}$
On dividing both sides by $\frac{9}{5},$ we get
$\Rightarrow\frac{9}{5}\text{x}+\frac{9}{5}=\frac{18}{5}+\frac{9}{5}$
$\Rightarrow\text{x}=\frac{18}{5}\times\frac{5}{9}=2$
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Question 171 Mark
In a Mathematics quiz, $30$ prizes consisting of $1st$ and $2nd$ prizes only are to be given. $1st$ and $2nd$ prizes are worth $Rs. 2000$ and $Rs. 1000,$ respectively. If the total prize money is $Rs. 52,000$ then show that: The solution of the equation is _______.
Answer
From $(c),$
$1000x + 30000 = 52000$
$\Rightarrow 1000x = 52000 - 30000 = 22000$
$\Rightarrow\text{x}=\frac{22000}{1000}=22$
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Question 181 Mark
Sum of two numbers is $81.$ One is twice the other. If smaller number is $x$, the other number is _________.
Answer
We are given that one number is twice the other. If smaller number is $x,$ then the other number is $2x.$
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Question 191 Mark
If $\text{x}-\frac{7}{8}=\frac{7}{8},$ then $x = $________
Answer
Given equation is $\text{x}-\frac{7}{8}=\frac{7}{8}$
$\text{x}=\frac{7}{8}+\frac{7}{8} [$transposing $\Big(-\frac{7}{8}\Big)$ to $RHS]$
$\text{x}=\frac{7+7}{8} [$taking $LCM]$
$\text{x}=\frac{14}{8}=\frac{7}{4}$
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Question 201 Mark
The sum of two numbers is $60$ and their difference is $30.$ The numbers ________are and _________.
Answer
The numbers are $x$ and $(60 - x).$ Now, put the value of $x,$ we get
Frist number $= 15$
Second number $= 60 - 15 = 45$
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Question 211 Mark
If $84$ exceeds another number by $12,$ then the other number is ________.
Answer
$\Rightarrow 84 - x = 12 $
$\Rightarrow -x = 12 - 84 [$transposing $84$ to $RHS] $
$\Rightarrow -x = -72$
$\Rightarrow x = 72 [$multiplynig both sides by $(-1)]$
Hence, the number is $72.$
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Question 221 Mark
If $\frac{1}{6}-\text{x}=\frac{1}{6},$ then $x =$ ________.
Answer
Given that, $\frac{1}{6}-\text{x}=\frac{1}{6}$
$\Rightarrow-\text{x}=\frac{1}{6}-\frac{1}{6} [$transposing $\frac{1}{6}$ to $RHS]$
$\Rightarrow-\text{x}=0$
$\Rightarrow\text{x}=0 [$multiplying both sides by $(-1)]$
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Question 231 Mark
One third of a number added to itself gives $10,$ can be represented as $\frac{\text{x}}{3}+10=\text{x}.$
Answer
Let the number be $x.$ Then, the equation formed is $\frac{\text{x}}{3}+\text{x}=10$
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Question 241 Mark
$x - 1 =$ _______ ; when $2x = 2.$
Answer
Given that, $2\text{x}=2$
$\Rightarrow\frac{2\text{x}}{2}=\frac{2}{2} [$dividing both sides by $2]$
$\Rightarrow\text{x}=1$
$\therefore\text{x}-1=1-1=0$
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Question 251 Mark
Sum of two numbers is $81.$ One is twice the other. The equation formed is _________.
Answer
We are given that sum of two numbers is $81.$
So, the equation will be $x + 2x = 81$
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Question 261 Mark
If $\text{x}-\frac{1}{2}=-\frac{1}{2},$ then $x =$ ______
Answer
Given that, $\text{x}-\frac{1}{2}=-\frac{1}{2}$
$\Rightarrow\text{x}=\frac{1}{2}-\frac{1}{2} [$transposing $\Big(-\frac{1}{2}\Big)$ to $RHS]$
$\Rightarrow\text{x}=0$
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Question 271 Mark
If $z + 3 = 5,$ then $z =$ _______.
Answer
Solve the given equation for $z,$
$z + 3 = 5$
$\Rightarrow z = 5 - 3 [$tranponding $3$ to $RHS]$
$\Rightarrow z = 2$
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Question 281 Mark
Finding the value of a variable in a linear equation that _______ the equation is called a _______ of the equation.
Answer
Finding the value of a variable in a linear equation that satisfies the equation is called a root of the equation.
Solution:
Finding the value of a variable in a linear equation that satisfies the equation is called a root of the equation.
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Question 291 Mark
$x - 0 =$ _______ ; when $3x = 12.$
Answer
Given that, $3x = 12$
$\Rightarrow\frac{3\text{x}}{3}=\frac{12}{3} [$dividing both sides by $3]$
$\text{x}=4$
$\therefore\text{x}-0=4-0=4$
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Question 301 Mark
The length of a rectangle is two times its breadth. Its perimeter is $60\ cm.$ The solution of the equation is ________.
Answer
On driving the equation by $6,$
we get $\frac{6\text{x}}{6}=\frac{60}{6}$
$\Rightarrow\text{x}=10$
Hence, the solution of the equation is $10.$
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Question 311 Mark
Mohan is $3$ years older than Sohan. The sum of their ages is $43$ years.
Answer
Let age of Sohan be $x$ year.
Then, the age of Mohan is $(x + 3)$ year.
$\therefore$ Sum of their ages $= 43$
So, the equation formed is $x + (x + 3) = 43$
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Question 321 Mark
Six times a number is $10$ more than the number.
Answer
Let the number be $x.$
Then, $6$ times of a number $= 6x$
So, the equation formed is $6x = 10 + x$
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Question 331 Mark
________ is the solution of $3x + 10 = 7.$
Answer
Solve the given equation for $x,$
$\Rightarrow 3x + 10 = 7$
$\Rightarrow 3x = 7 - 10 [$transposing $10$ to $RHS]$
$\Rightarrow 3x = -3$
$\Rightarrow\frac{3\text{x}}{3}=\frac{-3}{3} [$dividing both sides by $3]$
$\text{x}=-1$
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Question 341 Mark
If $9$ is the solution of variable $x$ in the equation $\frac{5\text{x}-7}{2}=\text{y,}$ then the value of $y$ is $28.$
Answer
Given that, $x = 9$ Put the value of $x$ in the equation,
we get $\Rightarrow\frac{5(9)-7}{2}=\text{y}$
$\Rightarrow\frac{45-7}{2}=\text{y}$
$\Rightarrow\frac{38}{2}=\text{y}$
$\Rightarrow\text{y}=19$
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Question 351 Mark
If $2x + 3 = 5,$ then value of $3x + 2$ is ________.
Answer
Solve the given equation for $x,$
$2x + 3 = 5$
$\Rightarrow 2x = 5 - 3 [$transposing $3$ to $RHS]$
$\Rightarrow\frac{2\text{x}}{2}=\frac{2}{2} [$dividing both sides by $2]$
$\Rightarrow\text{x}=1$
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Question 361 Mark
$\frac{9}{5}$ is the solution of the equation $4x - 1 = 8.$
Answer
Solve the equation for $x,$
$\Rightarrow 4x - 1 = 8$
$\Rightarrow 4x = 8 + 1 [$transposing $(-1)$ to $RHS]$
$\Rightarrow 4x = 9$
$\text{x}=\frac{9}{4} [$dividing both sides by $4]$
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Question 371 Mark
In a bag there are $5$ and $2$ rupee coins. If they are equal in number and their worth is $Rs. 70,$ then The worth of $x$ coins of $Rs. 2$ each ________.
Answer
Similarly, the worth of $12$ of $x$ coins $= Rs. 2x$
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Question 381 Mark
In a test Abha gets twice the marks as that of Palak. Two times Abha's marks and three times Palak's marks make $280.$ Marks obtained by Abha are ________.
Answer
Marks obtained by abha are $2x,$
i.e. $2 \times 40 = 80.$
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Question 391 Mark
$5$ is the solution of the equation $3x + 2 = 17.$
Answer
Solve the equation for $x, 3x + 2 = 17$
$\Rightarrow3\text{x}=17-2[ $transposing $2$ to $RHS]$
$\Rightarrow\frac{3\text{x}}{3}=\frac{15}{3} [$dividing both sides by $3]$
$\Rightarrow\text{x}=5$
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Question 401 Mark
Subtracting $5$ from $p,$ the result is $2.$
Answer
Subtract $5$ from $p$ i.e. $p - 5$ and its results $2.$
Hence, the equation formed is $p - 5 = 2.$
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Question 411 Mark
If a number is increased by $20,$ it becomes $45.$ Then the number is ________.
Answer
Let the number be $x.$
If it is increased by $20,$ it becomes $(x + 20),$
So, the equation formed is $x + 20 = 45$
$\Rightarrow x = 45 - 20 [$transposing $20$ to $RHS]$
$\Rightarrow x = 25 $
Hence, the number is $25.$
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Question 421 Mark
The sum of two numbers is $60$ and their difference is $30.$ The equation formed is______.
Answer
We are given that difference between two numbers is $30.$
So, the equation formed is $60 - 2x = 30$
$\Rightarrow -2x = 30 - 60 [$transposing $60$ to $RHS]$
$\Rightarrow -2x = -30$
$\Rightarrow 2x = 30 [$multiplying both sides by $(-2)]$
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Question 431 Mark
In a test Abha gets twice the marks as that of Palak. Two times Abha's marks and three times Palak's marks make $280.$ The solution of the equation is ________.
Answer
Solve the equation for $x,$
$\Rightarrow4\text{x}+3\text{x}=280$
$\Rightarrow7\text{x}=280$
$\Rightarrow\frac{7\text{x}}{7}=\frac{280}{7} [$dividing both sides by $7]$
$\text{x}=40$ Hence, the solution of the equation is $40.$
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Question 441 Mark
Sum of two numbers is $81.$ One is twice the other. The numbers are________ and _________.
Answer
The two number are $x = 27$ and $2x = 2 \times 27 = 54.$
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Question 451 Mark
$x - $________ $= 15;$ when $\frac{\text{x}}{2}=6.$
Answer
Given that, $\frac{\text{x}}{2}=6$
$\Rightarrow\text{x}=12$
$\therefore12-(-3)=15$
Hence, $\text{x}-(-3)=15$
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Question 461 Mark
In a Mathematics quiz, $30$ prizes consisting of $1st$ and $2nd$ prizes only are to be given. $1st$ and $2nd$ prizes are worth $Rs. 2000$ and $Rs. 1000,$ respectively. If the total prize money is $Rs. 52,000$ then show that: The equation formed is _______.
Answer
The equation formed is $1000x + 30000 = 52000$ From $(b),$
$2000x + 1000(30 - x) = 52000$
$\Rightarrow 2000x + 30000 - 1000x = 52000$
$\Rightarrow 1000x + 30000 = 52000$
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Question 471 Mark
In a Mathematics quiz, $30$ prizes consisting of $1st$ and $2nd$ prizes only are to be given. $1st$ and $2nd$ prizes are worth $Rs. 2000$ and $Rs. 1000,$ respectively. If the total prize money is $Rs. 52,000$ then show that: The number of $1st$ prizes are and the number of $2nd$ prizes are _______.
Answer
The number of $1st$ prizes are $22$ and the number of $2nd$ prizes are $8.$
From $(b), 2000x + 1000(30 - x) = 52000$
$2x + (30 - x) = 52 [$dividing both sides by $1000]$
$x + 30 = 52$
$\Rightarrow x = 52 - 30 = 22$
$\therefore$ Number of $2nd$ prizes $= 30 - 22 = 8.$
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Question 481 Mark
If $5$ is added to three times a number, it becomes the same as $7$ is subtracted from four times the same number. This fact can be represented as _________.
Answer
Let the number be $x.$
Now, $5$ is added to $3$ times the number $5 + 3x. $
It is same as $7$ is subtracted from $4$ times the number,
i.e. $Ax - 7.$ So, the equation formed is $5 + 3x = 4x - 7.$
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Question 491 Mark
The sum of two numbers is $60$ and their difference is $30.$ If smaller number is $x,$ the other number is ________ .(use sum)
Answer
If the smaller number is $x,$ then the other number is $(60 - x),$
since the sum of both numbers is $60.$
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Question 501 Mark
$\frac{3}{2}$ is the solution of the equation $8x - 5 = 7.$
Answer
Solve the equation for $x,$
$\Rightarrow8\text{x}-5=7$
$\Rightarrow8\text{x}=7+5[ $transposing $(-5)$ to $RHS]$
$\Rightarrow8\text{x}=12$
$\Rightarrow\frac{8\text{x}}{8}=\frac{12}{8} [$dividing both sides by $8]$
$\text{x}=\frac{3}{2}$
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1 Marks Question - MATHS STD 7 Questions - Vidyadip