Question 21 MarkIn $\triangle PQR , \angle P =\angle Q =60^{\circ}$, then $\overline{ PR }$ is the longest side.AnswerfalseView full question & answer→
Question 31 MarkWe can have an acute, an obtuse and a right angle in a triangle.AnswerfalseView full question & answer→
Question 41 MarkIn $\triangle XYZ , \angle Z =90^{\circ}$, then $\angle X +\angle Y =90^{\circ}$.AnswertrueView full question & answer→
Question 51 MarkIn $\triangle PQR , \angle Q =90^{\circ}$, therefore $\overline{ PR }$ is the hypotenuse.AnswertrueView full question & answer→
Question 61 MarkIn $\triangle ABC$, if $AB =3 cm , BC =4 cm$ and $AC =5 cm$. then $\angle C$ is the greatest angle.AnswerfalseView full question & answer→
Question 71 MarkIn $\triangle P Q R$, sides $P Q$ and $P R$ are equal. Therefore, measures of $\angle P$ and $\angle Q$ are equal.AnswerfalseView full question & answer→
Question 81 MarkAll the angles of an isosceles triangle are equal.AnswerfalseView full question & answer→
Question 91 MarkAn acute-angled triangle can be a right-angled triangle.AnswerfalseView full question & answer→
Question 121 MarkIn $\triangle PQR , \angle P =\angle Q =60^{\circ}$, then $\overline{ PR }$ is the longest side.AnswerfalseView full question & answer→
Question 131 MarkWe can have an acute, an obtuse and a right angle in a triangle.AnswerfalseView full question & answer→
Question 141 MarkIn $\triangle XYZ , \angle Z =90^{\circ}$, then $\angle X +\angle Y =90^{\circ}$.AnswertrueView full question & answer→
Question 151 MarkIn $\triangle PQR , \angle Q =90^{\circ}$, therefore $\overline{ PR }$ is the hypotenuse.AnswertrueView full question & answer→
Question 161 MarkIn $\triangle ABC$, if $AB =3 cm , BC =4 cm$ and $AC =5 cm$. then $\angle C$ is the greatest angle.AnswerfalseView full question & answer→
Question 171 MarkIn $\triangle P Q R$, sides $P Q$ and $P R$ are equal. Therefore, measures of $\angle P$ and $\angle Q$ are equal.AnswerfalseView full question & answer→
Question 181 MarkAn acute-angled triangle can be a right-angled triangle.AnswerfalseView full question & answer→