50 questions · timed · auto-graded
The basic unit of distance is metre (m).
The basic unit of time is second (s).
Speed = Distance/Time
Therefore, the basic unit of speed is m/s.
Speed = `"Distance"/"Time"`
In a distance-time graph, the constant speed of a truck will be represented by a straight line.
In a distance-time graph, a straight line parallel to the time axis indicates that the truck is not moving.
A curved line on the distance-time graph indicates that the truck is moving with a speed which is not constant.
During first hour, $\text{Speed}=\frac{60}{1}\text{km/ h}=60\text{km/ hr}$
During second hour, $\text{Speed}=\frac{70}{1}\text{km/ h}=70\text{km/ hr}$
During third hour, $\text{Speed}=\frac{20}{1}\text{km/ h}=20\text{km/ hr}$
So, the car travels different distances in equal time intervals.
This is an example of non - uniform motion.
As we know that speed $=\frac{\text{Distance}}{\text{Time}}$
$=\frac{54\times1000}{90\times60}\begin{bmatrix}1\text{km}=1000\text{m} \\1\text{min}=60\text{s}\ \ \ \ \ \ \ \end{bmatrix}=10\text{m/s}.$
$1$ kilosecond $= 1000$ seconds.
Time taken to complete $20$ oscillations $= 32s$
Time taken to complete $1$ oscillation $ = \frac{32}{20}\text{s} = 1.6\text{s}$
Time period of a pendulum is time taken by it to complete $1$ oscillation.
Time period of pendulum is $1.6$ seconds.
As we know the equation of a straight line is $Y = mX + C$
Let us assume $X$ and $Y$ are two different physical quantity and $C$ is any constant.
and the graph between them is straight line.
According to above equation,
$\text{Y}\propto\text{X}$
Hence, $X$ and $Y$ are Directly proportional.
Distance covered $= 640m$
Time taken $= 2\ min \ 40\ sec$
$= 2 × 60 + 40 = 160s$ (because $1$ minute $= 60$ seconds)
$\therefore\text{Speed}=\frac{\text{Distance}}{\text{Time}}=\frac{640}{160}=4\text{m}/\text{s}$
A person has two hourglasses, one of $30$ seconds and the other of $1$ minute.
$1$ minute $= 60$ seconds
$H.C.F.$ of $30$ seconds and $60$ seconds $=30$ seconds
He can only measure time intervals of $30, 60$, and $90$ seconds.
But he cannot measure the time interval of $50$ seconds.
In order to facilitate the measurement of time, a periodic event is required along with a device to calibrate the measured time.
We know that, in one year, there are $365$ days.
Out of the year $2005, 2006, 2007$ and $2008$, the year $2008$ is a leap year which has $366$ days.
So, total number of days $= 365 + 365 + 365 + 366 = 1461$ days.
An object covering equal distances in equal time interval, i.e.
moving with a uniform speed is said to be in a uniform motion.
An object moving in a circular path with uniform speed is said to be in a uniform circular motion.
Since, in a motion of a pendulum and in a car travelling in an overcrowded zig zag road, the speed of the object is changing and is not uniform, hence they are examples of non - uniform motion.
$1$ century $= 100$ years
A century has $100$ years.
The time interval of $5$ min can be measured by both $A$ and $B$. Since, the time interval of $30$ seconds cannot be measured by clock $A$ and can be measured by clock $B$. Also, the time interval of $4$ min $10$ seconds cannot be measured by clock $A$, but can be measured by clock $B.$
The distance covered by a train would be $240\ km.$
The World's Largest Sundial in Jaipur has been telling time for almost $300$ years.
In $24$ hour clock system, $4.15 p.m.$ will be written as
$12 + 4.15 = 12hrs + 4hrs + 15$ minutes $= 16$ hours $15$ minutes.
An odometer is a device that gives us the distance covered by a car.
Distance covered by the car in the given time is $d = 57336.0 − 57321 = 15.0\ km.$
Time period of vibration is the time taken for $1$ vibration.
Given:
$10$ vibrations are completed in $1sec.$
$1$ vibration will taken only: $\frac{1}{10}=0.1\text{sec}$
The basic unit of distance is metre $(m).$
The basic unit of time is second $(s).$
$\text{Speed}=\frac{\text{Distance}}{\text{Time}}$
Therefore, the basic unit of speed is m/s.
The time is taken by a car is $12$ hours.