MCQ 11 Mark
Find the simple interest on Rs. $1000$ for $2$ years at $8 \%$ per annum.
- A
Rs. $80$
- B
Rs. $40$
- C
Rs. $120$
- ✓
Rs. $160$
AnswerCorrect option: D. Rs. $160$
$\text{S.I} =\frac{1000\times2\times8}{100}=\text{Rs.}160$
View full question & answer→MCQ 21 Mark
The value of an article, which was purchased $2$ years ago, depreciates at $12\ %$ per annum. If its present value is Rs. $9680$, the price at which it was purchased is:
- A
Rs. $10,000$
- ✓
Rs. $12,500$
- C
- D
Rs. $14,575$
AnswerCorrect option: B. Rs. $12,500$
Rs. $12,500$
View full question & answer→MCQ 31 Mark
Tick $(\checkmark)$ the correct answer in the following: A man buys an article for Rs. $150$ and makes overhead expenses which are 10% of the cost price. At what price must he sell it to gain 20%?
- A
Rs. $182$
- B
Rs. $192$
- ✓
Rs. $198$
- D
Rs. $208$
AnswerCorrect option: C. Rs. $198$
$CP =$ Rs. $150$
Total $CP =$ Rs.$ (150 + 10 \%$ of $150)$
$=\text{Rs. }\Big(150+\Big(\frac{10}{100}\times150\Big)\Big)$
$=\text{Rs. }(150+15)$
$=\text{Rs. }165$
$\therefore$ Desired $SP$ $=\Big\{\frac{(100+\text{gain}\%)}{100}\times\text{total CP}\Big\}$
$=\Big\{\frac{(100+20)}{100}\times165\Big\}$
$=\text{Rs. }\Big(\frac{120}{100}\times165\Big)$
$=\text{Rs. }198$
View full question & answer→MCQ 41 Mark
Tick $(\checkmark)$ the correct answer in the following: A number is first increased by $10 \%$ and then reduced by $10 \%$. The number.
- A
- ✓
Decrease by $1 \%$
- C
Increases by $1 \%$
- D
AnswerCorrect option: B. Decrease by $1 \%$
Let $x$ be the number.
A $10 \%$ increase will given a new number, $\frac{100}{100}\text{x}=\frac{11}{10}\text{x}$
The number is then reduced by $10 \%$.
The new number will be $\frac{90}{100}\Big(\frac{11}{10}\text{x}\Big)=\frac{990}{1000}\text{x}=\frac{99}{100}\text{x}$
Difference $=\text{x}-\frac{99}{100}\text{x}=\frac{1}{100}\text{x}$
Percentage of decrease $=\frac{1}{100}\text{x}\times\frac{1}{\text{x}}\times100=1%$
View full question & answer→MCQ 51 Mark
Mithlesh purchased a $T.V.$ for Rs. $10000$ and sold it for Rs. $8000$. Find her loss $ \%$.
- A
$10 \%$
- ✓
$20 \%$
- C
$40 \%$
- D
$60 \%$
AnswerCorrect option: B. $20 \%$
$20 \%$
View full question & answer→MCQ 61 Mark
$(?) \%$ of $320$ is $48$?
- A
$25 \%$
- ✓
$15 \%$
- C
$14 \%$
- D
$9 \%$
AnswerCorrect option: B. $15 \%$
Let the required number be $x$.
Then, we have : $(x \%$ of $320)$ $= 48$
$\Rightarrow\Big(320\times\frac{\text{x}}{100}\Big)=48$
$\Rightarrow\frac{320\text{x}}{100}=48$
$\Rightarrow\text{x}=\Big(48\times\frac{100}{320}\Big)$
$\Rightarrow\text{x}=15\%$
View full question & answer→MCQ 71 Mark
A table marked at Rs. $15000$ is available for Rs. $14400$. Find the discount percent?
- A
$2 \%$
- ✓
$4 \%$
- C
$5 \%$
- D
$7 \%$
AnswerCorrect option: B. $4 \%$
$4 \%$
View full question & answer→MCQ 81 Mark
The ratio of speed of cycle $12\ km$ per hour to the speed of scooter 36km per hour is:
- A
$1 : 2$
- B
$1 : 4$
- ✓
$1 : 3$
- D
AnswerCorrect option: C. $1 : 3$
$\frac{\text{Speed of cycle}}{\text{Speed of scooter}}=\frac{12}{36}=\frac{1}{3}$
View full question & answer→MCQ 91 Mark
The $C.I.$ on a certain sum for $2$ years at $10 \%$ per annum is Rs. $525$. Calculate the $S.I.$ on the same sum for double the time at half the rate percent per annum.
- A
Rs. $400$
- ✓
Rs. $500$
- C
Rs. $600$
- D
Rs. $800$
AnswerCorrect option: B. Rs. $500$
Rs. $500$
View full question & answer→MCQ 101 Mark
Tick $(\checkmark)$ the correct answer in the following: A period of $4$ hours 30min is what percent of a day?
- ✓
$18\frac{3}{4}\%$
- B
$20\%$
- C
$16\frac{2}{3}\%$
- D
$19\%$
AnswerCorrect option: A. $18\frac{3}{4}\%$
Here $4$ hours $30$min $= (240+ 30) = 270$min
A day $= 24$ hours $= (24 \times 60) = 1440$min
$\therefore\Big(\frac{270}{1440}\times100\Big)\%=18\frac{3}{4}\%$
View full question & answer→MCQ 111 Mark
A sum of money at $CI$ amounts to thrice itself in $3$ years. In how many years will it be $9$ times itself?
View full question & answer→MCQ 121 Mark
Meenu purchased a fridge for Rs. $10000$ and sold it for Rs. $8000$ Find her loss.
- A
Rs. $8000$
- B
Rs. $10000$
- ✓
Rs. $2000$
- D
Rs. $12000$
AnswerCorrect option: C. Rs. $2000$
Loss $= C.P. - S.P. = 10000 – 8000$
= Rs. $2000$
View full question & answer→MCQ 131 Mark
Sugandha borrowed Rs. $40,000$ from her friend at $12 \%$ per annum compounded annually. What will be interest that she will pay after $2$ years and $3$ months?
- A
Rs. $11651.28$
- B
Rs. $12432.50$
- C
Rs. $11600$
- ✓
Rs. $11681.28$
AnswerCorrect option: D. Rs. $11681.28$
$P =$ Rs. 4$0,000,R = 12 \%$ $T = 2$ years
We know that,
$\text{A}=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{r}}$
$\Rightarrow \text{A}=40000\Big(1+\frac{12}{100}\Big)^2$
$\Rightarrow \text{A}=40000\Big(\frac{112}{100}\Big)^2$
Therefore, $A$= Rs. $50,176$
This amount will be the principle for remaining $3$ months i.e $\frac{1}{4}$ year
$\Rightarrow\text{SI}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$\Rightarrow\text{SI}=\frac{50176\times12\times1}{100\times4}$
$\Rightarrow\text{SI}=1505.28$
Interest for first $2$ years = Rs. $(50,176 - 40,000)$ = Rs. $10,176$
Therefore, total compound interest = Rs. $(10,176 + 1505.28)$ = Rs. $11681.28$
View full question & answer→MCQ 141 Mark
What is the percentage increase from $6000$ to $8460$?
- A
$67 \%$
- ✓
$41 \%$
- C
$49 \%$
- D
$51 \%$
AnswerCorrect option: B. $41 \%$
We know that percent increase $=\frac{\text{New value - old value}}{\text{old value }}\times100$
Therefore, the percent increase from $6000$ to $8460$ $=\frac{8460-6000}{6000}\times100=41\%$
View full question & answer→MCQ 151 Mark
A bought a tape recorder for Rs. $9,000$ and sold it to $B$. $B$ in turn sold it to $C$ each having a loss of $30 \%$ Which of the following is true:
- A
$A$ and $B$ suffered the same loss.
- ✓
$A$ suffered more loss than $B$.
- C
A suffered less loss than $B$.
- D
AnswerCorrect option: B. $A$ suffered more loss than $B$.
$CP$ of the tape recorder for $A$ = Rs. $9,000$
Then $A$ sold it to $B$ at $30 \%$ loss
Therefore, loss suffered by $\text{A}=\frac{30}{100}\times9000=\text{Rs. }2700$
$CP$ for $B$ = $SP$ for $A$ $= 9000 - 2700$ = Rs. $6,300$
Also, $B$ suffered a loss of $30 \%$ on his $CP$
Therefore, loss suffered by $\text{B}=\frac{30}{100}\times6300=\text{Rs. }1,890$
As we can see that loss suffered earned by $A$ is greater than $B$
View full question & answer→MCQ 161 Mark
The cost of a bicycle at a shop was Rs. $2,525$ the sales tax charged was $5 \%$ what is the bill amount?
- A
Rs. $2753.20$
- ✓
Rs. $2651.25$
- C
Rs. $3021.50$
- D
Rs. $3452$
AnswerCorrect option: B. Rs. $2651.25$
On Rs. $100$, the tax paid = Rs. $5$
On Rs. $2.525$. the tax paid = Rs. $\frac{5}{100}\times2525=\text{Rs. }126.25$
Bill amount = Cost of the bicycle + Sales tax = Rs. $2525$ + Rs. $126.25$ = Rs. $2651.25$
View full question & answer→MCQ 171 Mark
Manoj purchased a fan for Rs. $1000$ and sold it for Rs. $1200$. What is her profit?
- A
Rs. $1000$
- B
Rs. $1200$
- ✓
Rs. $200$
- D
Rs. $800$
AnswerCorrect option: C. Rs. $200$
Rs. $200$
View full question & answer→MCQ 181 Mark
Tick $(\checkmark)$ the correct answer in the following: On selling a chair for Rs. $720$, a man loses $25 \%$. To gain $25 \%$ it must be sold for.
- A
Rs. $900$
- ✓
Rs. $1200$
- C
Rs. $1080$
- D
Rs. $1440$
AnswerCorrect option: B. Rs. $1200$
Loss percentage $= 25 \%$
$\text{CP}=\Big\{\frac{100}{(100-\text{loss}\%)}\times\text{SP}\Big\}$
$=\text{Rs. }=\Big\{\frac{100}{100-25}\times\text{SP}\Big\}$
$=\text{Rs. }=\Big(\frac{100}{85}\times720\Big)$
$=\text{Rs. }960$
$\therefore$ Desired $SP$ $=\Big\{\frac{(100+\text{gain}\%)}{100}\times\text{CP}\Big\}$
$=\text{Rs. }=\Big\{\frac{(100+25)}{100}\times960\Big\}$
$=\text{Rs. }=\Big(\frac{125}{100}\times960\Big)$
$=\text{Rs. }1200$
View full question & answer→MCQ 191 Mark
$25 \%$ of $60$ students of a class likes to play football. How many students does not like to play football?
AnswerNumber of students $= 60$
$25 \%$ of 60 students $=\frac{25}{100}\times60=15$
Number of students who does not play football $= 60 - 15 = 45$
View full question & answer→MCQ 201 Mark
The price of a house was Rs. $34,00,000$ last year. It has increased by $20 \%$ this year. What is the price now?
- A
Rs. $40,40,000$
- ✓
Rs. $40,80,000$
- C
Rs. $30,40,000$
- D
Rs. $30,80,000$
AnswerCorrect option: B. Rs. $40,80,000$
Rs. $40,80,000$
View full question & answer→MCQ 211 Mark
A building worth Rs. $P$ is depreciated by $R \%$ per annum. Which of the following is true?
- ✓
$\text{P}\big[1-\frac{\text{R}}{100}\big]$
- B
$\text{P}\big[1+\frac{\text{R}}{100}\big]$
- C
$\text{P}\big[\big(1+\frac{\text{R}}{100}\big)-1]$
- D
$\text{P}\big[1-\big(1-\frac{\text{R}}{100}\big)]$
AnswerCorrect option: A. $\text{P}\big[1-\frac{\text{R}}{100}\big]$
$\text{P}\big[1-\frac{\text{R}}{100}\big]$
View full question & answer→MCQ 221 Mark
Find selling price $(SP)$ if a profit of $5 \%$ is made on a cycle of Rs. $700$ with Rs. $50$ as overhead charges.
- A
Rs. $600$
- ✓
Rs. $787.50$
- C
Rs. $780$
- D
AnswerCorrect option: B. Rs. $787.50$
Rs. $787.50$
View full question & answer→MCQ 231 Mark
Find the compound interest on Rs. $12600$ for $2$ years at $10 \%$ per annum compounded annually?
- ✓
Rs. $2646$
- B
Rs. $2700$
- C
Rs. $3420$
- D
Rs. $4526$
AnswerCorrect option: A. Rs. $2646$
Rs. $2646$
View full question & answer→MCQ 241 Mark
Tick $(\checkmark)$ the correct answer in the following:$x \%$ of $y$ is $y \%$ of?
- ✓
$x$
- B
$100x$
- C
$\frac{\text{x}}{100}$
- D
$\frac{\text{y}}{100}$
Answer$\Rightarrow\Big(\text{y}\times\frac{\text{x}}{100}\Big)=\Big(\text{z}\times\frac{\text{y}}{100}\Big)$
$\Rightarrow\frac{\text{yx}}{100}=\frac{\text{zy}}{100}$
$\Rightarrow\text{yx}=\text{zy}$
$\Rightarrow\text{z}=\text{x}$
View full question & answer→MCQ 251 Mark
A picnic is being planned in a school. Girls are $60 \%$ of the total number of students and are $300$ in number. Find the ratio of the number of girls to the number of boys in the class.
- ✓
It is $3 : 2$
- B
It is $3 : 1$
- C
It is $2 : 3$
- D
It is $2 : 1$
AnswerCorrect option: A. It is $3 : 2$
It is $3 : 2$
View full question & answer→MCQ 261 Mark
Tick $(\checkmark)$ the correct answer in the following: $0.8 \%$ when erpressed as a decimal, is.
- A
$0.08$
- ✓
$0.008$
- C
$8$
- D
$0.8$
AnswerCorrect option: B. $0.008$
$\frac{0.8}{100}=\frac{8}{1000}=0.008$
View full question & answer→MCQ 271 Mark
The percentage of $1 : 4$ is:
- ✓
$25 \%$
- B
$75 \%$
- C
$100 \%$
- D
$50 \%$
AnswerCorrect option: A. $25 \%$
$1 : 4=\frac{1}{4}$
$\frac{\Big(1\times100\Big)}{\Big(4\times100\Big)}=\frac{1}{4}\times100\%$
$=0.25\times100\%=25\%$
View full question & answer→MCQ 281 Mark
The cost price of an article is $Rs. 500$. If it is sold at a profit of $20 \%$. What is its selling price:
- ✓
$Rs. 600$
- B
$Rs. 700$
- C
$Rs. 400$
- D
$Rs. 520$
AnswerCorrect option: A. $Rs. 600$
$Rs. 600$
View full question & answer→MCQ 291 Mark
Tick $(\checkmark)$ the correct answer in the following: If the compound interest on a sum for $2$ years at $12\frac{1}{2}\%$ per annum is $Rs. 510$, the simple interest on the same sum at the same rate for the same period of time is.
- A
$Rs. 400$
- B
$Rs. 450$
- C
$Rs. 460$
- ✓
$Rs. 480$
AnswerCorrect option: D. $Rs. 480$
$C.I$ on a sum $= Rs. 510$
Rate $(R)$ $12\frac{1}{2}\%=\frac{25}{2}\%\text{ p.a}$
Period $(n) = 2$ years
$\text{C.I} = \text{A} - \text{P}=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}-\text{P}$
$\text{C.I}=\text{P}\Bigg[\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}-1\Bigg]$
$\Rightarrow510=\text{P}\Bigg[\Big(1+\frac{\text{R}}{2\times100}\Big)^2-1\Bigg]$
$\Rightarrow510=\text{P}\Big[\frac{9}{8}\times\frac{9}{8}-1\Big]$
$\Rightarrow510=\text{P}\Big[\frac{81}{64}-1\Big]$
$\Rightarrow510=\text{P}\Big(\frac{17}{64}\Big)=\text{P}=\frac{510\times64}{17}$
$\text{P}=\text{Rs. }1920$
$\therefore\text{S.I}=\frac{\text{PRT}}{100}=\frac{1920\times25\times2}{100\times2}$
$=\text{Rs. }480$
View full question & answer→MCQ 301 Mark
A man bought a number of clips at $3$ for a rupee and an equal number at $2$ for a rupee At what price per dozen should he sell them to make a profit of $20 \%$?
- A
$Rs\ 4$
- B
$Rs\ 5$
- ✓
$Rs\ 6$
- D
$Rs\ 7$
AnswerCorrect option: C. $Rs\ 6$
Let he bought $1$ dozen clips of each kind.
$C.P$ of $2$ dozen = $\frac{1}{3}\times12 + \frac{1}{2}\times12=10{\text{Rs}}$
$S.P$ of $2$ dozen$ = 120 \%$ of $10$ = ${\text{Rs}}\frac{120}{100}\times10=12{\text{Rs}}$
Hence $S.P$ per dozen $= 6$ $Rs$.
View full question & answer→MCQ 311 Mark
The $CI$ on a certain sum at $5 \%$ for $2$ years is $Rs. 328$. The SI for that sum at the same rate and for the same period will be:
- ✓
$Rs. 320$
- B
$Rs. 322$
- C
$Rs. 325$
- D
$Rs. 326$
AnswerCorrect option: A. $Rs. 320$
$Rs. 320$
View full question & answer→MCQ 321 Mark
The marked price of a refrigerator was $Rs. 7520$. It was sold for R$s. 4888$. What is the discount percentage?
- A
$28 \%$
- B
$40 \%$
- C
$38 \%$
- ✓
$35 \%$
AnswerCorrect option: D. $35 \%$
The market price of the refrigerator $= Rs. 7520$
The selling price $= Rs. 4888$
Therefore, discount $= 7520 - 4888 = Rs. 2632$
$\Rightarrow\text{Discount%}=\frac{\text{Discount}}{\text{Marked price}}\times100$
$\Rightarrow\text{Discount%}=\frac{2632}{7520}\times100=35\%$
View full question & answer→MCQ 331 Mark
The ratio of $50$ paise to $Rs. 1$ is:
- ✓
$1 : 2$
- B
$2 : 1$
- C
$1 : 1$
- D
$1 : 5$
AnswerCorrect option: A. $1 : 2$
$Rs. 1 = 100$ paise
$50$ paise : $100$ paise or $50 : 100$ or $1 : 2$
View full question & answer→MCQ 341 Mark
Tick $(\checkmark)$ the correct answer in the following: Rajan buys a toy for $Rs. 75$ and sells it for $Rs. 100$. His gain percent is:
- A
$25\%$
- B
$20\%$
- ✓
$33\frac{1}{3}\%$
- D
$37\frac{1}{2}\%$
AnswerCorrect option: C. $33\frac{1}{3}\%$
$SP = Rs. 100$
Gain $= Rs. (100 - 75) = Rs. 25$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{25}{75}\times100\Big)\%$
$=33\frac{1}{3}\%$
View full question & answer→MCQ 351 Mark
The population of a city was $20,000$ in the year $1997$. It increased at the rate of $5 \%$ $p.a$. Find the population at the end of the year $2000$.
- A
$25153$
- B
$24153$
- ✓
$23153$
- D
AnswerCorrect option: C. $23153$
$23153$
View full question & answer→MCQ 361 Mark
What sum lent out at $Cl$ will amount to $Rs. 968$ in $2$ years at $10 \%$ p.a. interest?
- ✓
$Rs. 800$
- B
$Rs. 1000$
- C
$Rs. 1200$
- D
AnswerCorrect option: A. $Rs. 800$
$Rs. 800$
View full question & answer→MCQ 371 Mark
Out of $40$ students in a class, $25 \%$ passed. How many students passed?
Answer$\because$ Out of $100$ passed $= 25$
$\therefore$ Out of $40$ passed $=\frac{25}{100}\times40=10$
or
$25%$ of $40%$ $=\frac{25}{100}\times40=10$
View full question & answer→MCQ 381 Mark
Out of $100$ students of a class, $30 \%$ like to watch $T.V.$ How many students like to watch $T.V.$?
AnswerNumber of student who like to watch $T.V = 30 \%$ of $100 \%$ $=\frac{30}{100}\times100=30$
View full question & answer→MCQ 391 Mark
The Ratio of $10\ m$ to $1\ Km$ is Equal To:
- A
$\frac{1}{1000}$
- B
$\frac{1}{10}$
- ✓
$\frac{1}{100}$
- D
$1000$
AnswerCorrect option: C. $\frac{1}{100}$
$\frac{10\text{m}}{1\text{km}}=\frac{10\text{m}}{1000\text{m}}=\frac{1}{100}$
View full question & answer→MCQ 401 Mark
To gain $44 \%$ after allowing a discount of $20 \%$, the shopkeeper must mark the price of the article which costs him $Rs 450$ as.
- A
$Rs. 710$
- B
$Rs. 800$
- ✓
$Rs. 810$
- D
$Rs. 825$
AnswerCorrect option: C. $Rs. 810$
Given that $CP = Rs. 450$
$44 \%$ of $Rs. 450$. $=\frac{44}{100}\times450$
$= Rs. 198$
Therefore, the, shopkeeper should sell the product at $Rs. 648 (19 + 450)$ to earn a profit of $44 \%$ we can say that $Rs. 648$ is the $SP$ of the product after offering $20 \%$ discount or $Rs. 648$ is the $80 \%$ of the marked price $(MP)$ hence, $80 \%$ of $4$ or,
$\frac{80}{100}\times\text{x} = 648$
$\Rightarrow\text{x}=\frac{648\times100}{80}$
Therefore, $MP = Rs. 810$.
View full question & answer→MCQ 411 Mark
If vishakha has spent $20 \%$ of her pocket money and saved $Rs. 500$ what is her pocket money?
- A
$Rs. 600$
- B
$Rs. 550$
- ✓
$Rs. 625$
- D
$Rs. 650$
AnswerCorrect option: C. $Rs. 625$
Let Vishakha's pocket money$= Rs. X$
According to the question,
$\frac{20}{100}\text{x}+500=\text{x}$
$\Rightarrow20\text{x}+50000=100\text{x}$
$\Rightarrow80\text{x}=50000$
$\Rightarrow\text{x}=625$
View full question & answer→MCQ 421 Mark
A person got a $10 \%$ increase in his salary. If his salary was $Rs. 50000$, then the new salary is:
- A
$Rs. 60000$
- ✓
$Rs. 55000$
- C
$Rs. 45000$
- D
$Rs. 65000$
AnswerCorrect option: B. $Rs. 55000$
Previous salary $= Rs. 50000$
$10 \%$ of $Rs. 50000$ $=\Big(\frac{10}{100}\Big)\times50000=\text{Rs. }5000$
New salary $= Rs. 50000 + Rs. 5000$
$= Rs. 55000/-$
View full question & answer→MCQ 431 Mark
The $CI$ on a certain sum for $2$ years at 10% per annum is $Rs. 525$. The $81$ on the same sum for double the time at half the rate percent per annum is:
- ✓
$Rs. 500$
- B
$Rs. 400$
- C
$Rs. 600$
- D
$Rs. 800$
AnswerCorrect option: A. $Rs. 500$
$Rs. 500$
View full question & answer→MCQ 441 Mark
The ratio of $1m$ and $100\ cm$ is:
- A
$1 : 10$
- ✓
$1 : 1$
- C
$10 : 1$
- D
$1 : 100$
AnswerCorrect option: B. $1 : 1$
One meter is equal to hundred centimeters
$1m = 100\ cm$
Thus, their ratio will be:
$\Rightarrow 1m : 100\ cm$
$\Rightarrow 100\ cm : 100\ cm$
$\Rightarrow 1 : 1$
View full question & answer→MCQ 451 Mark
In a mixture the amount of zinc is $45 \%$. Find the amount of zinc in $400\ g$ mixture.
- A
$60\ g$
- B
$120\ g$
- ✓
$180\ g$
- D
$200\ g$
AnswerCorrect option: C. $180\ g$
Amount of zinc $=400\times\frac{45}{100}=180\text{kg}$
View full question & answer→MCQ 461 Mark
In what time will a sum of $Rs. 800$ at $5 \%$ $p.a. C.I.$ amount to $Rs. 882$?
- A
$1$ year
- B
$5$ years
- C
$4$ years
- ✓
$2$ years
AnswerCorrect option: D. $2$ years
$2$ years
View full question & answer→MCQ 471 Mark
The quantity of protein in a particular variety of pulse is $25 \%$. Find the amount of protein in $4\ kg$ of pulse.
- ✓
$1\ kg$
- B
$2\ kg$
- C
$3\ kg$
- D
$4\ kg$
AnswerCorrect option: A. $1\ kg$
Amount of protein $=4\times\frac{25}{100}=1\text{kg}$
View full question & answer→MCQ 481 Mark
On which of the following percent profit or profit loss is calculated?
AnswerCorrect option: B. $C.p.$
Profit percentage formula:
The profit percent can be calculated as:
$\text{Profit%} = 100 \times \frac{\text{Profit}}{\text{Cost Price}}$
Percentage Loss:
The loss percent can be calculated as;
$\text{Loss%} = 100 \times \frac{\text{Loss}}{\text{Cost Price}}$
View full question & answer→MCQ 491 Mark
Tick $(\checkmark)$ the correct answer in the following:
A number exceeds $20 \%$ of itself by $40$. The number is.
AnswerLet the number be $x$.
$\therefore\text{x}-\frac{20\text{x}}{100}=40$
$\Rightarrow\frac{100\text{x}-20\text{x}}{100}=40$
$\Rightarrow80\text{x}=4000$
$\Rightarrow\text{x}=50$
View full question & answer→MCQ 501 Mark
Tick $(\checkmark)$ the correct answer in the following:$20 \%$ of $Rs. 800 = ?$
- ✓
$Rs. 160$
- B
$Rs. 16$
- C
$Rs. 1600$
- D
AnswerCorrect option: A. $Rs. 160$
$\frac{20}{100}\times800=\text{Rs. }160$
View full question & answer→