MCQ 1011 Mark
Mithlesh purchased a $T.V.$ for Rs. $10000$ and sold it for Rs. $8000$. Find her loss $\%$.
- A
$10 \%$
- ✓
$20 \%$
- C
$40 \%$
- D
$60 \%$
AnswerCorrect option: B. $20 \%$
Loss $= 10000 - 8000 = 2000$
$\therefore\text{Loss}\%=\frac{200}{1000}\times100\%=20\%$
View full question & answer→MCQ 1021 Mark
Ashima took a loan of Rs. $1,00,000$ at $12 \% p.a.$ compounded halfyearly. She paid Rs. $1,12,360$. If $(1.06)2$ is equal to $1.1236$, then the period for which she took the loan is:
- A
$2$ years
- ✓
$1$ year
- C
$6$ months
- D
$1\frac{1}{2}$ Years
AnswerCorrect option: B. $1$ year
Given, principal $(P) =$ Rs.$100000$
Rate of interest $(R \%) = 12 \%$ per annum compounded half-yearly
Let m be the time period, $v$ Amount paid = Rs.$112360$
We know that,
Amount, when interest is compound half-yearly
i.e., $\text{A}=\text{P}\Big(1+\frac{\text{R}}{200}\Big)^\text{2n},$ where n = time period
$112360=100000\Big(1+\frac{\text{12}}{100}\Big)^\text{2m}$
$\Big(\frac{53}{50}\Big)^{2\text{m}}=\frac{112360}{100000}$
$\Big(\frac{53}{50}\Big)^{2\text{n}}=\frac{2809}{2500}$
$\Big(\frac{53}{50}\Big)^{2\text{}}=\Big(\frac{53}{50}\Big)^{2\text{n}}$
On comparing both sides, we get
$2n = 2$
$n = 1$
So, the time period is $1$ yr.
Hence, option $(b)$ is correct.
View full question & answer→MCQ 1031 Mark
The $CI$ on a certain sum for $2$ years is Rs. $41$ and $SI$ is Rs. $40$. Then the rate percent per annum is:
- ✓
$5 \%$
- B
$4 \%$
- C
$8 \%$
- D
$6 \%$
AnswerCorrect option: A. $5 \%$
$5 \%$
View full question & answer→MCQ 1041 Mark
The present population of a town is $25,000$. It grows at $4 \%, 5 \%$ and $8 \%$ during first year, second year and third year respectively, the population after $3$ years is:
- A
$24,576$
- B
$28,696$
- ✓
$29,484$
- D
$30,184$
AnswerCorrect option: C. $29,484$
$29,484$
View full question & answer→MCQ 1051 Mark
Radhika bought a car for Rs. $2,50,000$. Next year its price decreased by $10 \%$ and further next year it decreased by $12 \%$. In the two years overall decrease per cent in the price of the car is:
- A
$3.2 \%$
- B
$22 \%$
- ✓
$20.8 \%$
- D
$8 \%$
AnswerCorrect option: C. $20.8 \%$
Radhika bought a car for Rs. $250000$.
Cost price of a car = Rs.$250000$
Its price decreased next year for $10 \%$
So, price became$=250000-\frac{10}{100}\times250000$
$= 250000 − 25000 =$ Rs. $225000$
Further next year, its price decreased by $12 \%$, then price will be
View full question & answer→MCQ 1061 Mark
A shopkeeper prefers to sell his goods at the cost price but uses a weight of $800 \gm$ instead of $1\ kg$ weight. He earns of profit of:
- A
$2 \%$
- B
$8 \%$
- C
$20 \%$
- ✓
$25 \%$
AnswerCorrect option: D. $25 \%$
Let $CP$ of $1$gm = Re$1$
Given : he sells $800\ gm$ instead of $1000\ gm(1\ kg)$
So, $CP$ of $800\ gm$ = $800$ Rs.
$SP$ of $800\ gm$ $= CP$ of $1000\ gm = 1000$ Rs.
Profit $= 1000 − 800 =$ Rs.$200$
Profit $\%=\frac{200}{800}\times100=25$
View full question & answer→MCQ 1071 Mark
The selling price of an article is $\frac{6}{5}$ of the cost price. The gain percent is:
- A
$15 \%$
- ✓
$20 \%$
- C
$25 \%$
- D
$30 \%$
AnswerCorrect option: B. $20 \%$
Let $x$ be the $CP$ of the article.
Then, $SP$ of the article $=\frac{6}{5}\text{x}$
Now, $\text{gain}=(\text{SP}-\text{CP})$
$=\Big(\frac{6}{5}\text{x}-\text{x}\Big)$
$=\frac{\text{x}}{5}$
$\therefore\text{Gain percentage}=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{\frac{\text{x}}{5}}{\text{x}}\times100\Big)\%$
$=\Big(\frac{\text{x}}{5}\times\frac{1}{\text{x}}\Big)\times100\Big)\%$
$=20\%$
View full question & answer→MCQ 1081 Mark
The difference in $SI$ and $CI$ on a certain sum of money in $2$ years at $15 \%$ $p.a.$ is Rs. $144$. The sum is:
- A
Rs. $6300$
- B
Rs. $6200$
- ✓
Rs. $6400$
- D
Rs. $6000$
AnswerCorrect option: C. Rs. $6400$
Rs. $6400$
View full question & answer→MCQ 1091 Mark
The percentage of $2 : 5$.
- A
$50 \%$
- ✓
$40 \%$
- C
$20 \%$
- D
$60 \%$
AnswerCorrect option: B. $40 \%$
$2 : 5=\frac{2}{5}=\frac{2}{5}\times100\%=0.4\times100\%=40\%$
View full question & answer→MCQ 1101 Mark
Tick $(\checkmark)$ the correct answer in the following: If the simple interest on a sum of money at $5 \%$ per annum for $3$ years is Rs. $1200$ then the compound interest on the same sum for the same period at the same rate will be.
- A
Rs. $1225$
- B
Rs. $1236$
- C
Rs. $1248$
- ✓
Rs. $1261$
AnswerCorrect option: D. Rs. $1261$
$S.I =$ Rs. $60000$
Rate $(R) = 5 \%$
Period $(T) = 3$ years
$\therefore$ Principal $=\frac{\text{S.I}\times100}{\text{R}\times\text{T}}=\frac{1200\times100}{5\times3}$
$=\text{Rs. }8000$
$\therefore$ Amount on $C.I$ $=8000\Big(1+\frac{5}{100}\Big)^3$
$=\text{Rs. }8000\times\frac{21}{20}\times\frac{21}{20}\times\frac{21}{20}$
$=\text{Rs. }9261$
$\therefore$ $C.I = A - P $= Rs. $9261 - 8000$
= Rs. $1261$
View full question & answer→MCQ 1111 Mark
Out of $25$ students in class, $60 \%$ are girls. How many are boys'?
AnswerSince $60 \%$ of the students are girls. Therefore, $40 \%$ are boys.
So, the number of boys $=\frac{40}{100}\times25=10$
View full question & answer→MCQ 1121 Mark
A $TV$ set was bought for Rs. $26,250$ including $5 \%$ $VAT$. The original price of the $TV$ set is:
- A
Rs. $27,562.50$
- B
Rs. $25,000$
- ✓
Rs. $24,937.50$
- D
Rs. $26,245$
AnswerCorrect option: C. Rs. $24,937.50$
Cost price of $TV$ set = Rs. $26250$.
$VAT$ including $= 5 \%$
Original price = Cost price of article including $VAT$$=26250\times\frac{5}{100}\times26250$
$=26250-\frac{26250}{20}=26250-1312.5$
So, original price of the $TV$ set = Rs. $24937.50$
Hence, option $(c)$ is correct.
View full question & answer→MCQ 1131 Mark
On a sum of money the $SI$ for two years is Rs. $660$, while $CI$ is Rs. $696.30$, the rate of interest being the same in both the cases. The rate of interest is:
- A
$12 \%$
- B
$10 \%$
- C
$15 \%$
- ✓
$11 \%$
AnswerCorrect option: D. $11 \%$
$11 \%$
View full question & answer→MCQ 1141 Mark
The ratio of $10\ m$ to $10\ km$ is:
- ✓
$\frac{1}{1000}$
- B
$\frac{1}{100}$
- C
$1000$
- D
$\frac{1}{10}$
AnswerCorrect option: A. $\frac{1}{1000}$
$\frac{10\text{m}}{10\text{km}}=\frac{10\text{m}}{10000\text{m}}=\frac{1}{1000}$
View full question & answer→MCQ 1151 Mark
If the simple interest on a sum of money at $10 \%$ per annum for $3$ years is Rs. $1500$, then the compound interest on the same sum at the same rate for the same period is:
- ✓
Rs. $1655$
- B
Rs. $1155$
- C
Rs. $1555$
- D
Rs. $1855$
AnswerCorrect option: A. Rs. $1655$
Here, $\text{SI}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$\Rightarrow\text{Rs. }1500=\frac{\text{P}\times10\times3}{100}$
$\Rightarrow\text{P}=\frac{1500\times100}{10\times3}=\text{Rs. }5000$
Now, $\text{A}=\text{P}\times\Big(1+\frac{\text{R}}{100}\Big)^\text{n}$
$=\text{Rs. }5000\times\Big(1+\frac{10}{100}\Big)^3$
$=\text{Rs. }5000\times\Big(\frac{110}{100}\Big)^3$
$=\text{Rs. }5000\times\Big(\frac{11}{10}\Big)\times\Big(\frac{11}{10}\Big)\times\Big(\frac{11}{10}\Big)$
$=\text{Rs. }(5\times11\times11\times11)$
$=\text{Rs. }6655$
$\therefore$ $CI = A - P =$ Rs. $(6655 - 5000)$ = Rs. $1655$
View full question & answer→MCQ 1161 Mark
Find the ratio of speed of a car $50\ km$ per hour to the speed of scooter $40\ km$ per hour.
- A
It is $4 : 5$
- B
It is $4 : 1$
- ✓
It is $5 : 4$
- D
It is $1 : 5$
AnswerCorrect option: C. It is $5 : 4$
It is $5 : 4$
View full question & answer→MCQ 1171 Mark
The fraction $\frac{2}{3}$ converted to percentage is:
- A
$20 \%$
- B
$30 \%$
- ✓
$40 \%$
- D
$50 \%$
AnswerCorrect option: C. $40 \%$
$\frac{2}{5}=\frac{2}{5}\times100\%=40\%$
View full question & answer→MCQ 1181 Mark
A man got $10 \%$ increase in his salary. If his new salary is $154000$, find his original salary?
- A
Rs. $160000$
- B
Rs. $150000$
- ✓
Rs. $140000$
- D
Rs. $130000$
AnswerCorrect option: C. Rs. $140000$
Rs. $140000$
View full question & answer→MCQ 1191 Mark
Tick $(\checkmark)$ the correct answer in the following: What percent of $10\ kg$ is $250\ g$?
- A
$25 \%$
- B
$5 \%$
- C
$10 \%$
- ✓
$2.5 \%$
AnswerCorrect option: D. $2.5 \%$
Hence $10\ kg = 10.000\ g$
Required percentage $=\Big(\frac{250}{10000}\times100\Big)\%=2.5\%$
View full question & answer→MCQ 1201 Mark
Tick $(\checkmark)$ the correct answer in the following: A number decreased by $27\frac{1}{2}\%$ gives $87$. The number is.
AnswerLet the number be $x$.
$\therefore \text{x}-\Big(27\frac{1}{2}\Big)\times\frac{1}{100}\times\text{x}=87$
$\Rightarrow\text{x}-\frac{55}{2}\times\frac{\times}{100}=87$
$\Rightarrow\frac{200\text{x}-55\text{x}}{100}=87$
$\Rightarrow145\text{x}=8700$
$\Rightarrow\text{x}=120$
View full question & answer→MCQ 1211 Mark
If $C.P$ is Rs. $1750$, $S.P$ is Rs. $1925$ then the profit percent is:
- A
$9\frac{1}{10}$
- ✓
$10$
- C
$25$
- D
$110$
Answer$C.P. =$ Rs$1750$
$S.P. =$ Rs$1925$
Profit $= 1925 − 1750 = 175$
Profit $ \%$ = $\%=\frac{\text{Profit}}{\text{Cp.}}\times100$
Profit $ \%$ = $\%=\frac{175}{1750}\times100=10\%$
View full question & answer→MCQ 1221 Mark
A number exceeds $25 \%$ of itself by $60$. The number is:
AnswerLet the required number be $x$. Then,
we have: $(25 \%$ of $x) + 60 = x$
$\Rightarrow\Big(\text{x}\times\frac{25}{100}\Big)+60=\text{x}$
$\Rightarrow\frac{25\text{x}}{100}+60=\text{x}$
$\Rightarrow\Big(\frac{25\text{x}}{100}-\text{x}\Big)=-60$
$\Rightarrow\frac{-75\text{x}}{100}=-60$
$\Rightarrow\text{x}=\Big(60\times\frac{100}{75}\Big)$
$\Rightarrow\text{x}=80$
View full question & answer→MCQ 1231 Mark
Tick $(\checkmark)$ the correct answer in the following:A dealer lists his articles at $20 \%$ above cost price and allows a discount of $10 \%$. His gain percent is:
- A
$10 \%$
- ✓
$8 \%$
- C
$9 \%$
- D
$8\frac{1}{4}\%$
AnswerCorrect option: B. $8 \%$
Let the $CP$ be Rs. $100$
Then, marked price = Rs. $120$
Discount $= 10 \%$ of $MP$
$= (10 \%$ of Rs. $120)$
$=\text{Rs. }\Big(120\times\frac{10}{100}\Big)$
$=$ Rs. $12$
Now, $SP = (MP)$ - (discount)
$=$ Rs $(120 - 12) =$ Rs. $108$
Gain percentage $= (108 - 100) \% = 8 \%$
View full question & answer→MCQ 1241 Mark
In what time will Rs. $1000$ amount to Rs. $1331$ at $10 \%$ $p.a.$ in $Cl$?
- ✓
$3$ years
- B
$1$ year
- C
$4$ years
- D
$2$ years
AnswerCorrect option: A. $3$ years
$3$ years
View full question & answer→MCQ 1251 Mark
Avinash bought an electric iron for Rs. $900$ and sold it at a gain of $10 \%$. He sold another electric iron at $5 \%$ loss which was bought Rs. $1200$. On the transaction he has a:
- A
Profit of Rs. $75$
- B
Loss of Rs. $75$
- ✓
Profit of Rs. $30$
- D
Loss of Rs. $30$
AnswerCorrect option: C. Profit of Rs. $30$
Avinash bought an electric iron = Rs. $900$
He sold it, at $10 \%$ profit.
So, selling price of the electric iron$=\frac{10}{100}\times900+900=90+900=\text{Rs.}990$
He also sold another electric iron at $5 \%$ loss.
Cost price of another electric iron = Rs.$1200$
So, selling price of the electric iron$=1200\times\frac{5}{100}\times1200$
$=1200-60=\text{Rs.}1140$
Total amount paid by Avinash for purchasing electric irons = Rs. $900$ + Rs.$1200$ =Rs.$2100$
Total received amount = Rs. $990$ + Rs. $1140$ = Rs. $2130$
So, his profit = Rs.$2130$- Rs.$2100$ = Rs.$30$ in transaction.
Hence, option $(c)$ is correct.
View full question & answer→MCQ 1261 Mark
A sum of money, at compound interest, yields Rs. $200$ and Rs. $220$ at the end of first and second year respectively. The rate $ \%$ is:
View full question & answer→MCQ 1271 Mark
Tick $(\checkmark)$ the correct answer in the following: The compound interest on Rs. $40000$ at $6 \%$ per annum for $6$ months, compounded quarterly, is.
- ✓
Rs. $1209$
- B
Rs. $1902$
- C
Rs. $1200$
- D
Rs. $1306$
AnswerCorrect option: A. Rs. $1209$
Principal $(P)$ = Rs. $40000$
Rate $(R)$ $=6\%\text{p.a}\frac{6}{4}=\frac{3}{2}\%$ quarterly
Period $(n)$ = $6$ months = $2$ quaters
$\therefore$ Amount $(A)$ $=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}$
$=\text{Rs. }40000\Big(1+\frac{3}{2\times100}\Big)^2$
$=\text{Rs. }40000\times\frac{230}{200}\times\frac{203}{200}$
$=\text{Rs. }41209$
$\therefore$ $C.I = A - P =$ Rs. $41209 - 40000$
$=$ Rs. $1209$
View full question & answer→MCQ 1281 Mark
Tick $(\checkmark)$ the correct answer in the following:
The price of watch including $10 \%$ $VAT$ is Rs $825$. What is its basic price?
- A
Rs. $742.52$
- B
Rs. $775$
- ✓
Rs. $750$
- D
Rs. $907.50$
AnswerCorrect option: C. Rs. $750$
Let the basic price be $x$
$VAT = 10 \%$ of Rs. $x$
$=\text{Rs. }\Big(\text{x}\times\frac{10}{100}\Big)$
$=\text{Rs. }\frac{11\text{x}}{10}$
Price including $VAT$ $=\text{Rs. }\Big(\text{x}+\frac{\text{x}}{100}\Big)$
$=\text{Rs. }\frac{11\text{x}}{10}$
Now, $\frac{11\text{x}}{10}=825$
$\Rightarrow\text{x}=\Big(825\times\frac{10}{11}\Big)$
$\Rightarrow\text{x}=750$
$\therefore$ The basic price of the watch is Rs. $750$
View full question & answer→MCQ 1291 Mark
An item marked at Rs. $840$ is sold for Rs. $714$. The discount $ \%$ is:
- A
$10 \%$
- B
$25 \%$
- C
$20 \%$
- ✓
$15 \%$
AnswerCorrect option: D. $15 \%$
Discount = Marked Price - Sale Price
$= 840 - 714$
$=$ Rs. $126$
$\text{Discount % }=\big(\frac{126}{840}\big)\times100\%=15\%$
View full question & answer→MCQ 1301 Mark
Latika bought a teapot for Rs $120$ and a set of cups for Rs $400$. She sold teapot at a profit of $5 \%$ and cups at a loss of $5 \%$. The amount received by her is:
- A
Rs $494$
- B
Rs $546$
- ✓
Rs $506$
- D
Rs $534$
AnswerCorrect option: C. Rs $506$
Latika bought a teapot = Rs. $120$ and a set of cups = Rs. $400$
She sold teapot at a prot of $5 \%$,
So, selling price of teapot$=\frac{5}{100}\times120+120$
$=\frac{120}{20}+120$
$= 6 + 120 =$ Rs. $126$
Also, she sold cups at a loss of $5 \%$. So, selling price of cups$=400-\frac{5}{100}\times400$
$= 400 - 20 =$ Rs. $380$
Then, the total amount received by her = Rs. $126 +$ Rs. $380 =$ Rs. $506$
Hence, option $(c)$ is correct.
View full question & answer→MCQ 1311 Mark
Tick $(\checkmark)$ the correct answer in the following:On selling an article at a certain price a man gains $10 \%$. On selling the same article at double the price, gain percent is:
- A
$20 \%$
- B
$100 \%$
- ✓
$120 \%$
- D
$140 \%$
AnswerCorrect option: C. $120 \%$
Let the $SP$ and $CP$ of the article be Rs $x$ and $y,$ respectively.
Gain percentage $= 10 \%$
$\Rightarrow10=\frac{\text{x}-\text{y}}{\text{x}}\times100$
$\Rightarrow\text{y}=\frac{10\text{x}}{11}$
According to the question, we have
$SP =$ Rs. $2x$
$\therefore$ Gain percentage $=\frac{\text{gain}}{\text{CP}}\times100$
$=\frac{2\text{x}-\frac{10\text{x}}{11}}{\frac{10\text{x}}{11}}\times100$
$=\frac{12}{10}\times100$
$=120\%$
View full question & answer→MCQ 1321 Mark
Calculate compound interest on Rs. $10,800$ for $3$ years at $12.5 \%$ per annum compounded annually.
- A
$13,377.34$
- ✓
$4577.34$
- C
$14,377.34$
- D
AnswerCorrect option: B. $4577.34$
$4577.34$
View full question & answer→MCQ 1331 Mark
The price of a motorcycle was Rs. $34,000$ last year. It has increased by $20 \%$ this year. The price of motorcycle now is:
- ✓
Rs. $40,800$
- B
Rs. $38,800$
- C
Rs. $32,000$
- D
Rs. $36,000$
AnswerCorrect option: A. Rs. $40,800$
$20 \%$ of Rs. $34,000$
$=\frac{20}{100}\times34000=\text{Rs. }6800$
New price $=$ Rs. $34,000$ + Rs. $6800$
$=$ Rs. $40,800$
View full question & answer→MCQ 1341 Mark
A number decreased by $30 \%$ gives $84$. The number is:
AnswerLet the required number be $x$
$x - (30 \%$ of $x) = 84$
$\Rightarrow\Big\{\text{x}-\Big(\text{x}\times\frac{30}{100}\Big)\Big\}=84$
$\Rightarrow\Big(\text{x}-\frac{30\text{x}}{100}\Big)=84$
$\Rightarrow\frac{70\text{x}}{100}=84$
$\Rightarrow\text{x}=\Big(84\times\frac{100}{70}\Big)$
$\Rightarrow\text{x}=120$
View full question & answer→MCQ 1351 Mark
The fraction $\frac{1}{8}$converted to percentege is:
- ✓
$12\frac{1}{2}\%$
- B
$25 \%$
- C
$8 \%$
- D
$16 \%$
AnswerCorrect option: A. $12\frac{1}{2}\%$
$\frac{2}{3}=\frac{2}{3}\times100\%=12\frac{1}{2}\%$
View full question & answer→MCQ 1361 Mark
The price of a scooter was Rs. $34,000$ last year. It has increased by $20 \%$ this year. What is the price now?
- A
Rs. $30,800$
- B
Rs. $30,400$
- ✓
Rs. $40,800$
- D
Rs. $40,400$
AnswerCorrect option: C. Rs. $40,800$
Rs. $40,800$
View full question & answer→MCQ 1371 Mark
If $80 \%$ of a is $910$. What is the value of a?
- ✓
$1137.5$
- B
$999$
- C
$1243.32$
- D
$1059.5$
AnswerCorrect option: A. $1137.5$
$\frac{80}{100}\times\text{a}=910$
$\Rightarrow\text{a}=\frac{910\times100}{80}$
$\Rightarrow\text{a}=1137.5$
View full question & answer→MCQ 1381 Mark
Tick $(\checkmark)$ the correct answer in the following: The compound interest on Rs. $5000$ at $8 \%$ per annum for $2$ years, compounded annually, is.
- A
Rs. $5035$
- B
Rs. $5051$
- ✓
Rs. $832$
- D
Rs. $5150$
AnswerCorrect option: C. Rs. $832$
Principal $(P)$ = Rs. $5000$
Rate $(r) = 8 \%$ p.a
Period $(n) = 2$ years
Amount $(A)$ $=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}$
$=\text{Rs. }5000\Big(1+\frac{8}{100}\Big)^2$
$=\text{Rs. }5000\times\frac{27}{25}\times\frac{27}{25}$
$=\text{Rs. }5832$
$\therefore$ $C.I = A - P =$ Rs. $5832 - 5000$
$=$ Rs. $832$
View full question & answer→MCQ 1391 Mark
A man borrowed Rs. $3125$ for $CI$, and it amounted to Rs. $4500$ in $2$ years. The rate of $CI$ per annum is:
- A
$30 \%$
- ✓
$20 \%$
- C
$25 \%$
- D
$15 \%$
AnswerCorrect option: B. $20 \%$
$20 \%$
View full question & answer→MCQ 1401 Mark
Tick $(\checkmark)$ the correct answer in the following:The ratio of cost price and selling price of an article is $20 : 21$. What is the gain percent on it?
- ✓
$5\%$
- B
$5\frac{1}{2}\%$
- C
$6\%$
- D
$6\frac{1}{4}\%$
Answer$CP =$ Rs. $20x$
$SP =$ Rs. $21x$
Gain = Rs. $(21 - 20)$ = Rs. $x$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{\text{x}}{20\text{x}}\times100\Big)\%=50\%$
View full question & answer→MCQ 1411 Mark
India has won $75 \%$ of the cricket match against England. If the total number of matches won by India are $15$. What is the total number of matches played?
AnswerLet the number of matches played = $x$
India bas won $75 \%$ oftbe matches.
$\Rightarrow\frac{15}{\text{x}}\times100=75$
$\Rightarrow\text{x}=\frac{15\times100}{75}$
$\Rightarrow\text{x}=20$
View full question & answer→MCQ 1421 Mark
Apala has $Rs.\ 200$ with her. She spent $80 \%$ amount she had. How much money is left with her?
- A
Rs. $10$
- B
Rs. $20$
- C
Rs. $30$
- ✓
Rs. $40$
AnswerCorrect option: D. Rs. $40$
$\because$ Out of Rs. $100$, money spent = Rs. $80$
$\therefore$ Out of Rs. $200$, money spent $=\frac{80}{100}\times200=\text{Rs. }160$
or
money spent $= 80\ %$ of Rs. $200$
$=200\times\frac{80}{100}\text{ Rs. }60$
$\therefore$ Money left = Rs. $200$ - Rs $160$ = Rs. $40$
View full question & answer→MCQ 1431 Mark
Saroj purchased a fan for Rs. $1000$ and sold it for Rs. $1200$ What is her profit?
- A
Rs. $1000$
- B
Rs. $1200$
- ✓
Rs. $200$
- D
Rs. $800$
AnswerCorrect option: C. Rs. $200$
Gain $= S.P. - C.P. = 1200 - 1000$
$=$ Rs. $200$
View full question & answer→MCQ 1441 Mark
There are $50$ students in a class of which $40$ are boys and the rest are girls. The ratio of the number of boys and number of girls is:
- A
$2 : 3$
- B
$1 : 5$
- ✓
$4 : 1$
- D
$2 : 5$
AnswerCorrect option: C. $4 : 1$
$4 : 1$
View full question & answer→MCQ 1451 Mark
A shopkeeper purchased $200$ bulbs for Rs. $10$ each. However $5$ bulbs were fused and had to be thrown away. The remaining were sold at Rs. $12$ each. Find the gain or loss %.
- A
$15 \%$
- ✓
$17 \%$
- C
$13 \%$
- D
AnswerCorrect option: B. $17 \%$
$17 \%$
View full question & answer→MCQ 1461 Mark
There are $1275$ trees in Chaudhary Farm. Out of these $36 \%$ trees are of fruits. How many trees of fruits are there in Chaudhary Farm?
AnswerRequired number $=\frac{1275\times36}{100}=\text{Rs. }459$
View full question & answer→MCQ 1471 Mark
What per cent of $\frac{2}{9}\text{ is }\frac{1}{45}?$
- A
$2.5 \%$
- B
$5 \%$
- C
$7.5 \%$
- ✓
$10 \%$
AnswerCorrect option: D. $10 \%$
Required percentage $=\Big(\frac{1}{45}\times\frac{9}{2}\times100\Big)\%=10\%$
View full question & answer→MCQ 1481 Mark
An article is at $10 \%$ more than the $CP$. If discount of $10 \%$ is allowed, then which of the following is right?
- A
$1 \%$ gain
- ✓
$1 \%$ loss
- C
- D
$1.1 \%$ loss
AnswerCorrect option: B. $1 \%$ loss
According to question,
Let $CP$ of the article is = Rs. $100$
$MP$ is $10 \%$ high of $CP$ mean = Rs. $110$
Discount always given on Marked Price
$10 \%$ discount of $MP$ means
$= \frac{10}{100} \times 110 = \text{Rs } 11$
$\therefore$ $SP = MP$ - Discount
$SP = 110 - 11 =$ Rs. $99$
$\therefore \text{ Loss%} = \frac{\text{CP - SP}}{\text{CP}} \times 100$
$= \frac{100 -99}{100} \times 100 = \frac{1}{100} \times 100 = 1\%$
View full question & answer→MCQ 1491 Mark
A sum of money, at compound interest, yields Rs. $200$ and Rs. $220$ at the end of first and second years respectively. What is the rate percent?
- A
$20 \%$
- B
$15 \%$
- ✓
$10 \%$
- D
$5 \%$
AnswerCorrect option: C. $10 \%$
$10 \%$
View full question & answer→MCQ 1501 Mark
If an article sold for Rs. $100$ then there is a gain of Rs. $20$, which of the following is the gain percent?
- ✓
$25 \%$
- B
$22 \%$
- C
$20 \%$
- D
$16 \%$
AnswerCorrect option: A. $25 \%$
Selling price = Rs. $100$
Profit = Rs. $20$
Cost price =$SP$ - Profit $= 100 - 20 = 80$
Thus, $\text{Profit%} = \frac{\text{Profit}}{\text{CP}} \times 100 \times \frac{20}{80} \times 100 = 20\%$
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