MCQ 11 Mark
Mark $(\checkmark)$ against the correct answer: If $6\times5$ is exactly divisible by $9,$ then the least value of $x$ is
AnswerWhen a number is divisible by $9,$ the sum of the digits is also divisible by $9.$
$6 + x + 5 = 11 + x$
To be divisible by $9:$
$11 + x = 18$
$⇒ x = 7$
View full question & answer→MCQ 21 Mark
Tick $(\checkmark)$ the correct answer of following. If the $4-$digit number $x27y$ is exactly divisible by $9,$ then the least value of $(x + y)$ is:
AnswerIf a number is divisible by $9$, then the sum of the digits is divisible by $9.$
$x + 2 + 7 + y = (x + y) + 9$
For this to be divisible by $9,$ the least value of $(x + y)$ is $0.$
But for $x + y = 0, x$ and $y$ both will be zero.
Since $x$ is the first digit, it can never be $0.$
$\therefore x + y + 9 = 18$
Or $x + y = 9$
View full question & answer→MCQ 31 Mark
Mark $(\checkmark)$ against the correct answer: If $x48y$ is exactly divisible by $9$ then the least value of $(x + y)$is:
AnswerWhen a number is divisible by $9,$ the sum of digits is also divisible by $9.$
$x + 4 + 8 + y = 12 +(x + y)$
For $12 + (x + y)$ to be divisible by $9:$
$12 + (x + y) = 18$
$⇒ (x + y) = 6$
View full question & answer→MCQ 41 Mark
Tick $(\checkmark)$ the correct answer of following. If $1A2B5$ is exactly divisible by $9,$ then the least value of $(A + B)$ is:
AnswerFor a number to be divisible by $9,$ the sum of the digits must also be divisible by $9.$
$1 + A + 2 + B + 5 = (A + B) + 8$
The number will be divisible by $9$ if $(A + B) =1(A + B) =1.$
View full question & answer→MCQ 51 Mark
Tick $(\checkmark)$ the correct answer of following. If $4xy7$ is exactly divisible by $3,$ then the least value of $(x + y)$ is:
AnswerIf a number is divisible by $3,$ the sum of the digits is also divisible by $3.$
$4 + x + y + 7 = 11 + (x + y)$
For the sum to be divisible by $3:$
$11 + (x + y) = 12$
$⇒ (x + y) = 1$
View full question & answer→MCQ 61 Mark
Tick $(\checkmark)$ the correct answer of following. If $7x8$ is exactly divisible by $9,$ then the least value of $x$ is
AnswerIf a number is exactly divisible by $9,$ the sum of the digits must also be divisible by $9.$
$7 + x + 8 = 15 + x$
$18$ is divisible by $9.$
$\therefore 15 + x = 18$
$⇒ x = 3$
View full question & answer→MCQ 71 Mark
Tick $(\checkmark)$ the correct answer of following. If $64y8$ is exactly divisible by $3,$ then the least value of $y$ is:
AnswerIf a number is divisible by $3,$ then the sum of the digits is also divisible by $3$.
$6 + 4 + y + 8 = 18$
This is divisible by $3$ as $y$ is equal to $0.$
View full question & answer→MCQ 81 Mark
Tick $(\checkmark)$ the correct answer of following. If $37y4$ is exactly divisible by $9,$ then the least value of $y$ is:
AnswerA number is divisible by $9$ if the sum of the digits is divisible by $9.$
$3 + 7 + y + 4 = 14 + y$
For this sum to be divisible by $9:$
$14 + y = 18$
$⇒ y = 4$
View full question & answer→MCQ 91 Mark
Mark $(\checkmark)$ against the correct answer: If $486*7$ is divisible by $9,$ then the least value of $*$ is:
AnswerFor a number to be divisible by $9,$ the sum of its digits must be divisible by $9.$
$4 + 8 + 6 + * + 7 = 25 + *$
Now,
$25 + * = 27($If $* = 2$ and $27$ is divisible by $9)$
View full question & answer→MCQ 101 Mark
Tick $(\checkmark)$ the correct answer of following. If $x4y5z$ is exactly divisible by $9,$ then the least value of $(x + y + z)$ is:
AnswerA number is divisible by $9$ if the sum of the digits is divisible by $9.$
$x + 4 + y + 5 + z = 9 + (x + y + z)$
The lowest value of $(x + y + z)$ is equal to 0 is equal to $0$ for the number $x4y5z$ to be divisible by $9$.
In this case, all $x, y$ and $z$ will be $0.$
But $x$ is the first digit, so it cannot be $0.$
$\therefore x + 4 + y + 5 + z = 18$
$⇒ x + y + z + 9 = 18$
$⇒ x + y + z = 9$
View full question & answer→MCQ 111 Mark
Tick $(\checkmark)$ the correct answer of following. If $5x6$ is exactly divistble by $3,$ then the least value of $x$ is-
AnswerIf a number is exactly divisible by $3,$ the sum of the digits must also be divisible by $3.$
$5 + x + 6 = 11 + x$ must be divisible by $3.$
The smallest value of $x$ is $1.$
$x = 1$
$⇒ x + 11 = 12$ is divisible by $3.$
View full question & answer→MCQ 121 Mark
If the 4 -digit number $x 27 y$ is exactly divisible by 9 , then the least value of $(x+y)$ is
View full question & answer→MCQ 131 Mark
If $1 A 2 B 5$ is exactly divisible by 9 , then the least value of $(A+B)$ is
View full question & answer→MCQ 141 Mark
If $x 4 y 5 z$ is exactly divisible by 9 , then the least value of $(x+y+z)$ is
View full question & answer→MCQ 151 Mark
If $x 7 y 5$ is exactly divisible by 3 , then the least value of $(x+y)$ is
View full question & answer→MCQ 161 Mark
If $4 x y 7$ is exactly divisible by 3 , then the least value of $(x+y)$ is
View full question & answer→MCQ 171 Mark
If $37 y 4$ is exactly divisible by 9 , then the least value of $y$ is
View full question & answer→MCQ 181 Mark
If $7 x 8$ is exactly divisible by 9 , then the least value of $x$ is
View full question & answer→MCQ 191 Mark
If $64 y 8$ is exactly divisible by 3 , then the least value of $y$ is
View full question & answer→MCQ 201 Mark
If $5 x 6$ is exactly divisible by 3 , then the least value of $x$ is
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