Question types

Trigonometric Ratios Of Compound Angles question types

123 questions across 5 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

123
Questions
5
Question groups
5
Question types
Sample Questions

Trigonometric Ratios Of Compound Angles questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

The value of $\frac{\sin5\alpha-\sin\beta}{\cos5\alpha+2\cos4\alpha+\cos3\alpha}$ is:
  • A
    $\cot\frac{\alpha}{2}$
  • B
    $\cot\alpha$
  • $\tan\frac{\alpha}{2}$
  • D
    None of these

Answer: C.

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The value of $\tan\text{x}+\tan\Big(\frac{\pi}{3}+\text{x}\Big)+\tan\Big(\frac{2\pi}{3}+\text{x}\Big)$ is:
  • $3\tan3\text{x}$
  • B
    $\tan3\text{x}$
  • C
    $3\cot3\text{x}$
  • D
    $\cot3\text{x}$

Answer: A.

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If $\tan\text{X}=\frac{\text{a}}{\text{b}},$ then $\text{b}\cos2\text{x}+\text{a}\sin2\text{x}$ is equal to:
  • A
    $\text{a}$
  • $\text{b}$
  • C
    $\frac{\text{a}}{\text{b}}$
  • D
    $\frac{\text{b}}{\text{a}}$

Answer: B.

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The value of $\sin^2\Big(\frac{\pi}{18}\Big)+\sin^2\Big(\frac{\pi}{9}\Big)+\sin^2\Big(\frac{7\pi}{18}\Big)+\sin^2\Big(\frac{4\pi}{9}\Big)$ is:
  • A
    1
  • 2
  • C
    3
  • D
    None of these

Answer: B.

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If $\text{a}\cos2\text{x}+\text{b}\sin2\text{x}=\text{c}$ has $\alpha$ and $\beta$ as its roots, then prove that,
$\tan(\alpha+\beta)=\frac{\text{b}}{\text{a}}$
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Q 173 Marks Question3 Marks
If $\tan\text{x}=\frac{\text{b}}{\text{a}},$ then find the value of $\sqrt{\frac{\text{a+b}}{\text{a}-\text{b}}}+\sqrt{\frac{\text{a}-\text{b}}{\text{a}+\text{b}}}$
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If $\text{a}\cos2\text{x}+\text{b}\sin2\text{x}=\text{c}$ has $\alpha$ and $\beta$ as its roots, then prove that,
$\tan\alpha+\tan\beta=\frac{2\text{b}}{\text{a+c}}$
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If $0\leq\text{x}\leq\pi$ and x lies in the IInd quadrant such that $\sin\text{x}=\frac{1}{4}.$ Find the values of $\cos\frac{\text{x}}{2},\sin\frac{\text{x}}{2}$ and $\tan\frac{\text{x}}{2}$
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