Magnetic scalar potential is defined as$\text{U}(\overrightarrow{\text{r}_2})-\text{U}(\overrightarrow{\text{r}_1})=-\int\limits^{\vec{\text{r}}_2}_{\vec{\text{r}_1}} \vec{\text{B}}.\text{d}\vec{\text{l}}.$
Apply this equation to a closed curve enclosing a long atraicht wire. The RHS of the above equation is then $-{\mu}_\text{o} \text{ i}$ by Ampere's law. We see that $\text{U}(\vec{\text{r}_2})\neq\text{U}(\vec{\text{r}_1})$ even when $\vec{\text{r}_2}=\vec{\text{r}_1}.$Can we have a magnetic acalar potential in this case?
Answer
Yes we can have magnetic potential scalar in this case.
To measure the magnetic moment of a bar magnet, one may use:
A tangent galvanometer.
A deflection galvanometer if the earth's horizontal field is known.
An oscillation magnetometer if the earth's horizontal field is known.
Both deflection and oscillation magnetometer if the earth's horizontal field is not known.
Answer
A deflection galvanometer if the earth's horizontal field is known.
An oscillation magnetometer if the earth's horizontal field is known.
Both deflection and oscillation magnetometers if the earth's horizontal field is not know.
Explanation:
Denial of $(a)$ :
Tangent galvanometer is an instrument used to measure electric current; it cannot be used to the measure magnetic moment of a bar magnet.
Justification of $(b)$ and $(c)$ :
Deflection magnetometer is used to measure $\frac{\text{M}}{\text{B}_\text{H}}$ of a permanent bar magnet.
Similarly, oscillation magnetometer is used to measure $M B _{ H }$ of a bar magnet. So, if earth's horizontal field, $B _{ H }$, is known, then the magnetic moment of a bar magnet, $M$, can be measured.
Justification of $(d)$:
Using deflection and oscillation magnetometers, we can calculate $\text{MBHMBH}$ and $M B_H$, respectively. Therefore, if we multiply the result obtained from both the instruments, then $B_H$ cancels out as $\frac{\text{M}}{\text{B}_\text{H}}\times\text{MB}_\text{H}=\text{M}^2$. Thus, the value of $B_H$ is not required.
Therefore, we can use both deflection and oscillation magnetometers if the earth's horizontal field is not known.