Question types

Differentiation question types

356 questions across 4 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

356
Questions
4
Question groups
5
Question types
Sample Questions

Differentiation questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

$\frac{\text{d}}{\text{dx}}\Big\{\tan^{-1}\Big(\frac{\cos\text{x}}{1+\sin\text{x}}\Big)\Big\}$ equals:
  • A
    $\frac{1}{2}$
  • $-\frac{1}{2}$
  • C
    $1$
  • D
    $-1$

Answer: B.

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Differential coefficient of $\sec(\tan^{-1}\text{x})$ is:
  • A
    $\frac{\text{x}}{1+\text{x}^2}$
  • B
    $\text{x}\sqrt{1+\text{x}^2}$
  • C
    $\frac{\text{x}}{\sqrt{1+\text{x}^2}}$
  • $\frac{\text{x}}{\sqrt{1+\text{x}^2}}$

Answer: D.

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Let $\text{U}=\sin^{-1}\Big(\frac{2\text{x}}{1+\text{x}^2}\Big)$ and $\text{V}=\tan^{-1}\Big(\frac{2\text{x}}{1-\text{x}^2}\Big),$ then $\frac{\text{dU}}{\text{dV}}=$
  • A
    $\frac{1}{2}$
  • B
    $\text{x}$
  • C
    $\frac{1-\text{x}^2}{\text{x}^2-4}$
  • $1$

Answer: D.

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If $\text{f}(\text{x})=\tan^{-1}\sqrt{\frac{1+\sin\text{x}}{1-\sin\text{x}}},0\leq\text{x}\leq\frac{\pi}{2},$ then $\text{f}'\Big(\frac{\pi}{6}\Big)$ is:
  • A
    $-\frac{1}{4}$
  • B
    $-\frac{1}{2}$
  • C
    $\frac{1}{4}$
  • $\frac{1}{2}$

Answer: D.

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The derivative of $\cos^{-1}(2\text{x}^2-1)$ with respect to $\cos^{-1}\text{x}$ is:
  • $2$
  • B
    $\frac{1}{2\sqrt{1+\text{x}^2}}$
  • C
    $\frac{2}{\text{x}}$
  • D
    $1-\text{x}^2$

Answer: A.

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If $\text{y}=\sec^{-1}\Big(\frac{\text{x}+1}{\text{x}-1}\Big)+\sin^{-1}\Big(\frac{\text{x}-1}{\text{x}+1}\Big),$ then write the value of $\frac{\text{dy}}{\text{dx}}.$
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Q 113 Marks Question3 Marks
If $\text{y}=\sqrt{\cos\text{x}+\sqrt{\cos\text{x}+\sqrt{\cos\text{x}+\ .... \text{to }\infty}}},$ prove that $\frac{\text{dy}}{\text{dx}}=\frac{\sin\text{x}}{1-2\text{y}}$
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Differentiate $\sin^{-1}\Big(2\text{ax}\sqrt{1-\text{a}^2\text{x}^2}\Big)$ with respect to $\sqrt{1-\text{a}^2\text{x}^2},$ if $-\frac{1}{\sqrt{2}}<\text{ax}<\frac{1}{\sqrt{2}}$.
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If $\text{y}=\frac{\text{e}^\text{x}-\text{e}^{-\text{x}}}{\text{e}^{\text{x}}+\text{e}^{-\text{x}}},$ prove that $\frac{\text{dy}}{\text{dx}}=1-\text{y}^2$
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