Maths M.C.Q. [1 Marks Each]

$5.5 - 4.17 = 1.33$

We know that $1000ml = 1$ litre.
Therefore, $1\text{ml}=\frac{1}{1000}=0.001\text{ litre}$
$15\text{ml}=\frac{15}{1000}=0.015\text{ litre}$
So, $15$ litre and $15ml$
$= 15$ litre $+ 0.015$ litre
$= 15.015$ litres.

$25.369$
In this, $5$ lies on ones place.
$\therefore$ Place value of $5 = 5 \times 1 = 5$

$\frac{3}{10}$ is equal to $0.3$. Since the denominator is $10$, we have to mark the decimal such that $3$ is in the tenth place.

$\because 6.3 - 2.8 = 3.5$

To find the percent of a given number, we will multiply it with $100$
Let the number in decimal be $x$
When converted to percent, the number becomes $x \times 100 = 0.002$
Which gives $x = 0.00002$

$10\frac{2}{10}\Rightarrow10\frac{2}{10}=\frac{102}{10}=10.2$

$2.1 = 2.100 and 2.005$
$2.100 > 2.055$
$\Rightarrow 2.1 > 2.055$

The sum of $11.006 + 34 + 0.72$ is $45.726$
Now, the number $45.726$ is rounded off as $45.73.$
Again it is rounded to nearest tenths as $45.7.$

Let $x = 1.263263263$ [we multiply it by $1000]$
Here $3$ digits are repeated
$1000x = 1263.263263....$
$x = 1.263263...$
$999x = 1262$
$\Rightarrow\text{x}=\frac{1262}{999}$
The recurring decimal $1.263$ in a fraction form is equal to $\frac{1262}{999}$

Given decimal number is $15.526$
In this, $2$ lies on one-hundredth place.
$\therefore$ Place value of $2= \frac{2}{100} = 0.02$

$\frac{3}{100}+\frac{5}{10000}$
$=0.03+0.0005$
$=0.0305$

$\frac{134}{1000}=0.134$

The whole parts of all the above numbers are equal. Comparing the tenth parts, we see that two of the decimals have a tenth part $0$ and two have a tenth part $3$. Leaving aside the decimals that have a tenth part $0$, we have $2.3$ and $2.33$. Comparing them, we find that $2.33$ is greater than $2.3$, because, in $2.3$, there is no hundredth part, but in $2.33$, the hundredth part is $3.$

$3.\overline{87}-2.\overline{59}= (3+0.\overline{87})-(2+0.\overline{59})$
$=\Big(3+\frac{87}{99}\Big)-\Big(2+\frac{59}{99}\Big)$
$=1+\Big(\frac{87}{99}-\frac{59}{99}\Big)$
$=1+\frac{28}{99}$
$=1.\overline{28}$

We need to find value of $0.0001289 - 0.0000000274 \times 1293 + 0.0000419032$
We have, $0.0001288726 \times 1293.0000419032$
$= 0.166632277$

Decimal means divide the numerator by the denominator.
Here, Numerator $= 4999$ and Denominator
$=1000\Rightarrow\frac{4999}{1000}=4.999$

The conversion formula for celcius to farenheit is $=\Big(\text{C}\times\frac{9}{5}\Big)+32$

$256.36, 256.56, 256.26, 256.46$
As integral part of all the numbers is same $(256),$ we compare them by fractional part, greater the fractional
part, greater is the number.
In ascending order, $256.26, 256.36, 256.46, 256.56$

$\frac{9}{1000}=0.009$

Total expenditure $= Rs.((2 \times 52.98) + (3 \times 12.98) + (2 \times 300.5))$
$= Rs.(105.96 + 38.94 + 600.10) = Rs. 745$
Amount of money left with her $= Rs. (5000 - 745) = Rs. 4255$

The fraction $\frac{7}{100}$ in decimal form is $0.07.$

$\frac{3}{25}=0.12$
$\begin{aligned}
& \text { 25) } 30(0.12 \\
& \frac{-25}{50} \\
& \frac{-50}{0} \\
& \hline
\end{aligned}$

Let ? be $\text{x}8.8=6+\frac{7}{\text{x}}$
$8.8-6=\frac{7}{\text{x}}$
$\frac{7}{\text{x}}=2.8$
$\frac{7}{2.8}=\text{x}$
$\text{x}=\frac{5}{2}$
$\text{x}=2$

Place Value Definition:
It is the value of the digit with reference to its position in the number. For example, $238$ has $2$ hundred, $3$ tens and $8$ ones.
Therefore ans is $90,00,000$

$\because 1.1 - 0.3$
$= 0.8$