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Maths M.C.Q. [1 Marks Each]

Triangles · Uttarakhand Board (UBSE) STD 6 (Uttarakhand - English Medium). 10 questions.

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M.C.Q. [1 Marks Each]

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10 questions · timed · auto-graded

MCQ 11 Mark
With the angles given below, in which case the construction of triangle is possible?
  • A
    $30^\circ , 60^\circ , 70^\circ$
  • ✓
    $50^\circ , 70^\circ , 60^\circ$
  • C
    $40^\circ , 80^\circ , 65^\circ$
  • D
    $72^\circ , 28^\circ , 90^\circ$
Answer
Correct option: B.
$50^\circ , 70^\circ , 60^\circ$
$\therefore$ Sum of three angles of a triangle is $180^\circ .$
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MCQ 21 Mark
In an isosceles $\triangle\text{ABC}$, the bisectors of $\angle\text{A}$ and $\angle\text{C}$ meet at a point $O$. If $\angle\text{A}$ = $40^\circ $, then $\angle\text{BOC}$ = ?
  • ✓
    $110^\circ$
  • B
    $70^\circ$
  • C
    $130^\circ$
  • D
    $150^\circ$
Answer
Correct option: A.
$110^\circ$
In an isosceles $\triangle\text{ABC}$, $\angle\text{B}$ = $\angle\text{C}$ and bisector of $\angle\text{B}$ and $\angle\text{C}$ meet at $O$ and $\angle\text{A} = 40^\circ $

$\therefore\angle\text{B}=\angle\text{C}=\frac{\Big(180^\circ-40^\circ\Big)}{2}$
$=\frac{140^\circ}{2}=70^\circ$
$\therefore\frac{1}{2}\angle\text{B}=\frac{1}{2}\angle\text{C}=\frac{70^\circ}{2}=35^\circ$
Now in $\triangle\text{OBC}$
$\angle\text{BOC}+\angle\text{OBC}+\angle\text{OCB}=180^\circ$
$\angle\text{BOC}+\frac{1}{2}\angle\text{B}+\frac{1}{2}\angle\text{C}=180^\circ$
$\Rightarrow\angle\text{BOC}+35^\circ+35^\circ=180^\circ$
$\Rightarrow\angle\text{BOC}=180^\circ-70^\circ=110^\circ$
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MCQ 31 Mark
How many parts does a triangle have?
  • A
    $2$
  • B
    $3$
  • ✓
    $6$
  • D
    $9$
Answer
Correct option: C.
$6$
$\therefore$ It has three sides and three angles i.e. six.
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MCQ 41 Mark
The side of a triangle are in the ratio $3 : 2 : 5$ and its perimeter is $30\ cm$. The length of the longest side is:
  • A
    $20\ cm$
  • ✓
    $15\ cm$
  • C
    $10\ cm$
  • D
    $12\ cm$
Answer
Correct option: B.
$15\ cm$
Side of a triangle are in the ratio $3:2:5$ and perimeter $= 30 m$
Length of longest side = $\frac{30\times5}{3+2+5}$
= $\frac{30\times5}{10} \ cm = 15\ cm (b)$
Side of a triangle are in the ratio $3:2:5$ and perimeter $= 30 m$
Length of longest side = $\frac{30\times5}{3+2+5 \ cm}$
= $\frac{30\times5}{10}$
$cm = 15\ cm$
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MCQ 51 Mark
Two angles of a triangle measure $30^\circ $ and $25^\circ $ respectively. The measure of the third angle is:
  • A
    $35^\circ $
  • B
    $45^\circ$
  • C
    $65^\circ$
  • ✓
    $125^\circ$
Answer
Correct option: D.
$125^\circ$
Two angles of a triangle are $30^\circ $ and $25^\circ $ But sum of three angles of a triangle $– 180^\circ $
Third angle $= 180^\circ - (30 + 25^\circ )$
$= 180^\circ - 55^\circ = 125^\circ $
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MCQ 61 Mark
Each angle of an equilateral triangle measures:
  • A
    $30^\circ$
  • B
    $45^\circ$
  • ✓
    $60^\circ$
  • D
    $80^\circ$
Answer
Correct option: C.
$60^\circ$
Each angles of an equilateral triangle $= 60^\circ $
As each angle of an equilateral triangle are equal
Each angle = $\frac{180^\circ}{3}$
$= 60^\circ $
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MCQ 71 Mark
In the adjoining figure, the point $P$ lies:
  • A
    In the interior of $\triangle\text{ABC}.$
  • B
    In the exterior of $\triangle\text{ABC}.$
  • ✓
    On $\triangle\text{ABC}.$
  • D
    Outside $\triangle\text{ABC}.$
Answer
Correct option: C.
On $\triangle\text{ABC}.$
In the figure, $P$ lies on $AB$. Its lies on the $\triangle\text{ABC}.$
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MCQ 81 Mark
A triangle having sides of different lengths is called:
  • A
    An isosceles triangle
  • B
    An equilateral triangle
  • ✓
    A scalene triangle
  • D
    A right triangle
Answer
Correct option: C.
A scalene triangle
$\therefore$ A scalene triangle has different sides.
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MCQ 91 Mark
One of the base angles of an isosceles triangle is $70^\circ $ The vertical angle is:
  • A
    $60^\circ$
  • B
    $80^\circ$
  • ✓
    $40^\circ$
  • D
    $35^\circ$
Answer
Correct option: C.
$40^\circ$
$\therefore$ Sum of three angles is $180^\circ $ and sum of two equal angles $= 70^\circ + 70^\circ = 140^\circ $,
then third angle will be $180^\circ - 140^\circ = 40^\circ .$
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MCQ 101 Mark
The two angles of a triangle are complementary. The third angle is:
  • A
    $60^\circ$
  • B
    $45^\circ$
  • C
    $36^\circ$
  • ✓
    $90^\circ$
Answer
Correct option: D.
$90^\circ$
$\therefore$ A triangle has $180^\circ $ and if two angles are complementary i.e. sum of two angles is $90^\circ $, then third angle will be $180^\circ - 90^\circ = 90^\circ .$
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