c
\((c)\)   \(92\,g\) of a compound react with excess of \(CH_3MgI\)  to give \(x \times 22400\, mL\) of \(CH_4\) at \(STP.\)

\(1\, g\) of a compoun react with excess of \(CH_3MgI\)  to give \(\frac{x \times 22400}{92}\)

\(0.092\) of a compoun react with excess of \(CH_3MgI\)  to give \(\frac{x \times 22400}{92} \times 0.092\)

\(\frac{x \times 22400 \times 0.092}{92} = 67\, mL\) of \(CH_4\) at \(STP\)

\(x = \frac{67 \times 92}{22400 \times 0.092} = \frac{67 \times 92 \times 1000}{22400 \times 92} = \frac{670}{224} = 2.99 \approx 3\)

\(x \Rightarrow\) number of active hydrogen in compound. active \(H  \Rightarrow 3\)