${K_a} = 0.1 \times {\left( {\frac{1}{{100}}} \right)^2} = {10^{ - 5}}$
જો તે $10$$\% $ આયનીકરણ થાય તો સાંદ્રતા
${10^{ - 5}} = C \times {\left( {\frac{{10}}{{100}}} \right)^2}\,\,\, \Rightarrow \,\,\,\,{10^{ - 5}} = C \times {10^{ - 2}}\,\,\,\,\,\,\therefore \,\,\,\,C = {10^{ - 3}}\,\,i.e.\,\,0.001\,M$