MCQ
$0.2$ molar solution of formic acid is ionized $3.2\%$. Its ionization constant is
- A$1 \times {10^{ - 12}}$
- ✓$2.1 \times {10^{ - 4}}$
- C$1.25 \times {10^{ - 6}}$
- D$1 \times {10^{ - 14}}$
✓
Answer
Correct option: B.
$2.1 \times {10^{ - 4}}$
(b) ${K_a} = C{\alpha ^2} = 0.2 \times {\left( {\frac{{3.2}}{{100}}} \right)^2} = 2.048 \times {10^{ - 4}}$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Double bond equivalent of cubane is
The quantum numbers $+1/2$ and $-1/2$ for the electron spin represent
→$(i)$ A strong acid has a weak conjugate base
→$(ii) $ An acid is an electron pair acceptorThe above statements $(i) $ and $(ii)$
Given below are two statements:
→Statement $I :$ Rutherford's gold foil experiment cannot explain the line spectrum of hydrogen atom.
Statement $II :$ Bohr'smodel of hydrogen atom contradicts Heisenberg's uncertainty principle.
In the light of the above statements, choose the most appropriate answer from the options given below :
Sodium generally does not shown oxidation state of $+2,$ because of its
→The size of isoelectronic species - $F ^{-}$, Ne and $Na ^{+}$is affected by
→A compound of carbon hydrogen and nitrogen contains three elements in the respective ratio of $9 : 1 : 35$ grams. The Empirical formula for the compound is
→The addition of NaCl to AgCl decreases the solubility of AgCl because:
The chemical equilibrium of a reversible reaction is not influenced by
Assign $A, B, C, D$ from given type of reaction.
$NaI + H_2SO_4 \,(Conc.) \longrightarrow Na_2SO_4 +I_2 \uparrow + SO_2$
→