$0.2\,F$ capacitor is charged to $600\,V$ by a battery. On removing the battery, it is connected with another parallel plate condenser of $1\,F$. The potential decreases to.........$volts$
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(a) By using charge conservation $0.2 \times 600 = (0.2 + 1)\,V$
$==>$ $V = \frac{{0.2 \times 600}}{{1.2}} = 100\,V$
$==>$ $V = \frac{{0.2 \times 600}}{{1.2}} = 100\,V$
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