MCQ
$0.5737373...... = $
- A$\frac{{284}}{{497}}$
- B$\frac{{283}}{{495}}$
- ✓$\frac{{568}}{{990}}$
- D$\frac{{567}}{{990}}$
$= 0.5 + 0.073 + 0.00073$
$= 0.5 +$ $\frac{{73}}{{1000}} + \frac{{73}}{{100000}} + ....$
= $0.5 + 73\left[ {\frac{1}{{1000}} + \frac{1}{{100000}} + .....} \right]$
= $0.5 + 73\left[ {\frac{{1/1000}}{{1 - \frac{1}{{100}}}}} \right]$
= $0.5 + \frac{{73}}{{1000}}.\frac{{100}}{{99}} = \frac{5}{{10}} + \frac{{73}}{{990}}$
= $\frac{{495 + 73}}{{990}} = \frac{{568}}{{990}}$.
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Statement $-1$ :Variance of $2{x_1}\;,2\;{x_2}\;,\;.\;.\;.\;,2{x_n}$ is $4{\sigma ^2}$ .
Statement $-2$: Arithmetic mean $2{x_1}\;,2\;{x_2}\;,\;.\;.\;.\;,2{x_n}$ is $4\bar x$.