$1$- બ્યુટાઇન ની $C{{H}_{3}}\,-\,\,C{{H}_{2}}\,-\,\,C\,\,\equiv \,\,CH\,+\,\,HCl\,\,\to \,\,B\,\,\xrightarrow{HI}\,\,C$ પ્રક્રિયામાં નીપજ $'C'$ શું મળે છે

Question

A${\mkern 1mu} \begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,I \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|
\end{array}} \\
{C{H_3}{\mkern 1mu} - {\mkern 1mu} {\mkern 1mu} C{H_2}{\mkern 1mu} - {\mkern 1mu} {\mkern 1mu} C{H_2}{\mkern 1mu} - {\mkern 1mu} C - HC{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl\,\,}
\end{array}$
B${\mkern 1mu} \begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,I} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}{\mkern 1mu} - {\mkern 1mu} {\mkern 1mu} C{H_2}{\mkern 1mu} - {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} CH - C{H_2}Cl}
\end{array}$
C$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
\,\,\,\,\,I \\
\,\,\,\,\,|
\end{array}} \\
{C{H_3} - C{H_2} - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl}
\end{array}$
D$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_2}I} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$

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Solution

c

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