MCQ
1-Chlorobutane on reaction with alcoholic potash gives:
- A1-butene
- B1-butanol
- C2-butene
- D2-butanol
Explanation:
Alc. KOH is a dehydrohalogenation agent, it reacts with an alkyl halide and alkene forms as a product.
Reaction of process:
$\text{CH}_3\text{CH}_2\text{CH}_2\text{Cl}\xrightarrow{\text{alc.KOH}}\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Here $A$ is nothing but :
Choose the correct statement($s$) about the above process
$(A)$ $OH ^{-}$ions react with $N _2 H _4$ at the anode to form $N _2( g )$ and water, releasing 4 electrons to the anode.
$(B)$ At the cathode, $N _2 H _4$ breaks to $N _2( g )$ and nascent hydrogen released at the electrode reacts with oxygen to form water.
$(C)$ At the cathode, molecular oxygen gets converted to $OH ^{-}$.
$(D)$ Oxides of nitrogen are major by-products of the electrochemical process.