MCQ
$1 + \frac{3}{2} + \frac{5}{{{2^2}}} + \frac{7}{{{2^3}}} + ......\,\infty \,$ is equal to
- A$3$
- B$6$
- C$9$
- ✓$12$
${S_\infty } = \frac{a}{{1 - r}} + \frac{{dr}}{{{{(1 - r)}^2}}}$$ = \frac{1}{{1 - \frac{1}{2}}} + \frac{2}{{{{\left( {1 - \frac{1}{2}} \right)}^2}}}$$ = \frac{2}{{\frac{1}{2}}} + \frac{2}{{\frac{1}{4}}}$
$ = 4 + 8 = 12$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.