MCQ
$1$ mole of a diatomic is heated through isochoric process from $300\,K$ to $500 \,K$. The entropy is :
  • $10.61$
  • B
    $38.26$
  • C
    $20.05$
  • D
    $30$

Answer

Correct option: A.
$10.61$
a
The entropy for a system can be calculated as :

$\Delta S=n C_{ v } \ln \frac{T_{2}}{T_{1}}+n R \ln \frac{V_{2}}{V_{1}} \cdots \cdots( I )$

The volume remains zero for isochoric process.

For diatomic gas;

$C_{ v }=\frac{5 R}{2}$

Substitute all the values in the expression $(I)$.

$\Delta S=1 \times \frac{5 R}{2} \ln \frac{500}{300}$

$=\frac{5}{2} \times 8.314 \times 0.5108$

$=10.61\,J$

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