MCQ
$1$ mole of a diatomic is heated through isochoric process from $300\,K$ to $500 \,K$. The entropy is :
- ✓$10.61$
- B$38.26$
- C$20.05$
- D$30$
$\Delta S=n C_{ v } \ln \frac{T_{2}}{T_{1}}+n R \ln \frac{V_{2}}{V_{1}} \cdots \cdots( I )$
The volume remains zero for isochoric process.
For diatomic gas;
$C_{ v }=\frac{5 R}{2}$
Substitute all the values in the expression $(I)$.
$\Delta S=1 \times \frac{5 R}{2} \ln \frac{500}{300}$
$=\frac{5}{2} \times 8.314 \times 0.5108$
$=10.61\,J$
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