\({MCl}_{3} \cdot 2 {~L} \stackrel{{Ex} . {AgNO}_{3}}{\longrightarrow} 1 {~mole} \text { of } {AgCl}\)
Its means that one \({Cl}^{-}\)ion present in ionization sphere.
\(\therefore \text { formula }=\left[{MCl}_{2} {~L}_{2}\right] {Cl}\)
For octahedral complex coordination no. is \(6\)
\(\therefore {L}\) act as bidentate ligand
$(I)\, [(Ph_3P)_2PdCl_2PdCl_2]$ $(II)\,[NiBrCl(en)]$
$(III)\, Na_4 [Fe(CN)_5 NOS]$ $(IV)\, Cr(CO)_3(NO)_2$
$(I)\,-\,(II)\,-\,,(III)\,-\,(IV)$