Question
${(1 + x)^{2n}}$ के विस्तार में मध्य पद होगा
$ = \frac{{(2n)!}}{{n!\,\,n!}}{x^n} = \frac{{1.3.5....(2n - 1)}}{{n!}}{2^n}{x^n}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$( S 1) P \left( A ^{\prime} \cup B \right)=\frac{5}{6}$ तथा
( $S 2) P \left( A ^{\prime} \cap B ^{\prime}\right)=\frac{1}{18}$ है। तब