${10^{ - 3}}amp$ is flowing through a resistance of $1000\,\Omega $. To measure the correct potential difference, the voltmeter is to be used of which the resistance should be
A$0\,\Omega $
B$500\,\Omega $
C$1000\,\Omega $
D$ > > 1000\,\Omega $
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D$ > > 1000\,\Omega $
d (d)Resistance of voltmeter should be greater than the external circuit resistance. An ideal voltmeter has infinite resistance.
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