$100\ g$ of water is heated from $30^o C$ to $50^o C$. Ignoring the slight expansion of the water, the change in its internal energy is .......$kJ$ (specific heat of water is $4184\ J/kg/K$):
AIEEE 2011, Easy
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$\Delta U = \Delta Q = mc\Delta T = 100 \times {10^{ - 3}} \times 4184\left( {50 - 30} \right)$$ \approx 8.4\,kJ$
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