d
Number of moles \(=\frac{\text { number of molocules }}{\mathrm{NA}}\) \(=\frac{6.02 \times 10^{20}}{6.02 \times 10^{23}}=10^{-3} \mathrm{mol}\)

Molar conc \(=\frac{n \times 1000}{V_{\text {solution }(\mathrm{mL})}}=\frac{10^{-3} \times 1000}{100}\)

Molar conc. \(=0.01 \mathrm{M}\)