$10\,Cells$, each of emf $'E'$ and internal resistance $'r'$, are connected in series to a variable external resistance. Figure shows the variation of terminal potential difference of their combination with the current drawn from the combination.$Emf$ of each cell is ............. $V$
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From similar triangle method

$\frac{6-0}{14-12}=\frac{E-0}{14-0}$

$\frac{6}{2}=\frac{E}{14} \quad \Rightarrow E=42$ $\mathrm{volt}$

$\mathrm{E}_{\mathrm{eq}}=42=10 \mathrm{\,E} \quad \Rightarrow \mathrm{E}=4.2 \mathrm{\,volt}$

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