c
(c) Energy stored in the capacitor \( = \frac{1}{2}C{V^2} \times 100\)
\( = \frac{1}{2} \times 10 \times {10^{^{ - 6}}} \times {(100 \times {10^3})^2} \times 100 = 5 \times {10^6}\,J\)
Electric energy costs \( = 108\,Paise\,per\,kWH\)\( = \frac{{108\,Paise}}{{3.6 \times {{10}^6}\,J}}\)
Total cost of charging \( = \frac{{5 \times {{10}^6} \times 108}}{{3.6 \times {{10}^6}}}\, = 150\,Paise\)