Question
$\frac{1}{3}-\text{2x}=0$

Answer

$\frac{1}{3}-\text{2x}=0$ Subtracting $13$ from both sides,
we get $\frac{1}{3}-2\text{x}-\frac13=0-\frac13$ $-2\text{2x}=-\frac13$
Multiplying both sides by $-1$,
we get $-2\text{x}\times(-1)=-\frac{1}{3}\times(-1)$ $2\text{x}=\frac13$
Dividing both sides by $2$, we get $\frac{2\text{x}}{2}=\frac{\frac13}{2}$ $\text{x}=\frac16$
Verification: Substituting $\text{x}=\frac16$ in
$L.H.S.$, we get $\text{L.H.S.}=\frac13-2\times\frac16=\frac13-\frac13=0,$ and $\text{R.H.S.}=0$
$\text{L.H.S.}=\text{R.H.S.}$
​​​​​​​Hence Verified.

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