Question
Find the missing frequency $(p)$ for the following distribution whose mean is $7.68$
x:
$3$
$5$
$7$
$9$
$11$ $13$
f:
$6$
$8$
$15$
$p$
$8$ $4$

Answer

Calculation of mean:
$x_i$
$f_i$
$x_if_i$
$3$
$6$
$18$
$5$
$8$
$40$
$7$
$15$
$105$
$9$
$p$
$9p$
$11$ $8$ $88$
$13$ $4$ $52$
Total
$\sum\text{f}_\text{i}=41+\text{p}$
$\sum\text{f}_\text{i}\text{x}_\text{i}=303+9\text{p}$
We have,
$\sum\text{f}_\text{i}=41+\text{p},\sum\text{f}_\text{i}\text{x}_\text{i}=303+9\text{p}$ $\therefore\text{Mean}=\frac{\sum\text{f}_\text{i}\text{x}_\text{i}}{\sum\text{f}_\text{i}}$
$\Rightarrow7.68=\frac{303+9\text{p}}{41+\text{p}}$
$\Rightarrow303 + 9\text{p} = 314.88 + 7.68\text{p}$
$\Rightarrow1.32\text{p} = 314.88 - 303$
$\Rightarrow\text{p}=\frac{11.88}{1.32}$
$\Rightarrow\text{p} = 9$

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