MCQ
$\frac{1}{(3+2\sqrt{2})}=\text{?}$
- ✓$(3-2\sqrt{2})$
- B$\frac{({3-2\sqrt{2})}}{13}$
- C$\frac{({3-2\sqrt{2})}}{17}$
- DNone of these.
✓
Answer
Correct option: A.
$(3-2\sqrt{2})$
$\frac{1}{(3+2\sqrt{2})}$
$=\frac{3-2\sqrt{2}}{(3+2\sqrt{2})(3-2\sqrt{2})}$
$=(3-2\sqrt{2})$
$=\frac{3-2\sqrt{2}}{(3+2\sqrt{2})(3-2\sqrt{2})}$
$=(3-2\sqrt{2})$
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