ગ્રામમાં વજન = તુલ્યભાર $×$ $N$ $×$ કદ
$ = 49 \times \frac{1}{7} \times \frac{{150}}{{1000}} = \frac{{21}}{{20}} = 1.05\,g$
$(i)$ $0.10\, {M} \,{Ba}_{3}\left({PO}_{4}\right)_{2}$
$(ii)$ $0.10\, {M}\, {Na}_{2} {SO}_{4}$
$(iii)$ $0.10\, {M}\, {KCl}$
$(iv)$ $0.10 \,{M} \,{Li}_{3} {PO}_{4}$