MCQ
$16$ g of $S_8$ molecules contain:
- A$3.78 \times 10^{22}$ atoms.
- B$3.78 \times 10^{22} \times 8$ atoms.
- C$3.78 \times 10^{22}$ moles.
- ✓$3.78 \times 10^{23}$ molecules.
Molar mass of $S _8=256 g mol ^{-1}$
We know,
$1$ mole of $S _8=$ Molar mass of $S _8=6.022 \times 10^{23}$ molecules.
$256 g$ of $S_8=6.022 \times 10^{23}$ molecules.
Hence, $16$ g of $S _8=\frac{6.022 \times 10^{23 \times} 16}{256}$ molecules
$=3.76 \times 1022$ molecules
$=3.76 \times 10^{22}$ molecules
$=3.78 \times 10^{23}$ molecules (approx)
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