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M.C.Q. [1 M]

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MCQ 11 Mark
The anion of an element has:
  • More electrons than the normal atom.
  • B
    Less electrons than the normal atom.
  • C
    More protons than the normal atom.
  • D
    Same number of electrons as normal atom.
Answer
Correct option: A.
More electrons than the normal atom.
The anion of an element has more electrons than the normal atom because it is formed by gaining electrons.
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MCQ 21 Mark
In hydrogen peroxide $\left( H _2 O _2\right)$, the proportion of hydrogen and oxygen by mass is:
  • A
    $1 : 8$
  • B
    $1 : 16$
  • C
    $8 : 1$
  • $16 : 1$
Answer
Correct option: D.
$16 : 1$
In hydrogen peroxide, the ratio of hydrogen to oxygen is $1 : 16$ by mass.
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MCQ 31 Mark
$1.008$ grams of hydrogen combines with $35.453 g$ of chlorine to form $36.463 g$ of a pure compound (hydrogen chloride). Dalton's explanation for this experimental fact might be:
  • A
    One atom of hydrogen combines with $35.453$ atoms of chlorine in this reaction
  • B
    Hydrogen and chlorine atoms always combine in a $1:35$ ratio.
  • C
    Chlorine accepts hydrogen's electron to form polar covalent hydrogen chloride
  • Hydrogen and chlorine atoms aren't created or destroyed in the process so the reactant mass is the same as the product mass.
Answer
Correct option: D.
Hydrogen and chlorine atoms aren't created or destroyed in the process so the reactant mass is the same as the product mass.

Dalton Atomic theory postulates-
All matter is made up of atoms and atoms are indestructible cannot be created or destroyed so the total mass of reactants remains equal to the total mass of products.

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MCQ 41 Mark
When we mix $\text{BaCl} _2(aq)$ with $Na _2 SO _4(aq)$, which of the following observations is correct?
  • A
    No reaction takes place.
  • B
    colourless solution is obtained.
  • White precipitate is formed.
  • D
    Green precipitate is formed.
Answer
Correct option: C.
White precipitate is formed.
White precipitate is formed.
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MCQ 51 Mark
Which of the following is not a postulate of Dalton's atomic theory
  • A
    Different elements have atoms of different masses.
  • B
    Atoms combine in simple whole number ratios to form compounds.
  • C
    Atoms are not created or destroyed in chemical change.
  • Atoms of a single element can have different masses.
Answer
Correct option: D.
Atoms of a single element can have different masses.
Postulates of Dalton's atomic theory:
All matter consists of indivisible particles called atoms.
Atoms of the same elements are similar in shape and mass but differ from the atoms of other elements.
Atoms cannot be created or destroyed.
Atoms of different elements may combine with each other in fixed, simple, whole-number ratios to form elements and compounds.
The atom is the smallest unit of matter that can take part in a chemical reaction.
'Atoms of a single element can have different masses' is not present in postulates of Dalton's atomic theory.
It is in fact a limitation of Dalton's atomic theory
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MCQ 61 Mark
$' X\ '$ and $' Y\ '$ are two elements which form $X_2 Y_3$ and $X_3 Y_4$. If $0.2$ mol of $X_2 Y_3$ weighs $32$ g and $0.4$ mol of $X_3 Y_4$, weighs $92.8$ g , the atomic weights of $X$ and $Y$ respectively are:
  • A
    $16, 56$
  • B
    $16, 16$
  • $56, 16$
  • D
    $56, 56$
Answer
Correct option: C.
$56, 16$
Molecular weight of $X _2 Y _3=32.0 g / 0.2 mol$
$X _2 Y _3=32.0 g / 0.2 mol=160 g / mol$
Molecular weight of $X_3 Y_4=92.8 g / 0.4 mol$
$X _3 Y _4=92.8 g / 0.4 mol=232 g / mol$
Now suppose the atomic weight of $X = a$ and atomic weight of $Y = b$
Then, $2 a+3 b=160$
And, $3 a+4 b=232$
For equ $(i)$
$A =\frac{(160-3 b)}{2}$
Put value of $(i)$ in $(ii)$
$3 \frac{(160-3 b)}{2}+4 b=232$
After solving,
$a =56$ and $b =16$
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MCQ 71 Mark
The element having atomicity ‘four’ is most likely to be:
  • A
    Argon.
  • B
    Fluorine.
  • Phosphorus.
  • D
    Francium.
Answer
Correct option: C.
Phosphorus.

Phosphorus has an atomicity of $4.$

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MCQ 81 Mark
Avogadro number is the number of atoms present in exactly:
  • A
    $16g$ of oxygen
  • $12g$ of carbon
  • C
    $2g$ of hydrogen
  • D
    None of the above
Answer
Correct option: B.
$12g$ of carbon

Avogadro number is the number of atoms in exactly $12 g$ of carbon $-12$ .
It is equal to $6.022 \times 10^{23}$.

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MCQ 91 Mark
Which of the following contains maximum number of molecules?
  • A
    $19 CO _2$
  • B
    $1 g N _2$
  • $1 g H _2$
  • D
    $1 g CH _4$
Answer
Correct option: C.
$1 g H _2$
$1 g H _2$
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MCQ 101 Mark
$16$ g of $S_8$ molecules contain:
  • A
    $3.78 \times 10^{22}$ atoms.
  • B
    $3.78 \times 10^{22} \times 8$ atoms.
  • C
    $3.78 \times 10^{22}$ moles.
  • $3.78 \times 10^{23}$ molecules.
Answer
Correct option: D.
$3.78 \times 10^{23}$ molecules.

Molar mass of $S _8=256 g mol ^{-1}$
We know,
$1$ mole of $S _8=$ Molar mass of $S _8=6.022 \times 10^{23}$ molecules.
$256 g$ of $S_8=6.022 \times 10^{23}$ molecules.
Hence, $16$ g of $S _8=\frac{6.022 \times 10^{23 \times} 16}{256}$ molecules
$=3.76 \times 1022$ molecules
$=3.76 \times 10^{22}$ molecules
$=3.78 \times 10^{23}$ molecules (approx)

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MCQ 111 Mark
Which of the following symbol of elements is not taken from Latin names:
  • A
    $K$
  • B
    $Na$
  • C
    $Cu$
  • $Zn$
Answer
Correct option: D.
$Zn$

$K, Na, Cu$ is derived from Latin names namely Kalium, Natrium, and Cuprum.
The symbol of Zinc is not taken from Latin names.

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MCQ 121 Mark
Which Indian philosopher was the first one to postulate the idea of matter divisibility around $500\ B.C:$
  • A
    Democritus
  • B
    Leucippus
  • C
    Pakudha Katyayama
  • Maharishi Kanad
Answer
Correct option: D.
Maharishi Kanad
Maharishi Kanad
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MCQ 131 Mark
An element $X\ '$ has valency equal to $3$. What will be its formula with carbonate ion?
  • A
    $X _2 CO _3$
  • B
    $X _2\left( CO _3\right)_2$
  • C
    $XCO _2$
  • $X _2\left( CO _3\right)_3$
Answer
Correct option: D.
$X _2\left( CO _3\right)_3$
Charge on carbonate ion is $-2$ and on oxide is also $-2 .$
So formula of the carbonate will be $X _2\left( CO _3\right)_3$
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MCQ 141 Mark
Which of the following configuration is most likely to form an anion:
  • $2, 6$
  • B
    $2, 8, 1$
  • C
    $2, 1$
  • D
    $2, 2$
Answer
Correct option: A.
$2, 6$

The electronic configuration of $2,6$ will accept two electrons to become an anion or negatively charged ion.
For all the other configurations, losing electrons would lead to a more stable state and would form cations instead.

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MCQ 151 Mark
The Latin language name of an element is natrium. The English name of this element is:
  • Sodium.
  • B
    Potassium.
  • C
    Magnesium.
  • D
    Sulphur.
Answer
Correct option: A.
Sodium.
Sodium.
The English name of the element natrium is Sodium$(Na).$
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MCQ 161 Mark
The atoms of which of the following pair of elements are most likely to exist in free state?
  • A
    Hydrogen and helium.
  • B
    Argon and carbon.
  • C
    Neon and nitrogen.
  • Helium and neon.
Answer
Correct option: D.
Helium and neon.
Atoms of helium and neon exist in a free state because they are inert gases and chemically inactive.
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MCQ 171 Mark
Who believed that atoms could not be split:
  • A
    Thomson
  • B
    Rutherford
  • Dalton
  • D
    Both $A$ and $B$
Answer
Correct option: C.
Dalton

Dalton believed matter to be made up of tiny indivisible particles called atoms.
Both Thomson and Rutherford considered the presence of charged species in an atom and did not believe in the indivisibility of atom.

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MCQ 181 Mark
Nitrogen and hydrogen combine together to form ammonia. $N _2+3 H _2 \rightarrow 2 NH 3\  [$Relative atomic masses of $N =14 u$, $H =1 u ]$ The mass of nitrogen and hydrogen which combine together to form $6.8$ g ammonia is,
  • A
    $N _2=2.8 g, H _2=4.0 g$
  • $N _2=5.6 g, H _2=1.2 g$
  • C
    $N _2=4.0 g, H _2=2.8 g$
  • D
    $N _2=12 g, H _2=5.6 g$
Answer
Correct option: B.
$N _2=5.6 g, H _2=1.2 g$
According to the law of conservation of mas,
$5.6 g+1.2 g=6.8 g$ of ammonia.
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MCQ 191 Mark
A change in the physical state can be brought about:
  • A
    Only when energy is given to the system.
  • B
    Only when energy is taken out from the system.
  • When energy is either given to, or taken out from the system.
  • D
    Without any energy change.
Answer
Correct option: C.
When energy is either given to, or taken out from the system.
When a solid changes into liquid, it absorbs energy. When a liquid changes into solid, it releases energy.
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MCQ 201 Mark
This subatomic particle of an atom has a $POSITIVE$ charge.
  • A
    Electron
  • B
    Neutron
  • Proton
  • D
    Amitron
Answer
Correct option: C.
Proton
Proton
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MCQ 211 Mark
Match the Column $I$ with Column $II$.
S.No
Column I
 
Column II
$a$
$9.033 \times 10^{24}$ atoms
$i$
$46g$ of He
$b$
$2$ moles of Na
$ii$
$15$ moles
$c$
$11.2 L of O_2$ at $STP$
$iii$
$3.011 \times 10^{23}$ molecules
$d$
$22g$ of $CO_2$
$iv$
$16g$
  • $A (ii) B (i) C (iv) D (iii)$
  • B
    $A (i) B (ii) C (iv) D (iii)$
  • C
    $A (i) B (iii) C (iv) D (ii)$
  • D
    $A (ii) B (i) C (iii) D (iv)$
Answer
Correct option: A.
$A (ii) B (i) C (iv) D (iii)$
 (A)
S.No
Column I
 
Column II
$a$
$9.033 \times 10^{24}$ atoms
$ii$
$15$ moles
$b$
$2$ moles of Na
$i$
$46g$ of he
$c$
$11.2 L of O_2$ at $STP$
$iv$
$16g$
$d$
$22g$ of $CO_2$
$iii$
$3.011 \times 10^{23}$ molecules
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MCQ 231 Mark
Which of the following obeys the law of constant proportions in their formation:
  • A
    Mixtures
  • Compounds
  • C
    Elements
  • D
    Colloids
Answer
Correct option: B.
Compounds
The Law of constant proportion is the rule where elements combine in a fixed proportion by mass.
Thus compounds are the kind that is formed from a fixed proportion of elements.
For example, Water $\rightarrow H _2 O$ is obtained from any source of water like a river, lake, pond. Here the ratio of $H$ and $O$ will be always $2 : 1.$
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MCQ 241 Mark
The law of constant proportions was given by:
  • Proust.
  • B
    Lavoisier.
  • C
    Dalton.
  • D
    Berzelius.
Answer
Correct option: A.
Proust.
The law of constant proportion was proposed by Joseph Proust.
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MCQ 251 Mark
An atom is:
  • A
    The smallest particle of matter known
  • B
    The smallest particle of a gas
  • The smallest indivisible particle of an element that can take part in a chemical change
  • D
    Radioactive emission
Answer
Correct option: C.
The smallest indivisible particle of an element that can take part in a chemical change
The smallest indivisible particle of an element that can take part in a chemical change
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MCQ 261 Mark
The ratio of mass of nitrogen and oxygen in nitric oxide is:
  • A
    $7 : 16$
  • B
    $1 : 8$
  • $7 : 8$
  • D
    $7 : 15$
Answer
Correct option: C.
$7 : 8$
$7 : 8$
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MCQ 271 Mark
An element which can exhibit valencies of $2, 4$ and $6$ can be:
  • A
    Copper.
  • B
    Iron.
  • C
    Mercury.
  • Sulphur.
Answer
Correct option: D.
Sulphur.

Sulphur exhibits the valencies of $2, 4$ and $6.$

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MCQ 281 Mark
Which of the following would weigh the highest?
  • A
    $0.2$ mole of sucrose $\left( C _{12} H _{22} O _{\ldots}\right)$
  • B
    $2$ moles of $CO _2$
  • $2$ moles of $CaCO _3$
  • D
    $10$ moles of $H _2 O$
Answer
Correct option: C.
$2$ moles of $CaCO _3$
$a.$ Mass of $1$ mole of sucrose $(12 \times 12)+(1 \times 22)+(16 \times 11)=342 g$
Mass of $0.2$ mole of sucrose $=342 \times 0.2=68.4 g$
$b.$ Mass of $1$ mole of $CO _2=12+(16 \times 2)=44 g$. Mass of $2$ moles of $CO _2=44 \times 2=88 g$
$c.$ Mass of $1$ mole of $CaCO _3=40+12+(16 \times 3)=100 g$
Mass of $2$ moles of $CaCO _3=100 \times 2=200 g$
$d.$ Mass of $1$ mole of $H _2 O =2+16=18 g$
Mass of $10$ moles of $H _2 O =18 \times 10=180 g$
Therefore, mass of $2$ moles of $CaCO _3$ is the highest, i.e., $200 g .$
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MCQ 291 Mark
A positively charged ion is called :
  • A
    Molecule
  • B
    Atom
  • C
    Anion
  • Cation
Answer
Correct option: D.
Cation
A positively charged ion, that gets attracted towards the cathode during the electrolysis of salts, is known, as a cation.
Eg. $\mathrm{Na}^{+}, \mathrm{H}^{+}, \mathrm{Ca}^2+$
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MCQ 301 Mark
The anion in $CaCl_2$​ is:
  • A
    $Ca ^{2-}$
  • $Cl ^{-}$
  • C
    $Ca ^{2+}$
  • D
    $Cl ^{+}$
Answer
Correct option: B.
$Cl ^{-}$
$CaCl _2$ is made up of two ions, The cation is $Ca ^{2+}$ and the anion is $Cl ^{-}$
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MCQ 311 Mark
In order to verify the law of conservation of mass, we carry out chemical reactions in a closed container, so that:
  • gaseous products do not escape.
  • B
    Heat transfer does not occur.
  • C
    Reactants do not mix with the products.
  • D
    None of the above.
Answer
Correct option: A.
gaseous products do not escape.
Some mass or energy in the form of gas will not escape.
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MCQ 321 Mark
The number of $Al ^{3+}$ ions in $0.051$ g of aluminium oxide are (Atomic mass of $AI =27 u , O =16 u)$.
  • $6.022 \times 10^{20}$
  • B
    $3.3 \times 10^{20}$
  • C
    $2.2 \times 10^{20}$
  • D
    $6.022 \times 10^{23}$
Answer
Correct option: A.
$6.022 \times 10^{20}$
Molar mass of $Al _2 O _3$$= 2 × 27 + 3 × 16 = 54 + 48 = 102g$
$102g$ of $Al _2 O _3$contains $=2 \times 6.22 \times 10^{23} Al ^{3+}$ ions
$\therefore$ $0.051$g of $Al _2 O _3$contains $=\frac{2\times6.022\times10^{23}}{102}\times0.051$
$=6.022 \times 10^{20} Al ^{3+}$ions.
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MCQ 331 Mark
The formula unit mass of a substance is the:
  • Sum of the atomic masses of all atoms in a formula unit of a compound
  • B
    Relative atomic masses of atoms
  • C
    Double the numerical value of the atomic mass
  • D
    None of above
Answer
Correct option: A.
Sum of the atomic masses of all atoms in a formula unit of a compound
Sum of the atomic masses of all atoms in a formula unit of a compound
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MCQ 341 Mark
Which of the following atomic number will most likely form an anion:
  • A
    $13$
  • B
    $18$
  • C
    $12$
  • $17$
Answer
Correct option: D.
$17$
$17$
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MCQ 351 Mark
Which of the following is octa$-$atomic?
  • Sulphur.
  • B
    Oxygen.
  • C
    Ozone.
  • D
    Phosphorus.
Answer
Correct option: A.
Sulphur.
Octa atomic species are those which are made up of eight atoms.
For example, sulphur molecule is an octa atomic molecule made up of eight atoms of sulphur and is denoted by $S_8$.
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MCQ 361 Mark
Which of the following correctly represents $360g$ water?
$i. 2$ moles of $H _2 O$.
$ii. 20$ moles of water.
$iii. 6.022 \times 10^{23}$ molecules of water.
$iv. 1.2044 \times 10^{25}$ molecules of water.
  • A
    $(i)$
  • B
    $(i)$ and $(iv)$
  • C
    $(ii)$ and $(iii)$
  • $(ii)$ and $(iv)$
Answer
Correct option: D.
$(ii)$ and $(iv)$
Because $20$ miles of water is $360 g$ and also number of particles in $360 g$ of water is $1.2044 \times 10^{25}$
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MCQ 371 Mark
Molecules made up of two or more elements are called:
  • A
    Ions
  • Compounds
  • C
    Mixture
  • D
    Both $a$ and $c$
Answer
Correct option: B.
Compounds

A substance consisting of atoms or ions of two or more different elements in definite proportions joined by chemical bonds into a molecule is known as compound.
The elements cannot be separated by physical means.
Water, for example, is a compound having two hydrogen atoms and one oxygen atom per molecule.

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MCQ 381 Mark
Which part of an atom is represented by the blue circles?
  • Electrons
  • B
    Neutrons
  • C
    Protons
  • D
    $A$ and $B$
Answer
Correct option: A.
Electrons
Electrons
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MCQ 391 Mark
Dalton's theory fails to determine the existence of:
  • A
    Molecules
  • B
    Compounds
  • Allotropes
  • D
    All of the above
Answer
Correct option: C.
Allotropes
Dalton's atomic theory fails to explain the existence of allotropes; it does not account for differences in properties of charcoal, graphite, diamond.
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MCQ 401 Mark
Molecular formula of potassium nitrate is:
  • A
    $\text{KNO}$
  • B
    $\text{KNO} _2$
  • $\text{KNO} _3$
  • D
    $\text{KNO} _4$
Answer
Correct option: C.
$\text{KNO} _3$
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MCQ 411 Mark
If $1.4g$ of calcium oxide is formed by the complete decomposition of calcium carbonate, then the amount of calcium carbonate taken and the amount of carbon dioxide formed will be respectively:
  • A
    $2.2g$ and $1.1g$
  • B
    $1.1g$ and $2.5g$
  • $2.5g$ and $1.1g$
  • D
    $5.0g$ and $1.1g$
Answer
Correct option: C.
$2.5g$ and $1.1g$
Molecular mass of $\text{CaCO}_3: \   40+12+(16 \times 3)=100 g$
Molecular mass of $\text{CaO}: \ 40+16=56 g$
Molecular mass of $CO_2:  \ 12+(16 \times 2)=44 g$
Reaction for the decomposition of calcium carbonate:
$\text{CaCO}_3\ x\rightarrow\text{CaO}+\text{CO}_2$
$100\text{g}\ 56\text{g}\ 44\ \text{g}\text{ X}\ 1.4\text{g}\text{Y}$
$56g$ of $\text{CaO}$ is obtained when $100g$ of $\text{CaCO} _3$ is burnt.
Therefore, to get $1.4g$ of $\text{CaO}$, the amount of $\text{CaCO} _3$ to be burnt will be $\frac{100\ \times\ 1.4}{56}=2.5\text{g}$
For $CO _2$,
$100 g$ of $\text{CaCO} _3$ yields $44 g$ of $CO _2$
Therefore, $2.5g$ of $\text{CaCO} _3$​​​​​​​ will yield $\frac{44\ \times\ 2.5}{100}=1.1\text{g}$
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MCQ 421 Mark
One $nm$ is equal to:
  • A
    $10^{-9} mm$
  • $10^{-7} cm$
  • C
    $10^{-9} cm$
  • D
    $10^{-6} m$
Answer
Correct option: B.
$10^{-7} cm$
One nanometre is equal to $10^{-7} $ centimetre.
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MCQ 441 Mark
Atom $: ............ :$  Electrons $:$ Negatively charged:
  • No charge
  • B
    Positively charged
  • C
    Negatively charged
  • D
    None of the above
Answer
Correct option: A.
No charge
Electrons are negatively charged.
The analogy is being made based on the charges present on the given entities.
An atom has no charge.
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MCQ 451 Mark
Molecular mass is expressed in:
  • A
    $kg$
  • B
    $g$
  • $u$
  • D
    $mg$
Answer
Correct option: C.
$u$

Molecular mass is expressed in $'u'$, or unified atomic mass unit.

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MCQ 461 Mark
Which among the following has molecular mass of $36.5u:$
  • A
    Carbon molecules
  • B
    Hydrogen molecules
  • C
    Sulphur molecules
  • Hydrochloric acid
Answer
Correct option: D.
Hydrochloric acid

Molar mass of Hydrochloric acid $= 1 \times $ atomic mass of $H + 1 \times $ atomic mass of $Cl$
$= 1 \times (1) + 1 \times (35.5)$
$= 36.5u$

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MCQ 471 Mark
During an experiment hydrogen $(H2)$ and oxygen $(O2)$ gases reacted in an electric are to produce water as follows: $2\text{H}+\text{O}_2\xrightarrow{\text{Eletricity}}2\text{H}_2\text{O}$ The experiment is repeated three times and data tabulated as shown below:
Elperiment number Mass of $H_2$ reacted Mass of $o_2$ reacted Mass of $H_2O$ produced
$1$ $2g$ $16g$ $18g$
$2$ $4g$ $32g$ $36g$
$3$ - - $9g$
During $3$rd experiment the researcher forgot to list masses of $H2$ and $O2$ used. So, if the law of constant proportion is correct then find mass of $O2$ used during 3rd experiment.
  • A
    $4g$
  • $8g$
  • C
    $16g$
  • D
    $32g$
Answer
Correct option: B.
$8g$
In experiment $(i)$, the ratio is $2:16, i.e., 1:8$
In experiment $(ii)$, the ratio is $4:32, i.e., 1:8$
According to the law of constant proportions, the ratio of third experiment should be the same $(1:8)$
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MCQ 481 Mark
Calculate the formula unit mass $(u)$ of $\text{CaCl} _2 \cdot[Ca =40 u , Cl =35.5 u]$
  • $111u$
  • B
    $101u$
  • C
    $91u$
  • D
    $55u$
Answer
Correct option: A.
$111u$
Formula unit mass $=$ Atomic mass of $Ca +(2 \times$ Atomic mass of $Cl)=40+(2 \times 35.5)=40+71=111 u$
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MCQ 491 Mark
Law of definite proportions was given by:
  • Proust
  • B
    Dalton
  • C
    Lavoisier
  • D
    None of these
Answer
Correct option: A.
Proust
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MCQ 501 Mark
Symbol of $........$ is taken from Greek word Kalium.
  • A
    Sodium
  • B
    Phosphorus
  • Potassium
  • D
    Chlorine
Answer
Correct option: C.
Potassium
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