(2, -3, -1) 2x - 3y + 6z + 7 = 0: 1. 4 2. 3 3. 2 4. 1 5 - Vidyadip

Question

(2, -3, -1) 2x - 3y + 6z + 7 = 0:

4
3
2
$\frac{1}{5}$

✓

Answer

2

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Three Dimensional Geometry→Three Dimensional Geometry — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

A line with positive direction cosines passes through the point P(2, -1, 2) and makes equal angles with the coordinate axes. The line meets the plane 2x + y + z = 9 at point Q. The length of the line segment PQ equals:

$1$
$\sqrt{2}$
$\sqrt{3}$
$2$

The differential coefficient of $\text{f}(\log\text{x})$ w.r.t. x, where $\text{f(x)}=\log\text{x}$ is:

$\frac{\text{x}}{\log\text{x}}$
$\frac{\log\text{x}}{\text{x}}$
$(\text{x}\log\text{x})^{-1}$
$\text{None of these.}$

Choose the correct answer from the given four options.
The probability distribution of a discrete random variable X is given below:

$\text{X}$	$2$	$3$	$4$	$5$
$\text{P}(\text{X})$	$\frac{5}{\text{k}}$	$\frac{7}{\text{k}}$	$\frac{9}{\text{k}}$	$\frac{11}{\text{k}}$

The value of k is:

A point P lies on the line segment joining the points (-1, 3, 2) and (5, 0, 6). If x-coordinate of P is 2, then its z-coordinate is:

$-1$
$4$
$\frac{3}{2}$
$8$

Choose the correct answer in Exercise:
The value of the integral $\int^{1}_{\frac{1}{3}}\frac{(\text{x}-\text{x}^{3})^{\frac{1}{3}}}{\text{x}^{4}}\text{dx}\ \text{is}$

6
0
3
4

If $\text{y}=\sqrt{\sin\text{x}+\text{y}},$ then $\frac{\text{dy}}{\text{dx}}$ equals:

$\frac{\cos\text{x}}{2\text{y}-1}$
$\frac{\cos\text{x}}{1-2\text{y}}$
$\frac{\sin\text{x}}{1-2\text{y}}$
$\frac{\sin\text{x}}{2\text{y}-1}$

The distance of the point (-3, 4, 5) from the origin:

50
$5\sqrt{2}$
6
None of these

If the projection of $\vec{\text{a}}=\hat{\text{i}}-2\hat{\text{j}}+3\hat{\text{k}}$ on $\vec{\text{b}}=2\hat{\text{i}}+\lambda\hat{\text{k}}$ is zero, then the value of $\lambda$ is:

$0$
$1$
$\frac{-2}{3}$
$\frac{-3}{2}$

Integrating factor of the differential equation, $(1-\text{x}^2)\frac{\text{dy}}{\text{dx}}-\text{xy}=1$ is:

$-\text{x}$
$\frac{\text{x}}{1+\text{x}^2}$
$\sqrt{1-\text{x}^2}$
$\frac{1}{2}\log(1-\text{x}^2)$

If $\text{f(x)}=\begin{cases}\text{mx}+1,&\text{x}\leq\frac{\pi}{2}\\\sin\text{x}+\text{n},&\text{n}>\frac{\pi}{2}\end{cases}$ is continuous at $\text{x}=\frac{\pi}{2},$ then:

$\text{m}=1,\text{ n}=0$
$\text{m}=\frac{\text{n}\pi}{2}+1$
$\text{n}=\frac{\text{m}\pi}{2}$
$\text{m}=\text{n}=\frac{\pi}{2}$