MCQ
$2-$ Butyne react with $Na$ in liquid Ammonia to form
- A$1-$ butene
- B$Cis$ $-2-$ butene
- ✓trans $-2-$ butene
- D$n-$ butane
$\begin{aligned}\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CCH}_{3} \frac{\mathrm{Na}}{\mathrm{Liq.NH}_{3}} \mathrm{CH}_{3}-\mathrm{C}=& \mathrm{C}-\mathrm{CH}_{3} \\& \mathrm{H}\end{aligned}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$A$ and $B$ in the above atmospheric reaction step are.
