MCQ 11 Mark
For the given reaction:
$Image$
$P$ is

Answera

View full question & answer→MCQ 21 Mark
Given below are two statements:
Statement $I$ : The boiling point of three isomeric pentanes follows the order
n-pentane $>$ isopentane $>$ neopentane
Statement $II$ : When branching increases, the molecule attains a shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point.
In the light of the above statements, choose the most appropriate answer from the options given below:
- A
Both Statement $I$ and Statement $II$ are incorrect
- B
Statement $I$ is correct but Statement $II$ is incorrect
- C
Statement $I$ is incorrect but Statement $II$ is correct
- ✓
Both Statement $I$ and Statement $II$ are correct
AnswerCorrect option: D. Both Statement $I$ and Statement $II$ are correct
d
Both statement $I$ and statement $II$ are correct.
Boiling point of n-pentane $=309 \mathrm{~K} $
isopentane $=301 \mathrm{~K} $
neopentane $ =282.5$
As branching increases molecules attain the shape of a sphere results in smaller area of contact thus weak intermolecular forces between spherical molecules, which are overcome at relatively lower temperature. Leading to decrease in boiling point.
View full question & answer→MCQ 31 Mark
Weight $(g )$ of two moles of the organic compound, which is obtained by heating sodium ethanoate with sodium hydroxide in presence of calcium oxide is :
Answerc
This reaction is called soda lime decarboxylation
Molar mass of $CH _4=16\,g / mol$
Weight of 2 moles of $CH _4=16 \times 2$
$=32\,g$

View full question & answer→MCQ 41 Mark
Consider the following compounds/species:
The number of compounds/species which obey Huckel's rule is $..........$

Answerb
Huckle's rule $=(4 n+2) \pi$ electrons Comp $(i), (ii), (v), (vii)$ obey Huckle's rule.
View full question & answer→MCQ 51 Mark
Compound $X$ on reaction with $O _{3}$ followed by $Zn /$ $H _{2} O$ gives formaldehyde and $2-$methyl propanal as products. The compound $X$ is :
- A
$2-$Methylbut$-1-$ene
- B
$2-$Methylbut$-2-$ene
- C
Pent$-2-$ene
- ✓
$3-$Methylbut$-1-$ene
AnswerCorrect option: D. $3-$Methylbut$-1-$ene
d

View full question & answer→MCQ 61 Mark
Which compound amongst the following is not an aromatic compound?
Answerc

View full question & answer→MCQ 71 Mark
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO}^{-} \mathrm{Na}^{+} \xrightarrow[\mathrm{Heat}]{\mathrm{NaOH},+?} \mathrm{CH}_{3} \mathrm{CH}_{3}+ \mathrm{Na}_{2} \mathrm{CO}_{3} .$
Consider the above reaction and identify the missing reagent/chemical.
AnswerCorrect option: C. $\mathrm{CaO}$
c
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{COONa} \xrightarrow[\Delta]{\mathrm{NaOH}+?} \mathrm{CH}_{3}-\mathrm{CH}_{3}$
It's decarboxylation in presence of sodalime so missing reagent is $\mathrm{CaO} .$ $(\mathrm{NaOH}+\mathrm{CaO})$ sodalime
View full question & answer→MCQ 81 Mark
Which of the following is a free radical substitution reaction?
- A
Propene with $HBr /\left( C _{6} H _{5} COO \right)_{2}$
- B
Benzene with $Br _{2} / AlCl _{3}$
- C
Acetylene with $HBr$
- ✓
Methane with $Br _{2} / hv$
AnswerCorrect option: D. Methane with $Br _{2} / hv$
d
Reaction of methane with $Br _{2}$ in the presence of light is a free radical substitution reaction.

View full question & answer→MCQ 91 Mark
An alkene on ozonolysis gives methanal as one of the product. Its structure is
Answerd

View full question & answer→MCQ 101 Mark
Urea reacts with water to form $A$ which will decompose to form $B. B$ when passed through $Cu ^{2+}( aq ),$ deep blue colour solution $C$ is formed. What is the formula of $C$ from the following$?$
AnswerCorrect option: C. $\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}$
c
$NH _{2} CONH _{2}+ H _{2} O \rightarrow CO _{2}+ NH _{4} OH$
$(A)$
$NH _{4} OH \stackrel{\Delta}{\longrightarrow} NH _{3}+ H _{2} O$
$(B)$
$Cu ^{+2}( aq )+4 NH _{3} \rightarrow\left[ Cu \left( NH _{3}\right)_{4}\right]^{+2}($ deep blue $)$
$(C)$
View full question & answer→MCQ 111 Mark
Which of the following alkane cannot be made in good yield by Wurtz reaction$?$
- A
n$-$Butane
- B
n$-$Hexane
- C
$2,3 -$Dimethylbutane
- ✓
n$-$Heptane
AnswerCorrect option: D. n$-$Heptane
d
n$-$Heptane can not be made in good yield using Wurtz reaction since it is unsymmetrical alkane.
View full question & answer→MCQ 121 Mark
The most suitable reagent for the following conversion is

- A
$Na/lquid\; NH_{3}$
- ✓
$\mathrm{H}_{2}, \mathrm{Pd} / \mathrm{C},$ quinoline
- C
$Zn/HCl$
- D
$\mathrm{Hg}^{2+} / \mathrm{H}^{+}, \mathrm{H}_{2}O$
AnswerCorrect option: B. $\mathrm{H}_{2}, \mathrm{Pd} / \mathrm{C},$ quinoline
b

View full question & answer→MCQ 131 Mark
In the following reaction,
$\mathrm{C}\mathrm{H}_{3} -\mathrm{C} \equiv \mathrm{CH} \xrightarrow[873\;K]{\text { red hot iron tube}} \mathrm{A}$
the number of sigma$(\sigma)$ bonds present in the product $A$ is
Answera

View full question & answer→MCQ 141 Mark
The alkane that gives only one mono-chloro product on chlorination with $Cl_2$ in presence of diffused sunlight is
- A
$2,2-$dimethylbutane
- ✓
- C
$n-$pentane
- D
View full question & answer→MCQ 151 Mark
The number of sigma ( $\sigma$ ) and pi ( $\pi$ ) bonds in pent$- 2 -$en$- 4 -$yne is
- ✓
$10\sigma $ bonds and $3\pi$ bond
- B
$8\sigma $ bonds and $5\pi$ bond
- C
$11\sigma $ bonds and $2\pi$ bond
- D
$13\sigma $ bonds and $\pi$ bond
AnswerCorrect option: A. $10\sigma $ bonds and $3\pi$ bond
a
$\begin{array}{*{20}{c}} {{\text{H}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {{\text{H - C - C = C - C}} \equiv {\text{C - H}}} \\ {|\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\;\;\,\,\,\,\,\,\,\,\,\,} \\ {{\text{H}}\,\,\,\,\,\,{\text{H}}\,\,\,\,\,\,{\text{H}}\,\,\,\,\;\;\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}$
Number of sigma bonds $=10$
Number of $\pi$ -bonds $=3$
View full question & answer→MCQ 161 Mark
Match the catalyst with the process
| Catalyst |
Process |
| $(i) \;\mathrm{Na}_{2} \mathrm{O}$ |
$(a)$ The oxidation of ethyne to ethanal |
| $(ii) \;\mathrm{TiCl}_{4}+ \mathrm{Al(CH_3)}_{3}$ |
$(b)$ Polymerisation of alkynes |
|
$(iii)\;\mathrm{PdCl_2} $
|
$(c)$ Oxidation of $SO_2$ in the manufacture of $H_2SO_4$ |
| $(iv)\;$Nickel complexes |
$(d)$ Polymerisation of ethylene |
Which of the following is the correct option ?
- ✓
$i-c, ii-d, iii-a, iv-b$
- B
$i-a, ii-b, iii-c, iv-d$
- C
$i-a, ii-c, iii-b, iv-d$
- D
$i-c, ii-a, iii-d, iv-b$
AnswerCorrect option: A. $i-c, ii-d, iii-a, iv-b$
View full question & answer→MCQ 171 Mark
An alkene $A$ on reaction with $\mathrm{O}_{3}$ and $\mathrm{Zn}-\mathrm{H}_{2} \mathrm{O}$ gives propanone and ethanal in equimolar ratio. Addition of $HCl$ to alkene $A$ gives $B$ as the major product. The structure of product $B$ is:
- A
$Cl - C{H_2} - C{H_2} - \begin{array}{*{20}{c}}
{C{H_3}} \\
{|\,\,\,\,\,} \\
{CH} \\
{|\,\,\,\,\,} \\
{C{H_3}}
\end{array}$
- B
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}Cl} \\
{\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - C{H_2} - CH - C{H_3}}
\end{array}$
- ✓
$C{H_3} - C{H_2} - \begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
- D
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{H_3}C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - CH - CH} \\
{\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\;\;|} \\
{\,\,\,\,\,\,\,Cl\,\,\,\;{H_3}C}
\end{array}$
AnswerCorrect option: C. $C{H_3} - C{H_2} - \begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
c

View full question & answer→MCQ 181 Mark
Hydrocarbon $(A)$ reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon contalning less than four carbon atoms. $(\mathrm{A})$ is
- A
$CH\equiv CH$
- B
$CH_2= CH_2$
- C
$CH_3-CH_3$
- ✓
$CH_4$
AnswerCorrect option: D. $CH_4$
d
$\mathrm{CH}_{4} \xrightarrow[hv]{Br_2}-\mathrm{CH}_{3}-\mathrm{Br} \xrightarrow[ether]{Na} \mathrm{CH}_{3}-\mathrm{CH}_{3}$
(less than four 'C)
View full question & answer→MCQ 191 Mark
With respect to the conformers of ethane, which of the following statements is true ?
- A
Bond angle changes but bond length resame.
- B
Both bond angle and bond length change.
- ✓
Both bond angle and bond length remain same.
- D
Bond angle resame but bond length changes.
AnswerCorrect option: C. Both bond angle and bond length remain same.
c
In conformation bond angle and bond length remain same.
View full question & answer→MCQ 201 Mark
Predict the correct intermediate and product in the following reaction :
${H_3}C - C \equiv CH\,\xrightarrow[{HgS{O_4}}]{{{H_2}O,\,{H_2}S{O_4}}}\,\mathop {Intermediate}\limits_{(A)} \,$$ \to \,\mathop {\Pr oduct}\limits_{(B)} $
- A
$A \,: \, \begin{array}{*{20}{c}}
{{H_3}C - C = C{H_2}} \\
| \\
{OH}
\end{array}$ $ B\,\, :\, \begin{array}{*{20}{c}}
{{H_3}C - C = C{H_2}} \\
| \\
{S{O_4}}
\end{array}$
- B
$A\,\, :\,\begin{array}{*{20}{c}}
{{H_3}C - C - C{H_3}} \\
{|\,|} \\
O
\end{array}$ $B\,\,:\, H_3C-C=CH$
- ✓
$A \,: \, \begin{array}{*{20}{c}}
{{H_3}C - C = C{H_2}} \\
| \\
{OH}
\end{array}$ $B\,\, :\,\begin{array}{*{20}{c}}
{{H_3}C - C - C{H_3}} \\
{|\,|} \\
O
\end{array}$
- D
$ A\,\, :\, \begin{array}{*{20}{c}}
{{H_3}C - C = C{H_2}} \\
| \\
{S{O_4}}
\end{array}$ $B\,\, :\,\begin{array}{*{20}{c}}
{{H_3}C - C - C{H_3}} \\
{|\,|} \\
O
\end{array}$
AnswerCorrect option: C. $A \,: \, \begin{array}{*{20}{c}}
{{H_3}C - C = C{H_2}} \\
| \\
{OH}
\end{array}$ $B\,\, :\,\begin{array}{*{20}{c}}
{{H_3}C - C - C{H_3}} \\
{|\,|} \\
O
\end{array}$
c
$C{{H}_{3}}-C\equiv CH\xrightarrow[HgS{{O}_{4}}]{{{H}_{2}}O.{{H}_{2}}S{{O}_{4}}}\begin{matrix}
C{{H}_{3}}-C=C{{H}_{2}} \\
|\,\, \\
\,\,\,OH \\
\end{matrix}$ $\xrightarrow{Tautomerism}\begin{matrix}
CH3-C-C{{H}_{3}} \\
|| \\
O \\
\end{matrix}$
View full question & answer→MCQ 211 Mark
Amongst the following compounds the one which is most easily sulphonated is
View full question & answer→MCQ 221 Mark
Which one is the correct order of acidity ?
- ✓
$CH\equiv CH > CH_{3}-C\equiv CH$$ > CH_2=CH_2 > CH_{3}-CH_3$
- B
$CH\equiv CH > CH_2=CH_2 $$> CH_{3}-C\equiv CH > CH_{3}-CH_3$
- C
$CH_{3}-CH_3 > CH_2CH_2 $$> CH_{3}-C \equiv CH > CH \equiv CH$
- D
$CH_2=CH_2 > CH_{3}-CH= CH_2 $$> CH_{3}-C \equiv CH > CH \equiv CH$
AnswerCorrect option: A. $CH\equiv CH > CH_{3}-C\equiv CH$$ > CH_2=CH_2 > CH_{3}-CH_3$
a
$\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>$$\mathrm{CH}_{2}=\mathrm{CH}_{2}>\mathrm{CH}_{3}-\mathrm{CH}_{3}$
acc. to EN and Inductive effect.
View full question & answer→MCQ 231 Mark
Which of the following compounds shall not produce propene by reaction with $HBr$ followed by elimination or direct only elimination reaction ?
- A
- B
$H_3C-CH_2-CH_2OH$
- ✓
$H_2C = C=O$
- D
$H_3C-CH_2-CH_2Br$
AnswerCorrect option: C. $H_2C = C=O$
c

View full question & answer→MCQ 241 Mark
The compound that will react most readily with gaseous bromine has the formula
- ✓
$C_3H_6$
- B
$C_2H_2$
- C
$C_4H_{10}$
- D
$C_2H_4$
AnswerCorrect option: A. $C_3H_6$
a
Propene is most reactive towards $B r_{2}$ (gaseous) than $C H_{2}=C H_{2}, H C=C H \&$ butane due to most electron density.
View full question & answer→MCQ 251 Mark
The pair of electrons in the given carbanion, $CH_3C \equiv C^-,$ is present in which of the following orbitals ?
Answerb
$\mathrm{CH}_{3}-\stackrel{sp}{\mathrm{C}}\equiv \stackrel{sp}{\mathrm{C}^{-}}$
Thus, pair of electrons is present in sp-hybridised orbital.
View full question & answer→MCQ 261 Mark
Which of the following can be used as the halide component for Friedel-Crafts reaction ?
Answerd

View full question & answer→MCQ 271 Mark
In which of the following molecules, all atoms are coplanar ?
Answera
Biphenyl is coplanar as all $C-$atoms are sp $^{2}$ hybridised and its geometry is trigonal planar.
View full question & answer→MCQ 281 Mark
In pyrrole the electron density is maximum on

- A
$2$ and $3$
- B
$3$ and $4$
- C
$2$ and $4$
- ✓
$2$ and $5$
AnswerCorrect option: D. $2$ and $5$
d
Pyrrole has highest electron density at $C_{2}$ and $C_{5}$ due to highest stability of protonated intermediate

View full question & answer→MCQ 291 Mark
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is
- A
the eclipsed conformation of ethane ismore stable than staggered conformation even though the eclipsed conformation has torsional strain
- ✓
the staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
- C
the staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
- D
the eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has notorsional strain.
AnswerCorrect option: B. the staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
b
Magnitude of torsional strain depends upon the angle of rotation about $\mathrm{C}-\mathrm{C}$ bond. Staggered form has the least torsional strain and the eclipsed form has the maximum torsional strain. So, the staggered conformation of ethane is more stable than the eclipsed conformation.

View full question & answer→MCQ 301 Mark
Consider the nitration of benzene using mixed conc. $H_2SO_4$ and $HNO_3. $ If a large amount of $KHSO_4$ is added to the mixture, the rate of nitration will be
Answerd
$\mathrm{H}_{2} \mathrm{SO}_{4}+\stackrel{\oplus}{\mathrm{H}} \longrightarrow \mathrm{NO}_{2}+\mathrm{H \stackrel{\ominus}{S}O}_{4}+\mathrm{H}_{2} \mathrm{O}$
$\mathrm{KHSO}_{4} \longrightarrow \mathrm{K}^{\oplus}+\mathrm{H\stackrel{\ominus}{S}O}_{4}$
Due to common ion effect backward reaction will take so the formation $\mathrm{NO}_{2}^{+}$ decrease so nitration process will become slower.
View full question & answer→MCQ 311 Mark
In the reaction
$H - C\, \equiv CH\,\xrightarrow[{(ii)\,C{H_3}C{H_2}Br}]{{(i)\,NaN{H_2}\,/\,liq.\,N{H_3}}}\,X$
$\xrightarrow[{(ii)\,C{H_3}C{H_2}Br}]{{(i)\,NaN{H_2}\,/\,liq.\,N{H_3}}}\,Y$
$X$ and $Y$ are
- A
$X= {2-}$Butyne$,\, Y = {2-}$Hexyne
- B
$X= 1-$Butyne$,\, Y = {2-}$Hexyne
- ✓
$X= 1-$Butyne$,\, Y = {3-}$Hexyne
- D
$X= {2-}$Butyne$, \,Y = {3-}$Hexyne.
AnswerCorrect option: C. $X= 1-$Butyne$,\, Y = {3-}$Hexyne
c
$H-C\equiv C-H\xrightarrow[liq.\,N{{H}_{3}}]{Na\,N{{H}_{2}}/}HC\equiv C\,Na$ $\xrightarrow[-NaBr]{C{{H}_{3}}C{{H}_{2}}-Br}CH\equiv C-C{{H}_{2}}-C{{H}_{3}}$
$C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\xrightarrow[liq.\,N{{H}_{3}}]{Na\,N{{H}_{2}}/}$ $C{{H}_{3}}-C{{H}_{2}}-C\equiv C\,Na\xrightarrow[-NaBr]{C{{H}_{3}}C{{H}_{2}}-Br}$ $\underset{3-Hexyne}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C\equiv C-C{{H}_{2}}-C{{H}_{3}}}}\,$
View full question & answer→MCQ 321 Mark
In the given reaction, the product $P$ is

Answerc

View full question & answer→MCQ 331 Mark
In the reaction with $HCl,$ an alkene reacts in accordance with the Markovnikov's rule to give a product $1-$chloro${-1}$ methylcyclohexane. The possible alkene is
AnswerCorrect option: C. $(A)$ and $(B)$
c

View full question & answer→MCQ 341 Mark
The oxidation of benzene by $V_2O_5$ in the presence of air produces and high tempreture
Answera

View full question & answer→MCQ 351 Mark
A single compound of the structure, is obtainable from ozonolysis of which of the following cyclic compounds?

Answerc

View full question & answer→MCQ 361 Mark
Identify $Z$ in the sequence of reactions :
$CH_3 CH_2 CH=CH_2 \xrightarrow{{HBr/{H_2}{o_2}}}\,Y\,\xrightarrow{{{C_2}{H_5}ONa}}Z$
- ✓
$CH_{3}-(CH_2)_3 - O - CH_2CH_3$
- B
$(CH_3)_2CH - O - CH_2CH_3$
- C
$CH_3(CH_2)_4 - O - CH_3$
- D
$CH_3CH_2 - CH(CH_3) - O - CH_2CH_3$
AnswerCorrect option: A. $CH_{3}-(CH_2)_3 - O - CH_2CH_3$
a
$C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}\xrightarrow[(peroxide\,or\,anti-Markovnikov's\,effect)]{HBr/{{H}_{2}}{{O}_{2}}}$ $\underset{(Y)}{\mathop{\underset{1-Bromobu\tan e}{\mathop{\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,| \\
C{{H}_{3}}C{{H}_{2}}-CH-C{{H}_{2}} \\
\,\,\,\,| \\
\,\,\,\,\,H \\
\end{matrix}}}\,}}\,\xrightarrow[\Delta ]{{{C}_{2}}{{H}_{5}}ONa}$ $\underset{(Z)}{\mathop{C{{H}_{3}}{{(C{{H}_{2}})}_{3}}-O-C{{H}_{2}}C{{H}_{3}}}}\,$
View full question & answer→MCQ 371 Mark
What products are formed when the following compound is treated with $Br_2$ in the presence of $FeBr_3$ ?

Answerc
$-\mathrm{CH}_{3}$ group is o.p-directing. Because of crowding, no substitution occurs at the carbon atom between the two $-\mathrm{CH}_{3}$ groups in $\mathrm{m}$ -Xylene, even though two $-\mathrm{CH}_{3}$ groups activate that position.

View full question & answer→MCQ 381 Mark
Which of the following organic compounds has same hybridization as its combustion product $(CO_2)\,?$
Answerb
Hybridisation of carbon $=s p^{3-n u m b e r\;of\; \pi -bonds}$ $\ln C O_{2}, \begin{array}{l}{\left(O =C=O\right)} \\ { { \quad 1\pi } \;\;\;\;1 \pi }\end{array}$ hybridisation of carbon
$=s p^{3-2}=s p$
In ethyne or acetylene, $C_{2} H_{2},\left(H-C_{2 \pi}^{=} C-H\right)$
hybridisation of carbon $=s p^{3-2}=s p$
View full question & answer→MCQ 391 Mark
In the following reaction:
$HC \equiv CH\,\xrightarrow[{H{g^{2 + }}}]{{{H_2}S{O_4}}}\,'P'$
Product $'P'$ will not give
View full question & answer→MCQ 401 Mark
Which of the following compounds will not undergo Friedal-Craft's reaction easily?
Answera
Friedal Craft reaction fails when strong deactivating group is attached with benzene ring.
View full question & answer→MCQ 411 Mark
Which of the following chemical system is non aromatic ?
Answerd
The molecules which do not satisfy Huckel rule or $(4 n+2) \pi$ -electron rule are said to be nonaromatic. The compound (d) has total $4 \pi e^-$. It does not follow $(4n + 2)$ rule. So it is non-aromatic compound. All other compounds $(a, b, c)$ are planar and have $6 \pi e^{-},$ so they are aromatic.
View full question & answer→MCQ 421 Mark
Some $meta-$ directing substituents in aromatic substitution are given. Which one is most deactivating?
- A
$- COOH$
- ✓
$- NO_2$
- C
$- C\equiv N$
- D
$- SO_3H$
AnswerCorrect option: B. $- NO_2$
b
$-\mathrm{NO}_{2}$ is most deactivating due to - $\mathrm{I}$ and $-\mathrm{M}$ effect.
View full question & answer→MCQ 431 Mark
Which of the following shows only one brominated compound
- A
Butene $-2$
- ✓
$2, 2-$ dimethylpropane
- C
Butyne $-1$
- D
Butanol $-3$
AnswerCorrect option: B. $2, 2-$ dimethylpropane
b
Option $A$ will give $2$ mono brominated products, as $Br$ can go on $C _1 / C _2$.
Option $B$ will give $1$ mono brominated products, as $Br$ can go on $C _1$.
Option $C$ will give $1$ mono brominated products, as $Br$ can go on $C _1 / C _2 / C _3 / C _4$.
Option $D$ will give $2$ mono brominated products, as $Br$ can go on $C _1 / C _2 / C _3 / C _4$.
Therefore,Option $B$ is correct answer for this question.
View full question & answer→MCQ 441 Mark
Kerosene is used as fuel because it is
View full question & answer→MCQ 451 Mark
$C{H_3} - C{H_2} - C{H_2} - C{H_3}\mathop {}\limits_{} {\rm{}}$ $ \xrightarrow[HBr]{AlCl_3} $ Product in above reaction is
- A
$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
- ✓
$C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_3}$
- C
$\mathop {\mathop {C{H_2}}\limits_{\,\,|\,\,\,\,\,\,\,\,\,\,} }\limits_{Br\,\,\,\,} - C{H_2} - \mathop {\mathop {C{H_2}}\limits_{|\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} $
- D
AnswerCorrect option: B. $C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_3}$
b
$C{H_3} - C{H_2} - C{H_2} - C{H_3}\mathop {}\limits_{} {\rm{}}$ $ \xrightarrow[HBr]{AlCl_3} C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_3}$
When $n$-butane is heated in the presence of $AlCl _{3} / HBr$.
It will be converted into Iso-butane.
It is a rearrangement reaction.
View full question & answer→MCQ 461 Mark
The chemical added to leaded petrol to prevent the deposition of lead in the combustion chamber is
View full question & answer→MCQ 471 Mark
Which of the following has the highest boiling point
- A
- B
$n-$ butane
- ✓
$n-$ heptane
- D
AnswerCorrect option: C. $n-$ heptane
c
The boiling point of $n$-heptane is $98.42$ degrees celsius.
The boiling point of $n$-butane is $-1$ degrees celsius.
The boiling point of neopentane is $9.5$ degrees celsius.
The boiling point of isobutane is $-11.7$ degrees celsius.
So $n$-heptane has the highest boiling point.
View full question & answer→MCQ 481 Mark
Which of the following does not react with $PC{l_5}$
- A
$C{H_3}OH$
- B
$C{H_3}COOH$
- C
$C{H_3}CHO$
- ✓
${C_2}{H_6}$
AnswerCorrect option: D. ${C_2}{H_6}$
d
$PCl _5$ usually used to replace - $OH$ group or oxygen of carbonyl group.

View full question & answer→MCQ 491 Mark
A reaction between methyl magnesium bromide and ethyl alcohol gives
Answera
(a)

View full question & answer→MCQ 501 Mark
Methane and ethane both can be obtained in single step from
- ✓
$C{H_3}I$
- B
${C_2}{H_5}I$
- C
$C{H_3}OH$
- D
${C_2}{H_5}OH$
AnswerCorrect option: A. $C{H_3}I$
a
(a)$C{H_3}I + 2H \xrightarrow{Zn/HCl} C{H_4} + HI$
$C{H_3}I + 2Na + IC{H_3}\mathop {}\limits_{{\rm{}}} \xrightarrow[Ether]{Dry} C{H_3} - C{H_3} + 2NaI$
View full question & answer→MCQ 511 Mark
Petroleum consists mainly of
Answera
Liquefied Petroleum Gas or LPG (also called Autogas) consists mainly of Aliphatic hydrocarbons
(propane, propylene, butane, and butylene in various mixtures).
It is produced as a by-product of natural gas processing and petroleum refining.
Petroleum is a mixture of a very large number of different hydrocarbons; the most commonly found molecules are alkanes (paraffins), cycloalkanes (naphthenes), aromatic hydrocarbons, or more complicated chemicals like asphaltenes.
View full question & answer→MCQ 521 Mark
The correct order of reactivity of $I, II$ & $III$ towards addition reactions is

- A
$I > III > II$
- ✓
$I > II > III$
- C
$III > II > I$
- D
$III > I > II$
AnswerCorrect option: B. $I > II > III$
b
$(b)$ Cyclopropane is most unstable therefore more reactive toward addition reaction. Cyclopentene is most stable $\therefore$ less reactive .
View full question & answer→MCQ 531 Mark
Which of the following reactants is suitable for preparation of methane and ethane by using one step only ?
- A
$H_2C = CH_2$
- B
$CH_3OH$
- ✓
$CH_3 - Br$
- D
$CH_3 - CH_2 - OH$
AnswerCorrect option: C. $CH_3 - Br$
c
$C{H_3} - Br\xrightarrow{{reduction}}C{H_4}$
$C{H_3} - Br\xrightarrow{{Wurtz}}C{H_3} - C{H_3}$
View full question & answer→MCQ 541 Mark
Product $(C)$ is
(figure) $\xrightarrow[CC{{l}_{4}}]{B{{r}_{2}}}(A)\xrightarrow[(ii)\,NaN{{H}_{2}}]{(i)\,alc.\,KOH}(B)\xrightarrow[(ii)\,C{{H}_{3}}-Cl]{(i)\,NaN{{H}_{2}}}(C)$

- A
$Ph - C \equiv CNa$
- B
$Ph - CH_2 -C \equiv CH$
- ✓
$Ph -C \equiv C - CH_3$
- D
$Ph - CH = C =CH_2$
AnswerCorrect option: C. $Ph -C \equiv C - CH_3$
c
$\begin{array}{*{20}{c}}
{(A)\,Ph - CH - C{H_2} - Br}\\
{|\,\,\,\,\,\,\,\,\,\,}\\
{Br\,\,\,\,\,\,\,\,\,}
\end{array}\,\,\,\,\,\,(B)\,Ph - C \equiv C - H\,\,\,\,(C)\,\,Ph - C \equiv C - C{H_3}$
View full question & answer→MCQ 551 Mark
How many carbon atoms does an alkane (not a cycloalkane) need before it is capable to exist in enantiomeric form ?
Answerd

View full question & answer→MCQ 561 Mark
Among the following free radical bromination reactions, select those in which $2^o$ halide is the major product

- A
$P, Q, R, S$
- ✓
$P, R, U$
- C
$P, R, S, T$
- D
$P, Q, R, S, T$
AnswerCorrect option: B. $P, R, U$
b
$(b)$ Bromine is more selective $\therefore$ it will form $3^o$ halide if there is presence of $3^o$ hydrogen. $\therefore\, Q, S, T,$ form $3^o$ halide as major and $P, R, U$ form $2^o$ halide as major.
View full question & answer→MCQ 571 Mark
$(A) + C{l_2}\xrightarrow{{hv}}$ monochloro product
To maximise the yield of monochloro product in the above reaction ?
- A
$Cl_2$ must be added in excess
- ✓
Reactant $(A)$ must be added in excess
- C
Reaction must be carried out in dark
- D
Reaction must be carried out with equimolar mixture of $Cl_2$ and $A$
AnswerCorrect option: B. Reactant $(A)$ must be added in excess
b
$(b)$ If reactant $(A)$ is added in excess then maximum collission between $(A)$ and $C{l^ \bullet }$ in the rate determining step.
View full question & answer→MCQ 581 Mark
$C{H_3} - C{H_2} - C{H_2} - C{H_3}\xrightarrow{{B{r_2}/hv}}$
Major product in the above reaction is
Answera
$(a)$ $2^o$ halide is major, due to formation of $sp^2$ -hybridized free radical racemization take place.
View full question & answer→MCQ 591 Mark
Product $(A)$ is

View full question & answer→MCQ 601 Mark
View full question & answer→MCQ 611 Mark
The reaction conditions leading to the best yields of $C_2H_5Cl$ are
- ✓
${C_2}{H_6}(excess)\, + \,C{l_2}\,\xrightarrow{{UV}}$
- B
${C_2}{H_6}\, + \,C{l_2}\,\xrightarrow[{room\,\,\,temp.}]{{dark}}$
- C
${C_2}{H_6}\, + \,C{l_2}(excess)\,\xrightarrow{{UV}}$
- D
${C_2}{H_6}\, + \,C{l_2}\,\xrightarrow{{UV}}$
AnswerCorrect option: A. ${C_2}{H_6}(excess)\, + \,C{l_2}\,\xrightarrow{{UV}}$
a
There can be polyhalogenation in this reaction but if excess of ethane is taken, then $C_5H_5Cl$ is obtained is major amount
View full question & answer→MCQ 621 Mark
$(CH_3)_2CHBr$ $\xrightarrow[{(2)\,CuI}]{{(1)\,Li}}\left( A \right)\xrightarrow{{{{\left( {C{H_3}} \right)}_2}CHC{H_2}Br}}B$
$'B'$ is
AnswerCorrect option: C. $(CH_3)_2CHCH_2CH(CH_3)_2$
c

View full question & answer→MCQ 631 Mark
$n-$ heptane $\xrightarrow[{600\,{}^oC}]{{C{r_2}{O_3}/{V_2}{O_3}}}$ ?
Answerb

View full question & answer→MCQ 641 Mark
Arrange following alkanes in order of their boiling points
$(A)$ Pentane
$(B)\,2-$ Methyl butane
$(C)\,2,2-$ Dimethyl propane
- ✓
$A > B > C$
- B
$A > C > B$
- C
$C > B > A$
- D
$C > A > B$
AnswerCorrect option: A. $A > B > C$
View full question & answer→MCQ 651 Mark
Choose the chain terminating step
(1)${H_2} \to {H^ \bullet } + {H^ \bullet }$
(2)$B{r_2} \to B{r^ \bullet } + B{r^ \bullet }$
(3)$B{r^ \bullet } + HBr \to {H^ \bullet } + B{r_2}$
(4)${H^ \bullet } + B{r_2} \to HBr + B{r^ \bullet }$
(5)$B{r^ \bullet } + B{r^ \bullet } \to B{r_2}$
Answerd
Step $5$ is chain termination step since no more radical formation is taking place.
View full question & answer→MCQ 661 Mark
Ethylene reacts with bromine to form
- A
$Br - C{H_2} - C{H_3}$
- B
$C{H_3} - CB{r_3}$
- ✓
$Br - C{H_2} - C{H_2}Br$
- D
$CHB{r_3}$
AnswerCorrect option: C. $Br - C{H_2} - C{H_2}Br$
c
Alkenes react in the cold with pure liquid bromine, or with a solution of bromine in an organic solvent like tetrachloromethane. The double bond breaks, and a bromine atom becomes attached to each carbon.... In the case of the reaction with ethene, $1,2$-dibromoethane is formed.

View full question & answer→MCQ 671 Mark
Which of the following will give a mixture of cis and trans- $1,4$ -dimethyl cyclohexane, when undergo catalytic hydrogenation ?
AnswerCorrect option: D. both $(a)$ & $(b)$
d

View full question & answer→MCQ 681 Mark
An optically active compound $A$ with molecular formula $C_8H_{14}$ undergoes catalytic hydrogenation to give mesa compound, the structure of $(A)$ is
Answerb

View full question & answer→MCQ 691 Mark
Sodium ethoxide is a specific reagent for
Answerc
(c) $C{H_3} - C{H_2} - C{H_2} - Br\mathop {}\limits_{{\rm{}}} $ $ \xrightarrow[C_2H_5ONa]{Dehydro halogenati on } $ $C{H_3} - CH = C{H_2} + HBr$
View full question & answer→MCQ 701 Mark
Which of the following has highest knocking
Answerc
(c) Straight chain olefins has highest knocking.
View full question & answer→MCQ 711 Mark
Addition of bromine to $1, 3-$butadiene gives
- A
$1, 2 $ addition product only
- B
$1, 4$ addition product only
- ✓
Both $1, 2$ and $1, 4$ addition products
- D
AnswerCorrect option: C. Both $1, 2$ and $1, 4$ addition products
c
$1,3$-butadiene accompanies the bromine molecule to form two products.
They are $1,2$-add products and $1,4$-surplus products.
At low temperatures, the $1,2$-pair is predominant but at higher temperatures, the $1,4$-pair is predominant. Products $A$ and $B$ will be on this basis.

View full question & answer→MCQ 721 Mark
How can ethene be produced from ethanol
AnswerCorrect option: C. By dehydration with conc. ${H_2}S{O_4}$ at ${170\,^o}C$
c
When ethanol is heated in presence of conc. $H _2 SO _4$, dehydration takes place to give ethylene.
The reaction of ethene with steam to form ethanol can be reversed. This allows ethanol to be converted into ethene. This is called a dehydration reaction.
$\underset{Ethanol}{C _2 H _5 OH} \xrightarrow[160^{\circ}-170^{\circ} C]{Conc. H _2 SO _4} \underset{Ethene}{CH _2= CH _2}+ \underset{Water}{H _2 O}$
View full question & answer→MCQ 731 Mark
Isopropyl alcohol is obtained by reacting which of the following alkenes with conc. ${H_2}S{O_4}$ and ${H_2}O$
Answerb
(b) $\mathop {C{H_3} - CH = C{H_2}}\limits_{} + {H_2}O \xrightarrow[Markownikoff's \,rule]{Conc.H_2 SO_4} \mathop {}\limits_{{\rm{}}} \mathop {C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{OH} } - C{H_3}}\limits_{{\rm{Isopropyl}}\,{\rm{\,alcohol}}} $
View full question & answer→MCQ 741 Mark
When 2-bromobutane reacts with alcoholic $KOH$, the reaction is called
Answerd
(d) $C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,}\limits_{Br\,} } - C{H_2} - C{H_3} \xrightarrow{alc.KOH} \mathop {C{H_3}CH = CHC{H_3}}\limits_{{\rm{2 - butene}}} $
The reaction is dehydrohalogenation.
View full question & answer→MCQ 751 Mark
$1, 3-$butadiene reacts with ethylene to form
- A
- B
- ✓
- D
$2, 3$ dimethyl butane
Answerc
the addition of ethene to $1,3$-butadiene to give cyclohexene.

View full question & answer→MCQ 761 Mark
Ethylene reacts with ozone gas to form the compound
- ✓
$HCHO$
- B
${C_2}{H_5}OH$
- C
- D
$C{H_3}CHO$
AnswerCorrect option: A. $HCHO$
a
(a)

View full question & answer→MCQ 771 Mark
A mixture of $1-$chloropropane and $2-$chloropropane when treated with alcoholic $KOH$ gives
- ✓
$1-$propene
- B
$2-$propene
- C
- D
AnswerCorrect option: A. $1-$propene
a
(a) $C{H_3}C{H_2}C{H_2}Cl + KOH \to $$C{H_3} - CH = C{H_2} + KCl + {H_2}O$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,\,} \\
{\,Cl\,\,\,\,}
\end{array}$ ${ + KOH \to C{H_3} - CH = C{H_2} + KCl + {H_2}O}$
View full question & answer→MCQ 781 Mark
The compound formed by passing ethylene gas into cold alkaline solution of $KMn{O_4}$ is
Answerd
(d) $\mathop {C{H_2} = C{H_2}}\limits_{{\rm{Ethene}}} \xrightarrow{Cold.\,alk \,KMnO_4} \mathop {\mathop {\mathop {C{H_2}}\limits_{|\,\,\,\,\,\,} }\limits_{OH} - \mathop {\mathop {C{H_2}}\limits_{|\,\,\,\,\,\,\,} }\limits_{OH\,} }\limits_{{\rm{Ethylene}}\,{\rm{glycol}}} $
View full question & answer→MCQ 791 Mark
When ethene is heated at ${400\,^o}C$ under high pressure, the product is/are
- A
Carbon and ${H_2}$
- ✓
- C
Acetylene and ${H_2}$
- D
Answerb
(b) $\mathop {n\,(C{H_2} = C{H_2})}\limits_{{\rm{(ethylene)}}} \xrightarrow[highpressure]{400\,^oC} \mathop {}\limits_{{\rm{}}} \,\,\mathop {{{( - C{H_2} - C{H_2} - )}_n}}\limits_{{\rm{(polyethylene)}}} $
View full question & answer→MCQ 801 Mark
Which decolorize aqueous bromine and gives white fumes of $HCl$ on reaction with $PC{l_5}$
- A
$C{H_3}COC{H_2}CH = C{H_2}$
- B
$C{H_3}C{H_2}C{H_2}C{H_2}C{H_3}$
- ✓
$C{H_3}CH = CHC{H_2}C{H_2}OH$
- D
$C{H_3}OC{H_2}C{H_2}C{H_2}C{H_2}OH$
AnswerCorrect option: C. $C{H_3}CH = CHC{H_2}C{H_2}OH$
c
$CH _3- CH = CH - CH _2- CH _2- OH + PCl _5 \rightarrow K _3 C - CH = CH - CH _2-CH _2- Cl + MCl + POCl _3$
$\downarrow Br _2 \mid H _2 O$
Colour decolorises due to the presence of double bond.
View full question & answer→MCQ 811 Mark
What product is formed when $1-$chlorobutane react with alcoholic $KOH$
- ✓
$1-$butene
- B
$2-$butene
- C
$1-$butanol
- D
$2-$butanol
AnswerCorrect option: A. $1-$butene
a
(a) $ClC{H_2} - C{H_2} - C{H_2} - C{H_3}$ $\xrightarrow{alc.KOH}$ $\mathop {C{H_2} = CH - C{H_2} - C{H_3}}\limits_{{\rm{1}} - {\rm{butene}}} $
View full question & answer→MCQ 821 Mark
The olefin which on ozonolysis gives $C{H_3}C{H_2}CHO$ and $C{H_3}CHO$ is
- A
$1-$butene
- B
$2-$butene
- C
$1-$pentene
- ✓
$2-$pentene
AnswerCorrect option: D. $2-$pentene
d
(d) $C{H_3}C{H_2}CH = CHC{H_3} \xrightarrow[Zn/H_2O]{O_3} \mathop {}\limits_{} \mathop {C{H_3}C{H_2}CHO}\limits_{{\rm{Propanal}}} + \mathop {CHOC{H_3}}\limits_{{\rm{Ethanal}}} $
View full question & answer→MCQ 831 Mark
Bond length between carbon-carbon in ethylene molecule is......$ \mathop A\limits^o $
- A
$1.54$
- ✓
$1.35$
- C
$1.19$
- D
$2.4$
AnswerCorrect option: B. $1.35$
b
A typical carbon-carbon single bond has a length of $154\, pm$, while a typical double bond and triple bond are $134\, pm$ and $120\, pm$, respectively.

View full question & answer→MCQ 841 Mark
When ethene reacts with bromine, it forms
- A
- ✓
- C
$1 $ bromopropane
- D
$1,2-$dichloroethene
Answerb
The bromine loses its original red-brown colour to give a colourless liquid. In the case of the reaction with ethene,
$1,2$-dibromoethane is formed,also know as ethylene dibromide. This decolourisation of bromine is often used as a test for a carbon-carbon double bond.
View full question & answer→MCQ 851 Mark
Answerb
(b)Paraffins or alkanes are non-polar compounds. Hence soluble in benzene.
View full question & answer→MCQ 861 Mark
Addition of $HCl$ to propene in presence of peroxides gives
- A
$1-$Chloropropane
- ✓
$2-$Chloropropane
- C
$3-$Chloropropane
- D
AnswerCorrect option: B. $2-$Chloropropane
b
(b) $C{H_3} - CH = C{H_2} + HCl \xrightarrow{peroxide} \begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
| \\
{\,\,\,Cl}
\end{array}$
Peroxide rule is applicable only to $HBr$.
View full question & answer→MCQ 871 Mark
The name of the product obtained by the addition of $HI$ to propene in presence of peroxide catalyst is
- A
- B
$2-$Iodopropane
- C
$3-$Iodopropane
- ✓
$1-$Iodopropane
AnswerCorrect option: D. $1-$Iodopropane
d
$C H_{3}-C H=C H_{2}+H I \stackrel{\text { Peroxide }}{\longrightarrow} C H_{3}-C H_{2}-C H_{2} I$
View full question & answer→MCQ 881 Mark
In the reaction ${C_2}{H_5}CH = C{H_2} + H - X \to $ Product. What is the product
- A
${C_2}{H_5} - C{H_3}$
- B
${C_2}{H_5}C{H_2} - C{H_2}X$
- ✓
${C_2}{H_5} - CHX - C{H_3}$
- D
$C{H_3} - C{H_2}X - CH = C{H_2}$
AnswerCorrect option: C. ${C_2}{H_5} - CHX - C{H_3}$
c
$C _2 H _5 CH = CH _2+ H - X \rightarrow C _2 H _5- CHX - CH _3$
When halide react with $1$ butene then tere will be a two product is possible.
$1.$ $C _2 H _5- CHX - CH _3$
$2.$ $C _2 H _5- CH _2- CHX_3$
But $90\, \%$ of the product is $C _2 H _5- CHX - CH _3$
And $10\, \%$ is $C _2 H _5- CH _2- CHX_3$.
Therefore our answer is Option $C$.
View full question & answer→MCQ 891 Mark
Alkene can be prepared from alkyl halide by the following reagent $R - X + N{u^ - } \to {\rm{Alkene}} + NuH$
- ✓
Alc. $KOH$ + heat
- B
Aq. $KOH $ + cold water
- C
$NaOH$
- D
$LiOH$
AnswerCorrect option: A. Alc. $KOH$ + heat
a
When heated with strong bases, alkyl halides typically undergo a $1,2$-elimination reactions to generate alkenes. Typical bases are $KOH$ in the alcohol as solvent.
View full question & answer→MCQ 901 Mark
$2-$chlorobutane is heated with alcoholic $NaOH$, the product formed in larger amount is
- A
$1-$Butene
- B
$1-$Butyne
- ✓
$2-$Butene
- D
AnswerCorrect option: C. $2-$Butene
c
(c) $C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{H\,\,\,} } - \mathop {CH}\limits_{\mathop {|\,\,\,\,}\limits_{Cl\,\,} } - \mathop {C{H_2}}\limits_{\mathop {|\,\,\,\,\,\,\,\,}\limits_{H\,\,\,\,\,} } \mathop {} $ $\xrightarrow[alc.NaOH] {-HCL} $ $C{H_3}CH = CH - C{H_3}$
View full question & answer→MCQ 911 Mark
Ethylene has high b.p. and high vapour pressure at ${100\,^o}C$ and does not dissolve in water. Hence ethylene is separated by this method
Answerc
Steam Distillation also know as vapour Distillation:- This technique is used for separating substances which are immiscible with water, volatile in steam and having high vapour pressure at the boiling temperature of water. It is also used for purifying liquids which decompose at their normal boiling points.
Therefore, Ethylene has high $b.p.$ and high vapour pressure at $100^{\circ} C$ and does not dissolve in water. Hence, ethylene is separated by thi vapour distillation method.
View full question & answer→MCQ 921 Mark
The compound most likely to decolourize a solution of potassium permanganate is
- A
$C{H_3}C{H_3}$
- B
- ✓
$C{H_3}CH = CHC{H_2}C{H_3}$
- D
$\mathop {\mathop {\mathop {\mathop {C{H_3} - C - C{H_3}}\limits^| }\limits^{\,\,\,\,\,\,C{H_3}} }\limits_| }\limits_{\,\,\,\,\,C{H_3}} $
AnswerCorrect option: C. $C{H_3}CH = CHC{H_2}C{H_3}$
c
(c)$C{H_3} - CH = CH - C{H_2} - C{H_3}$ it decolourizes $KMn{O_4}$ solution because double bond is present.
View full question & answer→MCQ 931 Mark
The product of reaction between propene and $HBr$ in the presence of a peroxide is
AnswerCorrect option: A. $C{H_3} - C{H_2} - C{H_2}Br$
a
(a) $C{H_3} - CH = C{H_2} + \mathop {HBr}\limits^{\,\,\,} \xrightarrow{peroxide} C{H_3} - C{H_2} - C{H_2} - Br$
View full question & answer→MCQ 941 Mark
Position of double bond in an organic compound is determined by
Answera
(a) Ozonolysis is useful in locating the position of a double bond in an alkene. The double bond is obtained by joining the carbon atoms of the two carbonyl compounds. For example
Let the product of ozonolysis be two molecules of ethanal.
$\mathop {C{H_3} - \mathop C\limits^{\mathop |\limits^H } = O}\limits_{} + O = \mathop C\limits^{\mathop |\limits^H } - C{H_3} \to $$\mathop {C{H_3} - CH = CH - C{H_3}}\limits_{{\rm{2}} - {\rm{Butene}}} $
View full question & answer→MCQ 951 Mark
A gas decolourises Bayer's reagent but does not react with Tollen's reagent, this gas is
Answera
The correct answer is - Ethene $\left( C _2 H _4\right)$ gas. Also, But-$1$-yne and But-$2$-yne are known for the same reactions.
Ammonical silver nitrate solution is also known as Tollen's reagent in chemical reaction studies.
These gases are known to decolourize aqueous bromine water. They also form a white precipitate when they react with aqueous ammoniacal silver nitrate solution.
View full question & answer→MCQ 961 Mark
The molecular formula of the first member of the family of alkenynes and its name is given by the set
- A
$C_3H_2,$ alkene
- B
$C_5H_6,\, 1-$ penten$-3-$yne
- C
$C_6H_8, \,1-$hexen$-5-$yne
- ✓
$C_4H_4,$ butenyne
AnswerCorrect option: D. $C_4H_4,$ butenyne
d
Alkenynes contain a double bond and a triple bond. So, they must have at least four carbon atoms.
The first member of the family of alkenynes is butenyne. Its molecular formula is $C _4 H _4$.
View full question & answer→MCQ 971 Mark
Major product of above reaction is

View full question & answer→MCQ 981 Mark
$\xrightarrow[{hv}]{{NBS}}$ Product ;
Which product will not likely to form
Answerb
In presence of $NBS$ , Allylic/Benzylic substitution take place
View full question & answer→MCQ 991 Mark
(image) $\xrightarrow[CC{{l}_{4}}]{HCl}X\xrightarrow{Aq.NaOH}Y\xrightarrow[\Delta ]{Conc.{{H}_{3}}P{{O}_{4}}}Z$ Major product is

- A
$CH_3 -CH_2 -CH=CH_2$
- ✓
$CH_3 -CH=CH-CH_3$
- C
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_2}}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
- D
$CH_2 =CH-CH=CH_2$
AnswerCorrect option: B. $CH_3 -CH=CH-CH_3$
b

View full question & answer→MCQ 1001 Mark
Reactant $(A)$ can be

Answerd
Source of this carbocation can be $(a), (b)$ and $(c).$

View full question & answer→MCQ 1011 Mark
Major product of the reaction is

Answerc

View full question & answer→MCQ 1021 Mark
$\begin{array}{*{20}{c}}
{C{H_2} - C{O_2}K} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - C{O_2}K}
\end{array}\xrightarrow{{electrolysis}}\mathop {(A)}\limits_{\left( {major} \right)} $ (Kolbe electrolysis method)
Product $(A)$ of the reaction is
- A
$CH_3 - CH_3$
- ✓
$CH_2 = CH_2$
- C
$CH_3 -CH = CH_2$
- D
AnswerCorrect option: B. $CH_2 = CH_2$
b

View full question & answer→MCQ 1031 Mark
Product $(C)$ of the reaction is

Answerc

View full question & answer→MCQ 1041 Mark
Product $W$ is

Answerc

View full question & answer→MCQ 1051 Mark
Methyl vinyl ether, $H_2C = CH -OCH_3$, reacts with $Br_2 /CH_3OH$. If methanol is reacting as water would, and if this reaction follows a typical mechanism of electrophilic addition, what would be the expected product ?
Answerb

View full question & answer→MCQ 1061 Mark
$2, 4$ -hexadiyne $(C_6H_6)$ is allowed to react with $Li $ in $NH_3 (liq)$. The product obtained is treated with $1$ equivalent of $Cl_2$ in $CCl_4$. Which of the following constitutional isomers are possible products ?

- A
$I$ and $II$
- B
$II$ and $III$
- C
$I$ and $V$
- ✓
$I$ and $III$
AnswerCorrect option: D. $I$ and $III$
d
$(d) \,1,2$ and $1,4-$ addition take place.
View full question & answer→MCQ 1071 Mark
Trans-cyclohexane- $1,2$ -diol can be obtained by the reaction of cyclohexene with
AnswerCorrect option: C. peroxy formic acid / $H_3O^+$
c

View full question & answer→MCQ 1081 Mark
The major product formed during the reaction of $1$ -methyl cyclopentene with $CH_3CO_3H$ is
Answerc
$(c)$ Epoxide will form.
View full question & answer→MCQ 1091 Mark
.

Answerb

View full question & answer→MCQ 1101 Mark
Product $(P)$ is

Answerb
$(b)$ Alkoxymercuration-De-mercuration reaction
View full question & answer→MCQ 1111 Mark
What is the major product expected from the following reaction ?

Answerb
$(b)$ cis-diol will form (syn addition takes place)
View full question & answer→MCQ 1121 Mark
$C{H_3} - CH = C{H_2}\xrightarrow[{(low\,\,conc.)}]{{B{r_2}/hv}}(A)$ ; Product $(A)$ of the reaction is
- A
$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - Br}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
- ✓
$H_2C = CH - CH_2 -Br$
- C
$\begin{array}{*{20}{c}}
{C{H_3} - C = C{H_2}}\\
|\\
{\,\,\,Br}
\end{array}$
- D
$Br - CH_2 - CH_2 - CH_2 -Br$
AnswerCorrect option: B. $H_2C = CH - CH_2 -Br$
b
$(b)\, Br_2/hv$ (low cone.) (or) $N.B.S,$ Allylic free radical substitution reaction.
View full question & answer→MCQ 1131 Mark
Reagent $(A)$ in the reaction is

- ✓
$O_3 /Zn(H_2O)$
- B
$HIO_4$
- C
$CrO_3$
- D
Cold dil. $KMnO_4$
AnswerCorrect option: A. $O_3 /Zn(H_2O)$
a
$(a)$ Alkene will be cleaved by ozonolysis.
View full question & answer→MCQ 1141 Mark
Product of the reaction is

Answerb
$(b)$ cis-diol will form
View full question & answer→MCQ 1151 Mark
Which compound is a possible product from addition of $Br_2$ to $1$ -butene ?
Answerd
$(d)$ Anti-addition take place.
View full question & answer→MCQ 1161 Mark
Addition of $Br_2$ to cis- $2$ -butene would give a product which is
Answerb

View full question & answer→MCQ 1171 Mark
Addition of $Br_2$ to trans- $2$ -butene would give a product which is
Answerc

View full question & answer→MCQ 1181 Mark
Addition of $OsO_4$ to cyclopentene would give a product which is
Answerc

View full question & answer→MCQ 1191 Mark
Addition of $BH_3$ followed by $H_2O_2$ to trans- $2$ -butene would give a product which is
Answerb
$(b)$ Hydroboration - oxidation reaction is a syn-addition.
View full question & answer→MCQ 1201 Mark
Reagent $A$ may be

AnswerCorrect option: C. $Hg(OCOCH_3)_2.H_2O/NaBH_4 .NaOH$
c
$(c)$ Oxymercuration - Demercuration reaction addition of $H_2O$ molecule is according to Markovnikoff's rule
View full question & answer→MCQ 1211 Mark
The major product of the following reaction is
$C{H_3} - CH = C{H_2} + HBr\xrightarrow{{{{({C_6}{H_5}CO)}_2}{O_2}}}$
- ✓
$CH_3 -CH_2 -CH_2 -Br$
- B
$CH_3CH (Br)-CH_3$
- C
$BrCH_2 - CH = CH_2$
- D
AnswerCorrect option: A. $CH_3 -CH_2 -CH_2 -Br$
a
$(a)$ Anti-Markovnikoffs addition take place (Peroxide effect operates).
View full question & answer→MCQ 1221 Mark
Identify $(B)$

Answerb

View full question & answer→MCQ 1231 Mark
Propene $CH_3CH = CH_2$ can be converted into $1$ -propanol by oxidation. Indicate which sets of reagents amongst the following is ideal to effect the above conversion ?
AnswerCorrect option: C. $B_2H_6$ and alk. $H_2O_2$
c
$(c)$ Hydroboration-oxidation reaction.
View full question & answer→MCQ 1241 Mark
The principal organic product formed in the reaction given below is
$C{H_2} = CH{(C{H_2})_8}COOH + HBr\xrightarrow{{peroxide}}....$
AnswerCorrect option: C. $CH_2BrCH_2 (CH_2)_8COOH$
c
$(c)$ Anti-Markovnikoffs addition take place.
View full question & answer→MCQ 1251 Mark
Which of the following alkene on catalytic hydrogenation given cis and trans- isomer?
Answerd

View full question & answer→MCQ 1261 Mark
In the reaction of hydrogen bromide with an alkene (in the absence of peroxides), the first step of the reaction is the ................. to the alkene
- A
fast addition of an electrophilic
- ✓
slow addition of an electrophile
- C
fast addition of a nucleophilic
- D
slow addition of a nucleophile
AnswerCorrect option: B. slow addition of an electrophile
b
$(b)$ Formation of carbocation is the rate determining step.
View full question & answer→MCQ 1271 Mark
Which of the following alcohols cannot be prepared from hydration of an alkene?
Answerd
$(d)$ Corresponding alkene is not possible.
View full question & answer→MCQ 1281 Mark
Which of the species shown below is the most stable form of the intermediate in the electrophilic addition of $Cl_2$ in water to cyclohexene to form a halohydrin ?
Answerd
$(d)$ Non-classical carbocation will form.
View full question & answer→MCQ 1291 Mark
The reaction, $(CH_3)_2C = CH_2 + B{{r}^{\centerdot }} \to (CH_3)_2 \overset{\centerdot }{\mathop{C}}\,- CH_2Br$
is an example of a/an ................ step in a radical chain reaction.
Answerc
$(c)$ Attack of free radical on alkene is an propagation step.
View full question & answer→MCQ 1301 Mark
Which of the following most accurately describes the first step in the reaction of hydrogen chloride with $1-$ butene ?
Answerb
$(b)$ Attack of alkene take place of $H - Cl$
View full question & answer→MCQ 1311 Mark
Which of the following best describes the flow of electrons in the acid-catalyzed dimerization of $(CH_3)_2C = CH_2$ ?
Answera
$(a)$ Carbocation formed will attacked by alkene.
View full question & answer→MCQ 1321 Mark
Hydroboration of $1$- methylcyclopentene using $B_2D_6$ , followed by treatment with alkaline hydrogen peroxide, gives
Answera
$(a)$ Hydroboration-oxidation take place (syn addition).
View full question & answer→MCQ 1331 Mark
Product $(B)$ of the reaction is

Answerb

View full question & answer→MCQ 1341 Mark
In catalytic reduction of hydrocarbons which catalyst is mostly used
- ✓
$Pt /Ni$
- B
$Pd$
- C
$Si{O_2}$
- D
AnswerCorrect option: A. $Pt /Ni$
a
(a) $Pt./Ni$ is used in catalytic reduction of hydrocarbon.
View full question & answer→MCQ 1351 Mark
Gasoline is obtained from crude petroleum oil by its
Answera
(a) Fractional distillation is used because the difference between the boiling point of different component is less.
View full question & answer→MCQ 1361 Mark
Which of the following does not give alkane
AnswerCorrect option: D. Reaction of ethyl chloride with alco. $KOH$
d
(d) $C{H_3} - C{H_2} - Cl + \mathop {KOH}\limits_{{\rm{(alc}}{\rm{.)}}} \to \mathop {C{H_2} = C{H_2}}\limits_{{\rm{Ethene}}} + KCl + {H_2}O$
In presence of alc. $KOH$ dehydrohalogenation occur and alkene is formed.
View full question & answer→MCQ 1371 Mark
$LPG$ is a mixture of
- A
${C_6}{H_{12}} + {C_6}{H_6}$
- ✓
${C_4}{H_{10}} + {C_3}{H_8}$
- C
${C_2}{H_4} + {C_2}{H_2}$
- D
${C_2}{H_4} + C{H_4}$
AnswerCorrect option: B. ${C_4}{H_{10}} + {C_3}{H_8}$
b
(b) Liquefied petroleum gas is a mixture of ethane, propane and butane. The main component is butane.
View full question & answer→MCQ 1381 Mark
Carbon black, which is used in making printer's ink, is obtained by decomposition of
Answerd
(d) $C{{H}_{4}}+{{O}_{2}}\underset{\begin{smallmatrix}
\text{Limited} \\
\text{supply }
\\
\text{of air}
\end{smallmatrix}}{\mathop{\xrightarrow{\Delta }}}\,C+2{{H}_{2}}O$
It contains $98-99\%$ carbon. It is used in making black ink, paints and shoe polishes.
View full question & answer→MCQ 1391 Mark
The addition of tetraethyl lead to petrol
- A
- ✓
- C
May raise or lower the octane number
- D
Has no effect on octane number
Answerb
(b)Tetraethyl lead is anti-knocking agent it increases the octane no. of the fuel.
View full question & answer→MCQ 1401 Mark
Knocking sound occurs in engine when fuel
- A
- ✓
- C
- D
Is mixed with machine oil
Answerb
(b)Knocking - Sudden and irregular burning of the fuel mixture causing jerks against the piston and gives rise to violent sound. This is known as knocking.
View full question & answer→MCQ 1411 Mark
Petroleum is mainly a mixture of
Answera
Petroleum is a mixture of a very large number of different hydrocarbons; the most commonly found molecules are alkanes (paraffins), cycloalkanes (naphthenes), aromatic hydrocarbons, or more complicated chemicals like asphaltenes.... They are the petroleum gases.
View full question & answer→MCQ 1421 Mark
Aqueous solution of the following compound on electrolysis gives ethane
Answerc
(c) $\mathop {2C{H_3}COOK}\limits_{{\rm{Potassium acetate}}} + 2{H_2}O\,\, \xrightarrow{Electrolysis} \,\,\mathop {C{H_3} - C{H_3} + 2C{O_2}}\limits_{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{Anode}}} + \mathop {2KOH + {H_2}}\limits_{\,\,\,\,\,\,\,\,\,\,\,\,{\rm{Cathode}}} $
View full question & answer→MCQ 1431 Mark
Which of the following does not decolourise bromine solution in carbon disulphide
Answerc
(c)Ethane does not decolourise bromine solution because it is a saturated compound.
View full question & answer→MCQ 1441 Mark
Anhydrous sodium acetate on heating with sodalime gives
Answerb
(b) $\mathop {C{H_3}COONa}\limits_{{\rm{Sodium acetate}}} + NaOH \xrightarrow{CaO} \mathop {C{H_4}}\limits_{{\rm{Methane}}} + N{a_2}C{O_3}$
View full question & answer→MCQ 1451 Mark
- A
$CO + C{O_2}$
- B
$CO + {N_2}$
- ✓
$CO + {H_2}$
- D
$CO + {N_2} + {H_2}$
AnswerCorrect option: C. $CO + {H_2}$
c
The mixture of carbon monoxide $( CO )$ and hydrogen $\left( H _2\right)$ is called water gas.
Syn gas is a mixture of $CO , CO _2$ and $H _2$.
Producer gas is a mixture of flammable gases (principally carbon monoxide and hydrogen) and nonflammable gases (mainly nitrogen and carbon dioxide).
Semi-water gas is a mixture of water gas and producer gas made by passing a mixture of air and steam through heated coke.
View full question & answer→MCQ 1461 Mark
A sample of gasoline contains $81\%$ iso-octane and $19\%$ $n-$ heptane. Its octane number will be
Answerb
(b) Octane number is related to the percentage of iso-octane since iso-octane is $81\%$ hence octane number is $81$.
View full question & answer→MCQ 1471 Mark
The natural petroleum contains
- A
- B
Cyclic saturated hydrocarbons
- C
- ✓
Answerd
The hydrocarbons in crude oil are mostly alkanes (paraffins), cycloalkanes (naphthenes) and various aromatic hydrocarbons while the other organic compounds contain nitrogen, oxygen and sulfur, and trace amounts of metals such as iron, nickel, copper and vanadium.
View full question & answer→MCQ 1481 Mark
The preparation of ethane by electrolysis of aqueous solution of potassium acetate is called as
- A
- B
Sabatier-Senderen's reaction
- ✓
- D
Answerc
(c) $2C{H_3}COOK + 2{H_2}O\xrightarrow{{{\text{Electrolysis}}}}$ $\underbrace {2C{O_2} + C{H_3} - C{H_3}}_{Anode} + \underbrace {2KOH}_{cathode} + {H_2}$
View full question & answer→MCQ 1491 Mark
As the number of carbon atoms in a chain increases the boiling point of alkanes
Answera
(a) Boiling point of alkanes increases with the number of carbon atoms because surface area increases which increases the Vander Waal forces.
View full question & answer→MCQ 1501 Mark
In the fractional distillation of crude petroleum
- A
Petrol condenses at the bottom of the column
- B
The gases condense at the top of the column
- ✓
High boiling constituents condense at the bottom of the column
- D
High boiling constituents condense at the top of the column
AnswerCorrect option: C. High boiling constituents condense at the bottom of the column
View full question & answer→MCQ 1511 Mark
Which of the following is not an endothermic reaction
- A
- B
- ✓
- D
Change of chlorine molecule into chlorine atoms.
Answerc
(c)The enthalpy of combustion i.e., $\Delta H$ is always negative. It means combustion is an exothermic reaction.
View full question & answer→MCQ 1521 Mark
- A
- ✓
The gaseous constituents of petroleum
- C
The mixture of uncondensed gases produced in the distillation of crude oil
- D
The mixture of the residue and gas oil obtained in the distillation of crude oil
AnswerCorrect option: B. The gaseous constituents of petroleum
b
Gasoline, also spelled gasolene, also called gas or petrol, mixture of volatile, flammable liquid hydrocarbons derived from petroleum and used as fuel for internal-combustion engines. It is also used as a solvent for oils and fats.
View full question & answer→MCQ 1531 Mark
In the process of cracking
- A
Organic compounds decompose into their constituent elements
- B
Hydrocarbons decompose into carbon and hydrogen
- ✓
High molecular weight organic compounds decompose to give low molecular weight organic compounds
- D
Hydrocarbons yield alkyl radicals and hydrogen
AnswerCorrect option: C. High molecular weight organic compounds decompose to give low molecular weight organic compounds
View full question & answer→MCQ 1541 Mark
Octane number has $0$ value for
- A
- B
$n-$ hexane
- ✓
$n-$ heptane
- D
AnswerCorrect option: C. $n-$ heptane
c
$n$-heptane is defined as the zero point of the octane rating scale. $2,2,4-$Trimethylpentane has an octane rating of $100$ , whereas $n$-heptane has an octane rating of $0$. The octane number is based on an arbitrary scale which is a measure of its ability to resist knocking, as it burns on combustion.
View full question & answer→MCQ 1551 Mark
Dry distillation of sodium propanoate with sodalime gives
Answerc
(c) $C{H_3}C{H_2}COONa + NaOH \,\,\, \xrightarrow{CaO} {C_2}{H_6} + N{a_2}C{O_3}$
View full question & answer→MCQ 1561 Mark
Which of the following fractions of petroleum refining contains kerosene ? (Boiling ranges in $^oC$ are given below)
- A
$40 - 80$
- B
$80 - 200$
- ✓
$200 - 300$
- D
Above $300$
AnswerCorrect option: C. $200 - 300$
c
The fraction of petroleum refining containing Useful hydrocarbons like kerosene is found between a temperature $200-300^{\circ} C$. These products are highly volatile, have small molecules, have low boiling points, flow easily, and ignite easily.
View full question & answer→MCQ 1571 Mark
Methane can be prepared by
Answerb
(b)$C{H_3}COONa + NaOH \xrightarrow{CaO} C{H_4} + N{a_2}C{O_3}$
View full question & answer→MCQ 1581 Mark
Which does not react with chlorine in dark
- A
${C_2}{H_4}$
- B
${C_2}{H_2}$
- ✓
$C{H_4}$
- D
$C{H_3}CHO$
AnswerCorrect option: C. $C{H_4}$
c
$Cl _2$ fissure into the atoms of of Chlorine. Chlorine atoms contact to Methane and they led to the formation of $HCl$ and the radicals of Methane. So, methane does not react with Chlorine in dark.
View full question & answer→MCQ 1591 Mark
Which of the following method can be used for the preparation of methane
- A
- B
- ✓
Reduction of alkyl halide
- D
AnswerCorrect option: C. Reduction of alkyl halide
c
(c) $C{H_3} - Cl + 2H \xrightarrow{Zn/HCl} C{H_4} + HCl$
View full question & answer→MCQ 1601 Mark
Which hydrocarbon will be most stable
Answerd
Longer chain alkanes are typically more stable (relatively, based on the number of carbons) compared with a shorter chain alkane. More branched compounds are typically more stable than straight chain alkanes with the same number of atoms.
View full question & answer→MCQ 1611 Mark
When sodium reacts with ethyl iodide, which of the following hydrocarbons is produced
Answerc
(c) Wurtz reaction
${C_2}{H_5} - I + 2Na + I - {C_2}{H_5} \xrightarrow[Ether]{Dry} \mathop {}\limits_{{\rm{Ether}}} \mathop {{C_2}{H_5} - {C_2}{H_5} + 2NaI}\limits_{{\rm{Butane}}} $
View full question & answer→MCQ 1621 Mark
$C{H_3}MgI$ will give methane with
AnswerCorrect option: D. Both $(a)$ and $(b)$
d
(d) $C{H_3}MgI + C{H_3} - C{H_2} - N{H_2} \to \,\,C{H_4} + C{H_3}C{H_2}NHMgI$
$C{H_3}MgI + {C_2}{H_5}OH \to C{H_4} + {C_2}{H_5}OMgI$
Alkyl group of Grignard’s reagent is involved in the formation of alkane.
View full question & answer→MCQ 1631 Mark
Propane$-1-$ol can be prepared from propene by its reaction with
AnswerCorrect option: C. ${B_2}{H_6}/NaOH,{H_2}{O_2}$
View full question & answer→MCQ 1641 Mark
Successive alkanes differ by
- ✓
$>C{H_2}$
- B
$>CH$
- C
$ - \,\,C{H_3}$
- D
${C_2}{H_4}$
AnswerCorrect option: A. $>C{H_2}$
a
successive members differ in mass by an extra methylene bridge $\left(- CH _2-\right.$ unit) inserted in the chain.
View full question & answer→MCQ 1651 Mark
Methane and ethane both can be prepared in one step by which of the following compound
- A
${C_2}{H_4}$
- B
$C{H_3}O$
- ✓
$C{H_3}Br$
- D
$C{H_3}C{H_2}OH$
AnswerCorrect option: C. $C{H_3}Br$
c
(c) $C{H_3}Br + {H_2}\,\, \xrightarrow{LiAlH4} CH_4 $ (methane) $ \xrightarrow{Na} \,\,C{H_3} - C{H_3}$ (Ethane)
View full question & answer→MCQ 1661 Mark
Photochemical chlorination of alkane is initiated by a process of
Answerd
(d) Photochemical chlorination of alkane take place by free radical mechanism which are possible by Homolysis of $C -C$ bond
$C{l_2} \xrightarrow{hv} C{l^ \bullet } + C{l^ \bullet }$
$C{H_3} - C{H_3} + C{l^ \bullet } \to C{H_3}C{l^ \bullet } + \dot C{H_3}$
View full question & answer→MCQ 1671 Mark
A petroleum fraction having boiling range $70-200\,^oC$ and containing $6-10$ carbon atoms per molecule is called
View full question & answer→MCQ 1681 Mark
Producer gas is a mixture of
- ✓
$CO$ and ${N_2}$
- B
$C{O_2}$ and ${H_2}$
- C
${N_2}$ and ${O_2}$
- D
$C{H_4}$ and ${N_2}$
AnswerCorrect option: A. $CO$ and ${N_2}$
a
(a) Producer gas -$ CO\,{\rm{and \,}}{N_2}$
View full question & answer→MCQ 1691 Mark
The highest boiling point is expected for
AnswerCorrect option: C. $n - $octane
c
(c) Among alkanes, boiling point increase with increasing molecular weight. For isomeric alkanes straight chain alkanes have higher boiling point than the branched alkanes.
View full question & answer→MCQ 1701 Mark
Which of the following is a good conductor of heat of electricity
Answerb
(b) Graphite is a good conductor of heat of electricity.
View full question & answer→MCQ 1711 Mark
Which one of the following has the minimum boiling point
- A
$1-$Butene
- B
$1-$Butyne
- C
$n-$Butane
- ✓
Answerd
(d)Among the isomeric alkanes, the normal isomer has a higher boiling point than the branched chain isomer. The greater the branching of the chain, the lower is the boiling point. The $n-$alkane have larger surface area in comparison to branched chain isomer (as the shape approaches that of a sphere in the branched chain isomers). Thus, intermolecular forces are weaker in branched chain isomers, there fore they have lower point in comparision to straight chain isomers.
View full question & answer→MCQ 1721 Mark
The octane number of a sample of petrol is $40$. It means that its knocking property is equal to the mixture of
- A
$40\%$ $n-$ heptane + $60\%$ iso-octane
- B
$40\%$ petrol + $60\%$ iso-octane
- ✓
$60\%$ $n-$ heptane + $40\%$ iso-octane
- D
$60\%$ petrol + $40\%$ iso-octane
AnswerCorrect option: C. $60\%$ $n-$ heptane + $40\%$ iso-octane
c
(c) Octane number of fuel is the percentage of iso- octane in mixture.
View full question & answer→MCQ 1731 Mark
When ethyl alcohol is heated with red phosphorus and $HI$, then which of the following is formed
- ✓
${C_2}{H_6}$
- B
$C{H_4}$
- C
${C_3}{H_8}$
- D
${C_2}{H_4}$
AnswerCorrect option: A. ${C_2}{H_6}$
a
(a) $\mathop {C{H_3}C{H_2} - OH}\limits_{{\text{Ethyl}}\,{\text{alcohol}}} + 2HI\xrightarrow{{Red\,P}}\mathop {C{H_3} - C{H_3}}\limits_{{\text{Ethane}}} + {H_2}O + {I_2}$
View full question & answer→MCQ 1741 Mark
In the Fischer-Tropsch synthesis of petrol..... and ..... are used as the raw materials
- ✓
${H_2};CO$
- B
$C{H_4};{H_2}$
- C
$C{H_4};C{H_3}OH$
- D
$C{H_3}OH;CO$
AnswerCorrect option: A. ${H_2};CO$
a
(a) Fischer-Tropsch process -
$\underbrace {CO + {H_2}}_{{\text{Water}}\,{\text{gas}}} + \mathop {{H_2}}\limits_{{\text{Excess}}} \mathop {\xrightarrow{{{\text{CO}}\,\,{\text{or}}\,{\text{Ni}}}}}\limits_{{\text{heat}}} \mathop {Mixure\,of\,hydrocarbons\,}\limits_{(Petrol)} + {H_2}O$
View full question & answer→MCQ 1751 Mark
On cracking petrol, we get
AnswerCorrect option: C. Both $(a)$ and $(b)$
c
(c) On cracking petrol gives smaller hydrocarbons like $CH_4$, $C_3H_6$.
View full question & answer→MCQ 1761 Mark
Cetane is a compound which has very good ignition property. Chemically it is
AnswerCorrect option: A. $C{H_3}{(C{H_2})_{14}}C{H_3}$
a
(a) Cetane is chemically hexadecane i.e,
$C{H_3}{(C{H_2})_{14}}C{H_3}$.
View full question & answer→MCQ 1771 Mark
The number of secondary hydrogens in $2, 2-$ dimethyl butane is
Answerd
(d) $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,H\,\,\,\,\,\,\,C{H_{3\,}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,|} \\
{{H_3}C - C - C - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,H\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{2,2\,\dim ethyl\,bu\tan e} $
View full question & answer→MCQ 1781 Mark
An alkane (molecular weight $72$) forms only one monochlorinated product. Its formula is
AnswerCorrect option: A. ${(C{H_3})_4}C$
a
(a) The alkane forms only one mono substituted product, it must have only one type of hydrogen atoms. there fore the alkane is $2, 2-$ dimethyl propane.
View full question & answer→MCQ 1791 Mark
The poisonous gas that comes out with petrol burning in a car is
- A
$C{H_4}$
- B
${C_2}{H_6}$
- C
$C{O_2}$
- ✓
$CO$
Answerd
(d) On petrol burning $CO$ comes out which is so much poisonous gas.
View full question & answer→MCQ 1801 Mark
$\mathop {{C_6}{H_{14}}}\limits_{n - hexane} \xrightarrow{{A{l_2}{O_3}/\Delta }}(A)\xrightarrow{{(CO + HCl)/AlC{l_3}}}(B)$
Select the incorrect statement among following
- A
Compound $'B'$ form silver mirror on reaction with $[Ag(NH_3)_2]OH$
- ✓
Molecularity of reaction during conversion from $'A'$ to $'B'$ is $'3'$
- C
Compound $'A'$ can also be synthesised by reaction of benzene diazonium chloride with $H_3PO_2$
- D
Compound $'B'$ give grey colour with aq. $HgCl_2$ solution
AnswerCorrect option: B. Molecularity of reaction during conversion from $'A'$ to $'B'$ is $'3'$
View full question & answer→MCQ 1811 Mark
Which has maximum $B.P.$ ?
View full question & answer→MCQ 1821 Mark
$CH_3Cl \to CH_4$
Above conversion can be achieved by
Answerd
$C{H_3}Cl\xrightarrow[{\operatorname{Re} d.}]{{Zn/{H^ \oplus }}}C{H_4}$
$C{H_3}Cl\xrightarrow[{\operatorname{Re} d.}]{{LiAl{H_4}}}C{H_4}$
$C{H_3}Cl\xrightarrow[\begin{subarray}{l}
Dry \\
ether
\end{subarray} ]{{Mg}}\mathop {\mathop C\limits^{.\,.} }\limits^\Theta {H_3}\mathop {Mg}\limits^ \oplus Cl\xrightarrow{{\mathop H\limits^ \oplus OR}}C{H_4}$
View full question & answer→MCQ 1831 Mark
Products ; Comment up on optical activity of products

- A
- ✓
- C
- D
Optically pure enantiomer
Answerb
Notice that the benzene ring is inert to these conditions; hydrogenation of benzene is discussed.

View full question & answer→MCQ 1841 Mark
Which of the following reactions do not represent the major product of given Birch reductions ?

- A
$(i), (iii), (vi)$
- ✓
$(iv), (vi), (vii)$
- C
$(iv), (v), (vi)$
- D
$(i), (ii), (v), (vii)$
AnswerCorrect option: B. $(iv), (vi), (vii)$
b

View full question & answer→MCQ 1851 Mark
When comparing the hydrogenation of benzene with that of a hypothetical $1, 3,
5-$ cyclohexatriene, benzene .................... than the cyclohexatriene.
- A
absorbs $152\, kJ /mol$ more heat
- B
gives off $152\, kJ/mol$ more heat
- C
absorbs $152\,kJ /mol$ less heat
- ✓
gives off $152\, kJ/mol$ less heat
AnswerCorrect option: D. gives off $152\, kJ/mol$ less heat
d
$(b)$ Benzene is aromatic therefore gives off $152 \,kJ/mol$ more heat.
View full question & answer→MCQ 1861 Mark
Which of the following ring compounds obeys Huckel's rule ?
- A
$C_4H_4^{-1}$
- B
$C_4H_4^{+1}$
- ✓
$C_4H_4^{-2}$
- D
$C_4H_4$
AnswerCorrect option: C. $C_4H_4^{-2}$
c

View full question & answer→MCQ 1871 Mark
Caliene, $C_7 H_6$ , is expected to be a fairly polar aromatic molecule. Which of the following resonance forms contributes to the greatest extent to wards the real structure (resonance hybrid) of the molecule ?
Answerd

View full question & answer→MCQ 1881 Mark
In the reaction given below, the major product formed is

Answerd
$(d)$ More activated ring undergo electrophilic aromatic substitution.
View full question & answer→MCQ 1891 Mark
Suggest the best reaction conditions for the synthesis shown below.

- A
$(1)\, HNO_3, H_2SO_2;$ then $(2)\, Br_2$
- B
$(1)\, Br_2;$ then $(2)\, HNO_3 , H_2SO_2$
- C
$(1)\, CH_3 Br, AlBr_3 ;$ then $(2) \,HNO_3 , H_2SO_3$
- ✓
$HNO_3 , H_2SO_2,$ then $(2)\, Br_2, FeBr_3$
AnswerCorrect option: D. $HNO_3 , H_2SO_2,$ then $(2)\, Br_2, FeBr_3$
d
$(d)$ Nitration following bromination.
View full question & answer→MCQ 1901 Mark
Which of the following benzene ring substituents is deactivating but orthopara directing ?
- ✓
$-N = O$
- B
$-OCH_3$
- C
$-COCH_3$
- D
$- NO_2$
AnswerCorrect option: A. $-N = O$
a
$(a)\, - \ddot{N} = O$ group is $+M$ and $ -M$
View full question & answer→MCQ 1911 Mark
Predict the product of the following reaction.

Answerc

View full question & answer→MCQ 1921 Mark
Which isomer of xylene can give three different monochloroderivatives ?
- A
$o-$ xylene
- ✓
$m-$ xylene
- C
$p-$ xylene
- D
xylene cannot give a monochloro derivative
AnswerCorrect option: B. $m-$ xylene
View full question & answer→MCQ 1931 Mark
The rate of $o-$ nitration of the above compounds, $(I)$ toluene, $(II)\, 2-D-$ toluene and $(III) \,2, 6-D_2$ -toluene is in the following order

- A
$I > II > III$
- B
$II > I > III$
- C
$III > I > II$
- ✓
The rate is the same for all the three compounds
AnswerCorrect option: D. The rate is the same for all the three compounds
View full question & answer→MCQ 1941 Mark
Which of the following is/are aromatic

- A
Only $a$
- B
$b, c$
- C
$a, b,c$
- ✓
Answerd
All of the following cyclic, plannar, conjugated compounds following Huckel rule.
View full question & answer→MCQ 1951 Mark
Identify the number of aromatic compounds

View full question & answer→MCQ 1961 Mark
Which of the following statement is wrong for the given molecule

AnswerCorrect option: B. This molecule has $6\pi$ delocalized electrons.
View full question & answer→MCQ 1971 Mark
$Ph - MgCl\xrightarrow{{Hydrolysis}}$ Product
Product will be
Answerb

View full question & answer→MCQ 1981 Mark
What is the major product of following reaction

View full question & answer→MCQ 1991 Mark
Aromaticity is present in
View full question & answer→MCQ 2001 Mark
Number of $\sigma $ and $\pi $ bonds in benzophenone is
- A
$24, 6$
- B
$24, 7$
- C
$25, 6$
- ✓
$25, 7$
AnswerCorrect option: D. $25, 7$
d

View full question & answer→MCQ 2011 Mark
In the following reaction ${C_6}{H_5}C{H_2}Br\xrightarrow[{(ii){H_3}{O^ + }}]{{(i)Mg.\,Ether}}X$
Product $X$ is
- ✓
$C_6H_5CH_3$
- B
$C_6H_5CH_2OH$
- C
$C_6H_5CH_2CH_2C_6H_5$
- D
$C_6H_5CH_2OCH_2C_6H_5$
AnswerCorrect option: A. $C_6H_5CH_3$
a
$C _6 H _5 CH _2 Br \stackrel{ Mg \text { Ether }}{\longrightarrow} \underset{Grignard\,\, Reagent}{C _6 H _5 CH _2 MgBr} \rightarrow C _6 H _5 CH _3+ Mg ( Br )( OH )$
View full question & answer→MCQ 2021 Mark
$\,$

View full question & answer→MCQ 2031 Mark
During mixed acid nitration of benzene Conc. $HNO_3$ behaves like
Answerb

View full question & answer→MCQ 2041 Mark
Which of the following does not give friedel-craft reaction ?
Answera
Aniline does give $FCR$ due to salt formation with $AlCl_3.$ Due to this nitrogen of aniline becomes strong $EWG.$
View full question & answer→MCQ 2051 Mark
The best method to introduce fluorine in benzene ring as a substituent is
- A
Fluorination by electrophilic substitution
- ✓
- C
- D
View full question & answer→MCQ 2061 Mark
$x$ is

View full question & answer→MCQ 2071 Mark
$Z$ is

View full question & answer→MCQ 2081 Mark
Which of the following reaction is not an example of addition reaction
View full question & answer→MCQ 2091 Mark
In which of the following $C-Cl$ bond length is minimum ?
View full question & answer→MCQ 2101 Mark
benzen + $CH_3-CH_2-CH_2-Cl$ $\xrightarrow{{AlC{l_3}}}$ the product
View full question & answer→MCQ 2111 Mark
Which is not formed in the given reaction

Answerb

View full question & answer→MCQ 2121 Mark
Which of the following is Aromatic
Answerd
cyclic Resonance presence with $6 \pi$ $\overline{\mathrm{es}}$ in Resonance $\therefore$ this is aromatic

View full question & answer→MCQ 2131 Mark
Which of the following undergo friedal craft reaction
Answerd
$-NO_2 , -CHO, NH_2$ If- group attached to benzene then friedal craft Reaction not possible
View full question & answer→MCQ 2141 Mark
$\begin{array}{*{20}{c}}
{C{H_2} - CH_2} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,\,\,Cl\,\,\,\,}
\end{array}$ $\xrightarrow[{(ii)NaN{H_2}}]{{(i)Alc.KOH}}A\xrightarrow{{\operatorname{Re} d\,hot\,Fe\,tube}}B$
Identify product $B$ in above reaction sequence
Answerb
$\begin{array}{*{20}{c}}
{C{H_2} - C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,} \\
{\,\,Cl\,\,\,\,\,\,\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{(ii)\,NaN{H_2}}]{{(i)\,Alc.\,KOH}}$ $HC \equiv CH\xrightarrow{{\operatorname{Re} d\,hote\,tube}}$ (figure)

View full question & answer→MCQ 2151 Mark
Which of the following reaction is called as wurtz- fittig reaction
View full question & answer→MCQ 2161 Mark
Chlorination of Benzene in the presence of sunlight gives
Answerb

View full question & answer→MCQ 2171 Mark
Which among the following statement is not correct for above reaction ?

AnswerCorrect option: B. Product $P$ is aromatic
View full question & answer→MCQ 2181 Mark
In which of the following compound electrophilic attacks at ortho and para positions:
View full question & answer→MCQ 2191 Mark
Which of the following species is not aromatic
View full question & answer→MCQ 2201 Mark
Which of the following species is not aromatic
View full question & answer→MCQ 2211 Mark
The total number of benzene derivatives with molecular formula $C_6H_3Cl_3$ is
Answerb
The total number of benzene derivatives with the molecular formula $\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{Cl}_{3}$ is 3 .

View full question & answer→MCQ 2221 Mark
Which of the following is aromatic compound ?
View full question & answer→MCQ 2231 Mark
benzene $ + \,C{H_2}C{l_2}\,\xrightarrow{{AlCl}}\,A$, $'A'$ is
Answerc
Correct option is ($C$ )

View full question & answer→MCQ 2241 Mark
Which of the following can not react with $NaHCO_3$
View full question & answer→MCQ 2251 Mark
How many products will be formed in above reaction ?

Answerb

View full question & answer→MCQ 2261 Mark
Product of the reacion is

Answera

View full question & answer→MCQ 2271 Mark
cis- $2$ -butene $\xrightarrow[{Peroxide}]{{HBr}}$ product ; Product of the reaction is
Answera
$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - \mathop C\limits^* H - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br}
\end{array}$ (racemic mixture)
View full question & answer→MCQ 2281 Mark
Rate of reaction towards reduction using $(H_2 /Pt)$

- ✓
$a > b$
- B
$a = b$
- C
$b > a$
- D
Reduction of given molecule is not possible
AnswerCorrect option: A. $a > b$
a
$(a)$ Less steric hinderance site will be attacked. Approach of $H_2$ is more hindered in $(b)$.
View full question & answer→MCQ 2291 Mark
Product is

Answerb
$(b)$ Oxidation take place i.e., epoxidation
View full question & answer→MCQ 2301 Mark
Major product of the given reaction is
$H_2C = CH - CH_2 - I \xrightarrow[CC{{l}_{4}}]{HI(excess)}$
- A
$\begin{matrix}
C{{H}_{3}}-CH-C{{H}_{2}} \\
\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,I\,\,\,\,\,\,\,\,\,\,\,I \\
\end{matrix}$
- ✓
$\begin{matrix}
C{{H}_{3}}-CH-C{{H}_{3}} \\
|\,\,\,\,\, \\
I\,\,\,\,\,\, \\
\end{matrix}$
- C
$CH_3 - CH_2 - CH_2 - I$
- D
$I - CH_2 - CdH_2 - CH_2 - I$
AnswerCorrect option: B. $\begin{matrix}
C{{H}_{3}}-CH-C{{H}_{3}} \\
|\,\,\,\,\, \\
I\,\,\,\,\,\, \\
\end{matrix}$
b
${H_2}C = CH - C{H_2} - I\xrightarrow[{M.Rule}]{{H - I}}$ $\mathop {\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2}} \\
{\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,I\,\,\,\,\,\,\,\,\,\,\,I\,}
\end{array}}\limits_{(unstable)} \xrightarrow{{( - {I_2})}}$ $C{H_3} - CH = C{H_2}\xrightarrow[{M.Rule}]{{H - I}}\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,} \\
{I\,\,\,\,}
\end{array}$
View full question & answer→MCQ 2311 Mark
Major product of the given reaction is

- A
- B
- ✓
- D
$\begin{matrix}
C{{H}_{3}}\,\,\, \\
|\,\,\,\,\,\,\,\,\,\, \\
{{H}_{2}}C=C-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}} \\
\end{matrix}$
Answerc

View full question & answer→MCQ 2321 Mark
Product $(P)$ is

Answerd

View full question & answer→MCQ 2331 Mark
Product $(A)$ of the reaction is

Answera

View full question & answer→MCQ 2341 Mark
Product $(A)$ is

Answerb

View full question & answer→MCQ 2351 Mark
Product $(Z)$ is

Answerc

View full question & answer→MCQ 2361 Mark
The reaction of propene with $HOCl$ proceeds via the addition of
AnswerCorrect option: B. $Cl^+$ in the first step
b

View full question & answer→MCQ 2371 Mark
Ozonolysis products of an olefin are $OHC-CHO$ and $OHC-CH_2-CH_2-CHO$, the olefin is
Answerc

View full question & answer→MCQ 2381 Mark
$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - C{H_3}\xrightarrow[{KOH}]{{Alc.}}\mathop X\limits_{\left( {{\text{major}}} \right)} \,;} \\
{\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\,$
$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - C{H_3}\xrightarrow[\Delta ]{{EtoNa}}\mathop {{\text{ }}Y}\limits_{\left( {{\text{major}}} \right)} } \\
{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} |{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,{\mkern 1mu} \,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \\
{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \mathop {{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,NM{e_3}\,\,\,\,\,\,\,{\mkern 1mu} }\limits_{\,\,\,\,\,\,\,\,\,\, \oplus \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} }
\end{array}{\mkern 1mu} $
Product $(X)$ and $(Y)$ respectively is
- A
$1-$ butene, trans $2-$ butene
- B
$1-$ butene, cis $-2-$ butene
- C
cis $-2-$ butene, $1-$ butene
- ✓
trans $2-$ butene, $1-$ butene
AnswerCorrect option: D. trans $2-$ butene, $1-$ butene
View full question & answer→MCQ 2391 Mark
Arrange the above in the decreasing order of reactivity towards $HBr$

- A
$a > b > c$
- ✓
$b > a > c$
- C
$b > c > a$
- D
$a > c > b$
AnswerCorrect option: B. $b > a > c$
b
$(b)$ Formation of carbocation is the rate determining step more the stable carbocation more is the reactivity toward $HBr$

View full question & answer→MCQ 2401 Mark
In which of the following reaction $CO_2$ gas will not be released ?
- A
$CH_2=CH-CH_3$ $\xrightarrow{{{O_3}/{H_2}O}}$
- B
- ✓
- D
$C{H_3} - C \equiv CH\,\xrightarrow[{(ii)\,{H_2}O}]{{(i)\,KMn{O_4} + KOH}}$
View full question & answer→MCQ 2411 Mark
Which of the following alkene is most stable
- A
$(CH_3)_3 C -CH = CH_2$
- B
$CH_2 = CH_2$
- ✓
$(CH_3)_2 C = CH_2$
- D
$CH_3 -CH = CH_2$
AnswerCorrect option: C. $(CH_3)_2 C = CH_2$
c

View full question & answer→MCQ 2421 Mark
Which of the following Alkane cannot be prepared by Hydrogenation of olefin
Answerd
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,\,\,\,C{H_3}}
\end{array} \to $ Neopentane cannot be prepared by Hydrogenation of olefin due to non availability of $\mathrm{H}$ that can be replaced and double bond can be placed between $2$ carbon atom
View full question & answer→MCQ 2431 Mark
Which reaction has the lowest $\Delta {{G}^{\begin{smallmatrix}
+ \\
+
\end{smallmatrix}}}$ or (Activation-Energy)?
Answerd

View full question & answer→MCQ 2441 Mark
Energy profile diagram for dehydration of $2$ -butanol using conc. $H_2SO_4$ is given below
Product $(b)$ of above reaction is

- A
$1$ -butene
- ✓
$cis-2$ -butene
- C
$trans-2$ -butene
- D
$iso$ -butene
AnswerCorrect option: B. $cis-2$ -butene
b

View full question & answer→MCQ 2451 Mark
How many alkene on catalytic hydrogenation given isopentane as a product ?
Answerb

View full question & answer→MCQ 2461 Mark
Which of the following would not rearrange to a more stable form ?
Answerc
is stable carbocation due to presence of $\sigma $ -resonance so it will not rearrange.

View full question & answer→MCQ 2471 Mark
Ethylene react with $Br_2$ give $1,2-$ Dibromoethane intermediate of reaction is
- A
$\begin{array}{*{20}{c}}
{C{H_2} - \mathop C\limits^ \oplus {H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
- ✓
- C
$Br - CH = \mathop C\limits^ \oplus H$
- D
View full question & answer→MCQ 2481 Mark
(Image) $\xrightarrow{{electrolysis}}$ Product is

AnswerCorrect option: B. $H - C \equiv C - H$
View full question & answer→MCQ 2491 Mark
The homologue of ethyne is
- A
${C_2}{H_4}$
- B
${C_2}{H_6}$
- C
${C_3}{H_8}$
- ✓
${C_3}{H_4}$
AnswerCorrect option: D. ${C_3}{H_4}$
d
(d)${C_2}{H_2}$ and ${C_3}{H_4}$ are homologue because they differ by $ - C{H_2}$ group. Both have triple bond in their molecule.
View full question & answer→MCQ 2501 Mark
When acetylene reacts with $HCl $ in the presence of $HgC{l_2}$, the product is
Answerc
(c) $CH \equiv CH + HCl\xrightarrow{{HgC{l_2}}}\mathop {C{H_2} = CH - Cl}\limits_{{\text{Vinyl chloride}}} $
View full question & answer→MCQ 2511 Mark
Propyne on polymerisation gives
Answera
(a)

View full question & answer→MCQ 2521 Mark
Which of the following catalyst is used in the polymerisation of $CH \equiv CH$ to ${C_6}{H_6}$
- ✓
$AlC{l_3}$
- B
$HgS{O_4}$
- C
$NbC{l_3}$
- D
$HCl$
AnswerCorrect option: A. $AlC{l_3}$
a
(a) $3CH \equiv CH\mathop {\xrightarrow{{{\text{Hot}}\,Cu\,{\text{tube}}}}}\limits_{AlC{l_3}} \,\,\,\,\,\begin{array}{*{20}{c}}
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,$

View full question & answer→MCQ 2531 Mark
$KMn{O_4}$ will oxidise acetylene to
Answerc
(c) $\mathop {\begin{array}{*{20}{c}}
{CH} \\
{|||\,\,\,\,} \\
{CH}
\end{array}}\limits_{Acetylene} \xrightarrow{{KMn{O_2}}}\mathop {\begin{array}{*{20}{c}}
{COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{COOH}
\end{array}}\limits_{Oxalic\,acid} $
View full question & answer→MCQ 2541 Mark
$1, 2-$dibromoethane when heated with alcoholic potash gives
Answerb
(b) $\mathop {|\,\,\,\,\,\,\,\,\,\,}\limits_{C{H_2}Br}^{C{H_2}Br} + 2KOH{\text{ (alcoholic) }}\xrightarrow{\Delta }CH \equiv CH + 2KBr + 2{H_2}O$
View full question & answer→MCQ 2551 Mark
Which of the following is not a member of homologous series
- A
- B
$1-$butene
- C
$2-$butene
- ✓
$2-$butyne
AnswerCorrect option: D. $2-$butyne
d
(d) All are alkenes but $2-$butyne is not.
View full question & answer→MCQ 2561 Mark
What is the product when $2-$butyne is treated with liquid $N{H_3}$ in presence of lithium
- A
$n-$butane
- B
cis$-2-$butene
- ✓
trans$-2-$butene
- D
$1-$butene
AnswerCorrect option: C. trans$-2-$butene
c
(c) Reduction of alkynes with liquid $N{H_3}/Li$ gives trans alkenes.
View full question & answer→MCQ 2571 Mark
Distinction in pentene$-1$ and pentyne$-1$ is done by
- ✓
${[Ag{(N{H_3})_2}]^ + }$
- B
Conc. ${H_2}S{O_4}$
- C
$HCl$
- D
$B{r_2}$
AnswerCorrect option: A. ${[Ag{(N{H_3})_2}]^ + }$
a
$1$-Pentene does not react with Tollen's reagent.
View full question & answer→MCQ 2581 Mark
A mixture of ethane, ethene and ethyne is passed through ammoniacal $AgN{O_3}$ solution. The gases which remain unreacted are
Answera
(a) Ethyne reacts with ammonical $AgN{O_3}$to give white ppt of silver acetylide while ethane and ethene do not react because acidic hydrogen is absent.
View full question & answer→MCQ 2591 Mark
In its reaction with silver nitrate acetylene shows
Answerd
(d)Acidic property because $H$ atoms are replaced by Silver metal atoms.
View full question & answer→MCQ 2601 Mark
Simplest alkyne is represented by
- A
$CH$
- B
$C{H_2}$
- ✓
${C_2}{H_2}$
- D
${C_2}{H_4}$
AnswerCorrect option: C. ${C_2}{H_2}$
c
The simplest acyclic alkynes with only one triple bond and no other functional groups form a homologous series with the general chemical formula $C _{ n } H _{2 n -2}$ Alkynes are traditionally known as acetylenes, although the name acetylene also refers specifically to $C _2 H _2$ known formally as ethyne using $IUPAC$ nomenclature.
View full question & answer→MCQ 2611 Mark
Carbide, which react with water to give propyne is
AnswerCorrect option: C. $M{g_2}{C_3}$
c
(c)$M{g_2}{C_3} + 4{H_2}O \to C{H_3}C \equiv CH + 2Mg{(OH)_2}$
View full question & answer→MCQ 2621 Mark
Hydrocarbon ${C_6}{H_6}$ decolourise $B{r_2}$ water and gives ppt. with ammonical $AgN{O_3}$ Hydrocarbon can be
Answerd
(d) Because Ammonical $AgN{O_3}$ reduce $C \equiv CH$ bond of yne.
View full question & answer→MCQ 2631 Mark
Order of reactivity of ${C_2}{H_6},{C_2}{H_4}$ and ${C_2}{H_2}$ is
- A
${C_2}{H_6} > {C_2}{H_4} > {C_2}{H_2}$
- B
${C_2}{H_2} > {C_2}{H_6} > {C_2}{H_4}$
- ✓
${C_2}{H_2} > {C_2}{H_4} > {C_2}{H_6}$
- D
AnswerCorrect option: C. ${C_2}{H_2} > {C_2}{H_4} > {C_2}{H_6}$
c
(c)Unsaturated hydrocarbons are more reactive than saturated hydrocarbons. Among ethyne $({C_2}{H_2})$ and ethene $({C_2}{H_4})$ the later is more reactive as $C \equiv C$ triple bond is quite strong bond and therefore ethyne generally require catalysts (like $H{g^{2 + }}$ etc) in its reactions.
View full question & answer→MCQ 2641 Mark
$C{H_3}C \equiv CC{H_3}\mathop {\xrightarrow{{(i){\text{ }}X}}}\limits_{(ii){H_2}O/Zn}$
$\begin{array}{*{20}{c}}
{C{H_3} - C - C - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{O\,\,\,\,\,\,\,\,\,O}
\end{array}$ $X$ in the above reaction is
- A
$HN{O_3}$
- B
${O_2}$
- ✓
${O_3}$
- D
$KMn{O_4}$
AnswerCorrect option: C. ${O_3}$
c
(c)$C{H_3} - C \equiv C - C{H_3}\mathop {\xrightarrow{{{\text{(i)}}\,{O_3}}}}\limits_{{\text{(ii)}}\,Zn/{H_2}O} C{H_3} - \mathop {\mathop C\limits_{||} }\limits_O - \mathop {\mathop C\limits_{||} }\limits_O - C{H_3}$
View full question & answer→MCQ 2651 Mark
In the reaction $HC \equiv CH + 2AgN{O_3}\xrightarrow{{N{H_4}OH}}X + 2N{H_4}N{O_3} + 2{H_2}O$ :‘$X$’ is
- A
$A{g_2}C$
- ✓
$A{g_2}{C_2}$
- C
$AgC$
- D
$AgOH$
AnswerCorrect option: B. $A{g_2}{C_2}$
b
(b) $HC \equiv CH + 2AgN{O_3}\xrightarrow{{N{H_4}OH}}$ $Ag - C \equiv C - Ag + 2N{H_4}N{O_3} + 2{H_2}O$
View full question & answer→MCQ 2661 Mark
Acetylene reacts with $HCN$ in the presence of $Ba{(CN)_2}$ to yield
- A
$1, 1-$dicyanoethane
- B
$1, 2-$dicyanoethane
- ✓
- D
Answerc
(c) $\mathop {CH \equiv CH + HCN}\limits_{{\text{Acetylene}}} \xrightarrow{{Ba{{(CN)}_2}}}\mathop {C{H_2} = CHCN}\limits_{{\text{Vinyl cyanide}}} $
View full question & answer→MCQ 2671 Mark
$Ca{C_2} + {H_2}O \to A\xrightarrow{{{H_2}S{O_4}/HgS{O_4}}}B$ Identify $A$ and $B$ in the given reaction
- ✓
${C_2}{H_2}$ and $C{H_3}CHO$
- B
$C{H_4}$ and $HCOOH$
- C
${C_2}{H_4}$ and$C{H_3}COOH$
- D
${C_2}{H_2}$ and $C{H_3}COOH$
AnswerCorrect option: A. ${C_2}{H_2}$ and $C{H_3}CHO$
a
(a)Wohler reaction :
$Ca{C_2} + 2{H_2}O\xrightarrow{{}}{C_2}{H_2} + Ca{(OH)_2}$
$\mathop {{C_2}{H_2}}\limits_{{\text{Acetylene}}} \mathop {\xrightarrow{{dil.\,{H_2}S{O_4}/HgS{O_4}}}}\limits_{{{60}^o}C} \mathop {[C{H_2} = CHOH]}\limits_{{\text{Unstable}}} \to \mathop {C{H_3}CHO}\limits_{{\text{Acetaldehyde}}} $
View full question & answer→MCQ 2681 Mark
What is formed when calcium carbide react with heavy water
- ✓
${C_2}{D_2}$
- B
$Ca{D_2}$
- C
$Ca{D_2}O$
- D
$C{D_2}$
AnswerCorrect option: A. ${C_2}{D_2}$
a
$\mathop {Ca{C_2}}\limits_{{\text{calcium carbide}}} + \mathop {2{D_2}O}\limits_{{\text{heary water}}} \xrightarrow{{}}{C_2}{D_2} + Ca{(OD)_2}$
View full question & answer→MCQ 2691 Mark
When acetylene is reacted with $HBr$, we get
Answerd
(d) $CH \equiv CH\xrightarrow{{HBr}}C{H_2} = CH - Br\xrightarrow{{HBr}}$

View full question & answer→MCQ 2701 Mark
$CH \equiv CH + HBr \to X,$ product $X$ is
Answerb
(b) $\mathop {CH \equiv CH + HBr}\limits_{{\rm{Acetylene}}} \to \,\,\,\mathop {C{H_2} = CHBr}\limits_{{\rm{Vinyl bromide}}} $
View full question & answer→MCQ 2711 Mark
Which of the following compound do not release $CO_2$ on oxidative ozonolysis
- A
$1-$ butene
- ✓
$2-$ butyne
- C
- D
AnswerCorrect option: B. $2-$ butyne
b
Terminal alkene & alkyne release $CO_2$ on oxidative ozonolysis
View full question & answer→MCQ 2721 Mark
$1$-butyne can be distinguished from $2$-butyne by
- A
$H_2/Pd\ BaSO_4$
- B
$Br_2 / H_2O$
- ✓
$Cu_2Cl_2/NH_4OH$
- D
AnswerCorrect option: C. $Cu_2Cl_2/NH_4OH$
c
$C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\xrightarrow{C{{u}_{2}}C{{l}_{2}}/N{{H}_{4}}OH}$
$C{{H}_{3}}-C{{H}_{2}}-C\equiv \overset{\Theta }{\mathop{C}}\,\,\overset{\oplus }{\mathop{C}}\,u\,\,(\operatorname{Re}d\,Coloured)$
View full question & answer→MCQ 2731 Mark
Product $A$ is major

AnswerCorrect option: B. $CH_3 - C \equiv C - CH_3$
b
Bromination followed by dehydrohalogenation
View full question & answer→MCQ 2741 Mark
What is final product $Ph - C \equiv CH\xrightarrow[{Hgs{o_4}}]{{dil{H_2}S{O_4}}}\Pr oduct$
- ✓
$\,\,\,\begin{array}{*{20}{c}}
O \\ {||\,} \\
{Ph - C - C{H_3}}
\end{array}$
- B
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{Ph - C{H_2} - C - H}
\end{array}$
- C
$Ph-CH_2-CH_3$
- D
$\,\,\,\begin{array}{*{20}{c}} {OH} \\ {|\,\,\,\,\,\,\,} \\ {Ph - CH - C{H_3}} \end{array}$
AnswerCorrect option: A. $\,\,\,\begin{array}{*{20}{c}}
O \\ {||\,} \\
{Ph - C - C{H_3}}
\end{array}$
View full question & answer→MCQ 2751 Mark
Which of the following decolorise $Br_2$ water solution
- A
- B
$CH_3-CH_2-OH$
- ✓
$HC \equiv CH$
- D
$CH_3-CH_2-Cl$
AnswerCorrect option: C. $HC \equiv CH$
View full question & answer→MCQ 2761 Mark
In the reaction sequence
$C{H_3} - C \equiv CH\xrightarrow[{Dry\,ether}]{{C{H_3}MgBr}}C{H_4} + (A)\xrightarrow[{(ii)\,{H_2}O/{H^ + }}]{{(ii)\,C{O_2}}}(B),(B)$ will be
- A
$C{H_3} - C \equiv C - C{H_3}$
- B
$C{H_3} - C \equiv C - MgBr$
- ✓
$C{H_3} - C \equiv C - COOH$
- D
$CH_3 -CH = CH -COOH$
AnswerCorrect option: C. $C{H_3} - C \equiv C - COOH$
c

View full question & answer→MCQ 2771 Mark
$CH_3-C \equiv C-O-CH_3 \xrightarrow{{dil.\,{H_2}S{O_4},HgS{O_4}}}$ major product
Answerb

View full question & answer→MCQ 2781 Mark
$C_6H_5-C \equiv C-CH_3 \xrightarrow[{{H_2}S{O_4}}]{{HgS{O_4},\,{H_2}O}} A$
Major Product $(A)$ will be
- ✓
- B
- C
$\begin{array}{*{20}{c}}
{{C_6}{H_5} - C = CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
- D
$\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH = C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
Answera
Addition of $H_2O$ according to Markownikoff's rule without rearrangement of carbocation
View full question & answer→MCQ 2791 Mark
(image) $\xrightarrow{\Delta }X;X$ can also be formed by

- A
$CH_3-CH_2-CH_2-Cl \xrightarrow{{LiAl{H_4}}}$
- B
$CH_3-CH_2-COOH \xrightarrow{{P + HI}}$
- ✓
$C{H_3} - C \equiv CH\xrightarrow[{{H_2}O}]{{H{g^{ + 2}}}}$
- D
AnswerCorrect option: C. $C{H_3} - C \equiv CH\xrightarrow[{{H_2}O}]{{H{g^{ + 2}}}}$
View full question & answer→MCQ 2801 Mark
Sum of $x + y =$ ?

View full question & answer→MCQ 2811 Mark
$C{H_3} - C \equiv C - C{H_3}\,\xrightarrow[{{\text{(2) B}}{{\text{r}}_2}}]{{{\text{(1)}}{{\text{H}}_2}{\text{ /Pd/CaC}}{{\text{O}}_3}}}\,(X){\kern 1pt} ,\,(X)$ is
- A
$(d)-2,3-$ Dibromobutane
- B
$(1)-2,3-$ Dibromobutane
- ✓
$(d, \ell )-2,3-$ Dibromobutane
- D
meso $-2,3-$ Dibromobutane
AnswerCorrect option: C. $(d, \ell )-2,3-$ Dibromobutane
View full question & answer→MCQ 2821 Mark
Number of pure $p-$ orbitals in the given molecule hexa $-1, 3-$ dien $-5-$ yne
View full question & answer→MCQ 2831 Mark
Which of the following molecule possesses a bond formed by $sp^2-sp$ orbital overlap ?
- ✓
- B
- C
But $-2-$ yne
- D
But $-2-$ ene
View full question & answer→MCQ 2841 Mark
Calcium carbide + heavy water $ \to$ ?
The product of the above reaction is
- A
$C_2 H_2$
- B
$CaD_2$
- ✓
$Ca(OD)_2$
- D
$CD_4$
AnswerCorrect option: C. $Ca(OD)_2$
c
$(c) \,CaC_2 + D_2O \to Ca(OD)_2 + D-C \equiv C - D$
View full question & answer→MCQ 2851 Mark
Order of the bond strength of $C-H$ bonds involving $sp, sp^2$ and $sp^3$ hybridized carbon atoms is
- ✓
$sp > sp^2 > sp^3$
- B
$sp^3 > sp^2 > sp$
- C
$sp^2 > sp^3 > sp$
- D
$sp^2 > sp > sp^3$
AnswerCorrect option: A. $sp > sp^2 > sp^3$
a
$(a)$ $EN$ value $sp > sp^2 > sp^3$ (more the electronegativity more will be the bond strength)
View full question & answer→MCQ 2861 Mark
Product $(B)$ of the reaction is
$\begin{matrix}
CH-C{{O}_{2}}H \\
\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
CH-C{{O}_{2}}H \\
\end{matrix}\xrightarrow[(two\,mole)]{NaOH}(A)\xrightarrow{electrolysis}(B);$
- A
$CH_3 -CH_3$
- B
$H_2C = CH_2$
- ✓
$H - C \equiv C - H$
- D
$CH_2 = CH -CH =CH_2$
AnswerCorrect option: C. $H - C \equiv C - H$
c

View full question & answer→MCQ 2871 Mark
Product $(B)$ is

Answerc

View full question & answer→MCQ 2881 Mark
(image) $X$ can also be formed by

- A
$C{H_3} - C{H_2} - C{H_2} - Cl\xrightarrow{{LiAl{H_4}}}$
- B
$C{H_3} - C{H_2} - COOH\xrightarrow{{P + HI}}$
- ✓
$C{H_3} - C \equiv CH\xrightarrow[{{H_2}O}]{{H{g^{ + 2}}}}$
- D
AnswerCorrect option: C. $C{H_3} - C \equiv CH\xrightarrow[{{H_2}O}]{{H{g^{ + 2}}}}$
View full question & answer→MCQ 2891 Mark
Which of the following reagent is used to distinguish propene and propyne
AnswerCorrect option: D. $AgNO_3$ in $NH_4OH$
d
Propene and propyne can be distinguish by using Ammoniacal silver nitrate test.
Propyne has an acidic hydrogen due to which it readily react with Ammoniacal silver nitrate gives white precipitate while propene does not give any precipitate.
View full question & answer→MCQ 2901 Mark
$CH \equiv CH + CO + {H_2}O\,\xrightarrow{{Ni{{(CO)}_4}}}$ Product,
For this reaction which statement is false
- A
The product of reaction is a $\alpha ,$ $\beta -$ unsaturated acid
- B
The reaction involves addition of Hydrogen and carboxylic group at $\pi $ bond
- C
The product name in this reaction is acrylic acid
- ✓
The product reacts with ethyl alcohol to give ethyl butanoate
AnswerCorrect option: D. The product reacts with ethyl alcohol to give ethyl butanoate
View full question & answer→MCQ 2911 Mark
Two mole of $HBr$ is added with $CH_3 -C$ $ \equiv $ $CH$ in presence of peroxide to give
- A
$CH_3-CH_2-CHBr_2$
- ✓
$CH_3-CH(Br)-CH_2Br$
- C
$CH_3-CBr_2-CH_3$
- D
$CH_3 -CH_2Br -CHBr_2$
AnswerCorrect option: B. $CH_3-CH(Br)-CH_2Br$
View full question & answer→MCQ 2921 Mark
$C{H_3} - C \equiv CH\xrightarrow[{(ii)\,\,{H_2}{O_2}/\mathop O\limits^\Theta H}]{{(i)\,\,B{H_3} - THF}}\,(P)$
$C{H_3} - C \equiv CH\xrightarrow[{(ii)\,\,NaB{H_4}}]{{(i)\,\,Hg{{(OAC)}_2}/{H_2}O}}\,(Q)$
Choose the correct option
- A
$(P)$ and $(Q)$ are identical in nature
- B
$(P)$ and $(Q)$ are geometrical isomer
- C
$(P)$ and $(Q)$ are position isomers
- ✓
$(P)$ and $(Q)$ are functional isomers
AnswerCorrect option: D. $(P)$ and $(Q)$ are functional isomers
View full question & answer→MCQ 2931 Mark
Identify wrong statement
$R - C \equiv C - R\xrightarrow{{Pd/BaS{O_4}}}A$
$R - C \equiv C - R\xrightarrow{{Na/Liq.\,NH_3}}B$
- A
$\vec \mu (A) > \vec \mu (B)$
- B
Boiling point $(A) >$ boiling point $(B)$
- C
Stability $(A) <$ stability $(B)$
- ✓
Melting point $(A) >$ melting point $(B)$
AnswerCorrect option: D. Melting point $(A) >$ melting point $(B)$
View full question & answer→MCQ 2941 Mark
Which of the following reaction forms aldehyde as a product
- ✓
$CH \equiv CH\,\xrightarrow[{333\,\,K}]{{H{g^{ + 2}}/{H_3}{O^ \oplus }}}$
- B
$C{H_3} - C \equiv CH\,\xrightarrow[{333\,\,K}]{{H{g^{ + 2}}/{H_3}{O^ \oplus }}}$
- C
$C{H_3} - C \equiv C - CH\,\xrightarrow[{333\,\,K}]{{H{g^{ + 2}}/{H_3}{O^ \oplus }}}$
- D
$A$ and $B$ both
AnswerCorrect option: A. $CH \equiv CH\,\xrightarrow[{333\,\,K}]{{H{g^{ + 2}}/{H_3}{O^ \oplus }}}$
View full question & answer→MCQ 2951 Mark
But $-1-$ yne and But $-2-$ yne can be distinguished by
- ✓
$(AgNO_3 + NH_4OH)$
- B
$Br_2|CCl_4$
- C
- D
$HCl$
AnswerCorrect option: A. $(AgNO_3 + NH_4OH)$
View full question & answer→MCQ 2961 Mark
$2-$ Butyne react with $Na$ in liquid Ammonia to form
- A
$1-$ butene
- B
$Cis$ $-2-$ butene
- ✓
trans $-2-$ butene
- D
$n-$ butane
AnswerCorrect option: C. trans $-2-$ butene
c
When but- $2-$ yne is treated with Na in liquid ammonia, addition of two $\mathrm{H}-$ atoms takes place at the triple bonded carbon atoms in trans manner.
$\begin{aligned}\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CCH}_{3} \frac{\mathrm{Na}}{\mathrm{Liq.NH}_{3}} \mathrm{CH}_{3}-\mathrm{C}=& \mathrm{C}-\mathrm{CH}_{3} \\& \mathrm{H}\end{aligned}$
View full question & answer→MCQ 2971 Mark
When $CH_3CH_2CH_2CHCl_2$ is treated with $2\, gram$ equivalent $NaNH_2$, the product formed is
AnswerCorrect option: A. $C{H_3}C{H_2}C \equiv CH$
a
$CH_3-CH_2-CH_2-CHCl_2$ $\xrightarrow{{NaN{H_2}}}C{H_3} - C{H_2} - C \equiv CH$
View full question & answer→MCQ 2981 Mark
Which of the following compound does not react with $Na$ ?
- A
$CH_3OH$
- B
$C{H_3} - C \equiv CH$
- C
$Ph-OH$
- ✓
View full question & answer→MCQ 2991 Mark
$C{H_3} - C \equiv CH\xrightarrow{{Na}}X\xrightarrow{{C{H_3} - Cl}}Y$ ,
$Y$ is
- A
$C{H_3} - C{H_2} - C \equiv CH$
- ✓
$C{H_3} - C \equiv C - C{H_3}$
- C
$C{H_3} - C{H_2} - CH = C{H_2}$
- D
$C{H_3} - CH = CH - C{H_3}$
AnswerCorrect option: B. $C{H_3} - C \equiv C - C{H_3}$
View full question & answer→MCQ 3001 Mark
When $23\, g$ $Na$ reacts with $1\, mole$ of propyne then how many mole of $H_2$ gas will be released......$mole$
Answerb
$C{{H}_{3}}-C\equiv CH+\underset{\begin{smallmatrix}
23\,gm \\
\left( 1\,mole \right)
\end{smallmatrix}}{\mathop{Na}}\,\longrightarrow C{{H}_{3}}\equiv {{C}^{\Theta }}N{{a}^{\oplus }}+\underset{\left( 1/2\,mole \right)}{\mathop{1/2{{H}_{2}}}}\,$
View full question & answer→MCQ 3011 Mark
Which of the following are not aromatic
- A
- B
Cyclo-octatetrarenyl dianion
- C
- ✓
View full question & answer→MCQ 3021 Mark
Cyclopentadienyl anion is
View full question & answer→MCQ 3031 Mark
Which gives monosubstituted product
- A
$o$- dinitrobenzene
- ✓
$m$- dinitrobenzene
- C
$p$- dinitrobenzene
- D
AnswerCorrect option: B. $m$- dinitrobenzene
b
(b) gives only monosubstitution product as $ - N{O_2}$ group is meta directing and only one $m$-position is possible in $m$- dinitrobenzene.

View full question & answer→MCQ 3041 Mark
The presence of the chlorine atom on benzene ring makes the second substituent enter at a position
Answerd
(d)Chlorine atom is orth-para directing group.
View full question & answer→MCQ 3051 Mark
In electrophilic substitution reaction nitrobenzene is
- A
- B
- ✓
- D
Not reactive and does not undergo any substitution
Answerc
Nitrobenzene is meta-directing for an electrophilic substitution reaction since it has an electron-withdrawing group (i.e $NO _2$ ). There is less electron density at ortho- and para- position and more electron density at meta- position. That's why it is meta directing.

View full question & answer→MCQ 3061 Mark
The most common type of reaction in aromatic compounds is
- A
- B
- ✓
Electrophilic substitution reaction
- D
AnswerCorrect option: C. Electrophilic substitution reaction
c
Aromatic compounds or arenes undergo substitution reactions, in which the aromatic hydrogen is replaced with an electrophile, hence their reactions proceed via electrophilic substitution.
Arenes contain double bonds just like alkenes but they do not undergo electrophilic addition because these would result to their loss of ring aromaticity.
View full question & answer→MCQ 3071 Mark
The function of $AlC{l_3}$ in Friedel-Craft’s reaction is
Answerd
The function of $AlCl _3$ in Friedel-Crafts reaction, is to produce electrophile which later attack on benzene.

View full question & answer→MCQ 3081 Mark
Which of the following can’t be used in Friedal Craft’s reactions
- A
$FeC{l_3}$
- B
$FeB{r_2}$
- C
$AlC{l_3}$
- ✓
$NaCl$
AnswerCorrect option: D. $NaCl$
d
(d)All cations are expected to act as Lewis acid since they are electron deficient in nature. However cation such as $N{a^ + },\;{K^ + }$ etc. (Inert gas configuration) have a very little tendency to accept electrons. Therefore they do not acts as lewis acids in friedel Craft’s reaction.
View full question & answer→MCQ 3091 Mark
The nitration of a compound is due to the
- A
$N{O_2}$
- B
$N{O_3}$
- C
$NO$
- ✓
$NO_2^ + $
AnswerCorrect option: D. $NO_2^ + $
d
(d) The process of nitration takes place as below
$HON{O_2} + 2{H_2}S{O_4}$ $ \rightleftharpoons $ ${H_3}{O^ + } + 2HSO_4^ - + \mathop {NO_2^ + }\limits_{({\rm{nitronium ion}})} $
The electrophile responsible for nitration is $NO_2^ + $ ion.
View full question & answer→MCQ 3101 Mark
The product formed when acetylene is passed through red hot tube is
Answera
(a)

View full question & answer→MCQ 3111 Mark
Which of the following pairs has the same bond angle
Answerc
(c) Ethylene and Benzene
$120^°$ $120^°$
$s{p^2}$ $s{p^2}$
View full question & answer→MCQ 3121 Mark
Benzene is the polymer of
Answerd
(d)

View full question & answer→MCQ 3131 Mark
The compound formed as a result of potassium permanganate oxidation of ethylbenzene is
Answera
The compound formed as a result of oxidation of ethyl benzene by alkaline $KMnO _4$ is benzoic acid.
Other reagents that can be used are acidified potassium dichromate or dilute nitric acid.

View full question & answer→MCQ 3141 Mark
The function of anhydrous $AlC{l_3}$ in the Friedel-Craft's reaction is to
Answerc
The function of $AlCl _3$ in Friedel-Crafts reaction, is to produce electrophile which later attack on benzene.

View full question & answer→MCQ 3151 Mark
Acylation process is preferred than direct alkylation because (by the Friedel-Craft's reaction)
- A
In alkylation, a poisonous gas is evolved
- B
In alkylation, large amount of heat is evolved
- ✓
In alkylation, polyalkylated product is formed
- D
Alkylation is very costly
AnswerCorrect option: C. In alkylation, polyalkylated product is formed
c
When benzene is alkylated, along with mono alkyl benzene, polyalkylation products are also obtained. Hence, instead of direct alkylation, acylation is preferred. This is followed by reduction of carbonyl group to methylene group.
View full question & answer→MCQ 3161 Mark
The reaction of benzene with chlorine in the presence of iron gives
Answerb
(b)

View full question & answer→MCQ 3171 Mark
Benzene on treatment with a mixture of conc. $HN{O_3}$ and conc. ${H_2}S{O_4}$ at ${100\,^o}C$ gives
- A
- ✓
$m-$dinitrobenzene
- C
$p-$dinitrobenzene
- D
$o-$dinitrobenzene
AnswerCorrect option: B. $m-$dinitrobenzene
b
(b)

View full question & answer→MCQ 3181 Mark
What is the end product which is obtained on the nitration of toluene
AnswerCorrect option: D. $2, 4, 6-$trinitrotoluene
d
(d)

View full question & answer→MCQ 3191 Mark
Which of the following processes is reversible
Answerb
(b)

View full question & answer→MCQ 3201 Mark
The attacking (electrophilic) species in sulphonation of benzene is
- A
$S{O_2}$
- ✓
$S{O_3}$
- C
$SO_4^{2 - }$
- D
$HSO_3^ - $
AnswerCorrect option: B. $S{O_3}$
b
Sulphur trioxide $SO _3$ is active species in sulphonation of benzene.
$SO _3$ acts as an electrophile and accepts a pair of $pi$ electrons from benzene.
View full question & answer→MCQ 3211 Mark
Which xylene is most easily sulphonated
Answerc
(c) $m-$ xylene is most easily sulphonated because $O$ and $P$ both positions are free with respect to methyl group.

View full question & answer→MCQ 3221 Mark
Toluene on oxidation with dilute $HN{O_3}$ and alkaline $KMn{O_4}$ gives
Answerd
(d)

View full question & answer→MCQ 3231 Mark
Benzene vapour mixed with air when passed over ${V_2}{O_5}$ catalyst at $775\,K$ gives
Answerc
(c)

View full question & answer→MCQ 3241 Mark
Most common reactions of benzene (aromatic hydrocarbon) and its derivatives are
- A
Electrophilic addition reactions
- ✓
Electrophilic substitution reactions
- C
Nucleophilic addition reactions
- D
Nucleophilic substitution reactions
AnswerCorrect option: B. Electrophilic substitution reactions
b
Benzene and it's derivatives is much more stable than expected. The extra stability means that benzene will less readily undergo addition reactions. The more loosely held electrons are open to attack by electrophiles. Hence, the characteristic reaction of benzene is electrophilic substitution reaction.
View full question & answer→MCQ 3251 Mark
Which is most readily nitrated
Answerb
(b)Phenol is most easily nitrated.
View full question & answer→MCQ 3261 Mark
$o, p-$ directing groups are mostly
Answera
Most $o,p$-directing groups are Activating Group. If electrophilic aromatic substitution of a monosubstituted benzene is faster than that of benzene under identical conditions, the substituent in the monosubstituted benzene is called an Activating Group.
View full question & answer→MCQ 3271 Mark
Which of the following would be least reactive towards bromine
Answera
(a) Nitrobenzene is least reactive towards bromine because of presence of $ - N{O_2}$ group decreases electron density at $o$ and $p$ positions and hence attack of electrophile on the benzene nucleus is difficult because $+ ve$ charge on $o$ and $p$ position repel the incoming electrophile.

View full question & answer→MCQ 3281 Mark
Amongst the following, the compound that is nitrated with difficulty is
Answerb
Nitrogen of nitro benzene is difficult as it contain electron with drawing group, making compound electron elements.
View full question & answer→MCQ 3291 Mark
$(i)$ Chlorobenzene and $(ii)$ benzene hexachloride are obtained from benzene by the reaction of chlorine, in the presence of
- A
$(i)$ Direct sunlight and $(ii)$ anhydrous $AlC{l_3}$
- B
$(i) $ Sodium hydroxide and $(ii)$ sulphuric acid
- C
$(i)$ Ultraviolet light and $(ii)$ anhydrous $FeC{l_3}$
- ✓
$(i)$ Anhydrous $AlC{l_3}$ and $(ii)$ direct sunlight
AnswerCorrect option: D. $(i)$ Anhydrous $AlC{l_3}$ and $(ii)$ direct sunlight
d
(d)

View full question & answer→MCQ 3301 Mark
Nitration of benzene is a
- ✓
Electrophilic displacement
- B
- C
- D
Nucleophilic displacement
AnswerCorrect option: A. Electrophilic displacement
a
Nitration of benzene involves the formation of a very powerful electrophile, the nitronium ion, which is linear. This occurs following the interaction of two strong acids, sulfuric and nitric acid. Sulfuric acid is the stronger and it protonates the nitric acid on the $OH$ group so that a molecule of water can leave. Benzene attacks the positively charged nitrogen atom of the electrophile, where one of the $N = O$ bonds is broken at the same time. This is followed by rapid loss of a proton to regenerate the aromaticity.
View full question & answer→MCQ 3311 Mark
Answerd
There are delocalised electrons above and below the plane of the ring. The presence of the delocalised electrons makes benzene particularly stable.
Benzene resists addition reactions because that would involve breaking the delocalisation and losing that stability.
An alkylbenzene is simply a benzene ring with an alkyl group attached to it. ... Alkyl groups are usually fairly resistant to oxidation. However, when they are attached to a benzene ring, they are easily oxidised by an alkaline solution of potassium manganate($VII$) (potassium permanganate).
View full question & answer→MCQ 3321 Mark
Benzene can be obtained in the reaction
Answerb
(b) Benzene can be obtained by polymerisation of acetylene.
View full question & answer→MCQ 3331 Mark
Thiophene and benzene are separated by
- A
Sulphonation of thiophene
- ✓
- C
- D
Answerb
Probably the most convenient method is to use the fact that thiophene is highly reactive toward sulfonation.
Shaking a mixture of benzene and thiophene with sulfuric acid at room temperature causes sulfonation of the thiophene but leaves the benzene untouched.
The thiophene sulfonic acid dissolves in the sulfuric acid layer, which you can separate.
You can then wash, dry, and distill the benzene in the usual way.
View full question & answer→MCQ 3341 Mark
Which of the following is a hydrocarbon
Answerb
(b) Benzene ${C_6}{H_6}$ is made up of hydrogen and carbon only.
View full question & answer→MCQ 3351 Mark
Aromatic compounds burn with sooty flame because
- A
They have a ring structure of carbon atoms
- B
They have a relatively high percentage of hydrogen
- ✓
They have a relatively high percentage of carbon
- D
They resist reaction with oxygen of air
AnswerCorrect option: C. They have a relatively high percentage of carbon
c
(c)They have a relatively high percentage of carbon
View full question & answer→MCQ 3361 Mark
Among the following compound which one is planar in shape
Answerc
(c) All $6$ carbons of Benzene are $s{p^2}$-hybridised so it is planar.
View full question & answer→MCQ 3371 Mark
Methyl group attached to benzene can be oxidised to carboxyl group by reacting with
- A
$F{e_2}{O_3}$
- B
$AgN{O_3}$
- ✓
$KMn{O_4}$
- D
$C{r_2}{O_3}$
AnswerCorrect option: C. $KMn{O_4}$
c
(c)

View full question & answer→MCQ 3381 Mark
How it is widely used

Answerc
(c) $2,4,6-$Trinitro toluene $(TNT)$ is used as explosive.
View full question & answer→MCQ 3391 Mark
The compound ‘$A$’ when treated with $HN{O_3}$ (in presence of ${H_2}S{O_4}$) gives compound ‘$B$’ which is then reduced with $Sn$ and $HCl$ to aniline. The compound ‘$A$’ is
Answerb
(b)

View full question & answer→MCQ 3401 Mark
The compound used as an explosive is
- A
$2,4, 6$ -tribromoaniline
- B
$1,3, 5-$ trinitrobenzene
- C
$2,4, 6-$ trichlorotoluene
- ✓
$2,4, 6-$ trinitrotoluene
AnswerCorrect option: D. $2,4, 6-$ trinitrotoluene
d
(d) $TNT$ is used as an explosive.
View full question & answer→MCQ 3411 Mark
Adding of $C{l_2}$ to benzene in the presence of $AlC{l_3}$ is an example of
Answerd

View full question & answer→MCQ 3421 Mark
What happens when naphthalene balls are put inside kerosene
Answerc
compounds dissolves in polar solvents non polar or covalent compounds dissolved in non polar solvents.
Here, naphthalene and kerosene are polar compounds.
View full question & answer→MCQ 3431 Mark
Three fused benzene rings are found in
Answerb
Anthracene is a solid polycyclic aromatic hydrocarbon ($PAH$) of formula $C _{14} H _{10}$ consisting of three fused benzene rings. It is a component of coal tar.
Anthracene is used in the production of the red dye alizarin and other dyes.
Anthracene is colorless but exhibits a blue $(400-500\, nm$ peak) fluorescence under ultraviolet radiation

View full question & answer→MCQ 3441 Mark
Product obtained after nitration of nitrobenzene is
- A
$TNT$
- ✓
$1, 3-$dinitrobenzene
- C
- D
$1, 4-$dinitrobenzene
AnswerCorrect option: B. $1, 3-$dinitrobenzene
b
(b)

View full question & answer→MCQ 3451 Mark
After ozonolysis of benzene (not hydrolysis), the product is
Answera
Ozonolysis is the cleavage of an alkene or alkyne with ozone to form organic compounds in which the multiple carbon-carbon bond has been replaced by a double bond to oxygen. The ozonolysis of benzene forms Glyoxal through the formation of benzene Triozonide as an intermediate.
Therefore in here is no hydrolysis take place so benzene Trioznide is seems as a product.

View full question & answer→MCQ 3461 Mark
The compound ‘$A$’ having formula ${C_8}{H_{10}}$ (aromatic) which gives $1$ mononitro substitute and $3$ nitrosubstitute compound is
- A
$m-$Xylene
- ✓
$p-$Xylene
- C
$o-$Xylene
- D
AnswerCorrect option: B. $p-$Xylene
b
From above reaction we find best appropriate option is $B$.
View full question & answer→MCQ 3471 Mark
Answera
Benzene was first discovered by the English scientist Michael Faraday in $1825$ in illuminating gas. In $1834$ German chemist Eilhardt Mitscherlich heated benzoic acid with lime and produced benzene. In $1845$ German chemist A.W. von Hofmann isolated benzene from coal tar.
View full question & answer→MCQ 3481 Mark
The ‘middle oil’ fraction of coaltar distillation contains
Answerc
Aromatic hydrocarbons are obtained by fractional distillation of coal tar. The first fraction (crude light oil) mainly contains benzene, toluene and xylene. The second fraction (middle oil) contains naphthalene, while the next fraction (green oil) contains mainly anthracene and phenanthrene.
View full question & answer→MCQ 3491 Mark
Lindane can be obtained by reaction of benzene with
AnswerCorrect option: B. $C{l_2}$ / sunlight
b
(b)

View full question & answer→MCQ 3501 Mark
Which of the following oil is obtained from benzene after fractional distillation of coal tar
Answera
(a)Benzene on fractional distillation gives light oil [It is lighter than water and hence called as light oil]
View full question & answer→MCQ 3511 Mark
Decreasing order of $C-C$ bond length is
$I.$ ${C_2}{H_4}$ $II.$ ${C_2}{H_2}$
$III.$ ${C_6}{H_6}$ $IV.$ ${C_2}{H_6}$
- ✓
$IV > III > I > II$
- B
$I > II > IV > III$
- C
$II > I > IV > III$
- D
$IV > I > III > II$
AnswerCorrect option: A. $IV > III > I > II$
a
(a) Bond length $ \propto \frac{1}{{{\rm{Bond order}}}}$
Bond order = $\frac{{{\rm{Bonding -- antibonding electron}}}}{{\rm{2}}}$
Bond order is highest for ${C_2}{H_6}$ so it has minimum bond strength.
View full question & answer→MCQ 3521 Mark
Benzene can be obtained by heating either benzoic acid with $X$ or phenol with $Y$. $X$ and $Y$ are respectively
- A
- ✓
- C
Zinc dust and sodium hydroxide
- D
Answerb
(b) ${C_6}{H_5}COOH + \mathop {NaOH}\limits_{{\text{(x)}}} \to {C_6}{H_5}COONa + {H_2}O$ $\xrightarrow{{NaOH}}{C_6}{H_6} + N{a_2}C{O_3}$
${C_6}{H_5}OH + \mathop {Zn}\limits_{{\text{(y)}}} \xrightarrow{{{\text{distill}}}}{C_6}{H_6} + ZnO$
View full question & answer→MCQ 3531 Mark
When toluene is treated with $KMn{O_4}$, what is produced
Answerd
(d)

View full question & answer→MCQ 3541 Mark
In presence of light & heat toluene chlorinated & react with aqueous $NaOH$ to give
Answerd
(d)

View full question & answer→MCQ 3551 Mark
Which of the following is Friedel-Craft's reaction
- A
${C_6}{H_6} + FeC{l_3} + C{l_2} \to {C_6}{H_5}Cl$
- B
${C_6}{H_5}CHO + C{H_3}CHO + KOH \to {C_6}{H_5}CH = CH - CHO$
- ✓
${C_6}{H_6} + C{H_3}COCl + AlC{l_3} \to \mathop {\mathop {{C_6}{H_5} - C - C{H_3}}\limits^{\,\,\,\,||} }\limits^{\,\,\,O} $
- D
${C_6}{H_5}OH + CHC{l_3} + KOH\xrightarrow{{}}{\text{Salicylaldehyde}}$
AnswerCorrect option: C. ${C_6}{H_6} + C{H_3}COCl + AlC{l_3} \to \mathop {\mathop {{C_6}{H_5} - C - C{H_3}}\limits^{\,\,\,\,||} }\limits^{\,\,\,O} $
c
(c) Friedel-craft's reaction
$\mathop {C{H_3}COCl}\limits_{{\text{Acetyl chloride}}} + \mathop {{C_6}{H_6}}\limits_{{\text{Benzene}}} \xrightarrow{{{\text{anhydrous }}AlC{l_3}}}\mathop {C{H_3}CO{C_6}{H_5}}\limits_{{\text{Acetophenone}}} + HCl$
View full question & answer→MCQ 3561 Mark
Which one of the following reactions is most suitable for the preparation of $n-$ propyl benzene
Answerc
(c)

View full question & answer→MCQ 3571 Mark
Answerd
(d) Naphthalene is a molecular solid. If the crystals contains only individuals atoms; as in solid argon or krypton or if they are composed of non polar molecules as in naphthalene, the only attraction between the molecules are the London forces.
View full question & answer→MCQ 3581 Mark
Which of the following is not aromatic
AnswerCorrect option: D. $1,3,5- $heptatriene
d
(d) A compound is said to be aromatic if it is planar and there is complete delocalization of $\pi $ electrons, which is only possilble if it is a conjugated cyclic system and number of electrons used in delocalization is $(4n + 2)$. $1, 3, 5- $heptatriene is not an aromatic compound because complete delocalization of $\pi $ electrons, is not possible in it.

View full question & answer→MCQ 3591 Mark
A group which deactivates the benzene ring towards electrophilic substitution but which directs the incoming group principally to the $o-$ and $p-$ positions is
- A
$ - N{H_2}$
- ✓
$ - Cl$
- C
$ - N{O_2}$
- D
$ - {C_2}{H_5}$
AnswerCorrect option: B. $ - Cl$
b
(b) Electron accepting groups which make the substitution difficult are known of deactivating groups. the group or substituent already present on the ring also decides the position of incoming group.
ortho and para directing groups are as follow
$ - C{H_3},{C_2}{H_5}( - R), - N{H_2}, - OH$, halogens, $(Cl,\,Br,\,I)$
View full question & answer→MCQ 3601 Mark
Which order is correct for the decreasing reactivity to ring monobromination of the following compounds
$\begin{array}{l}{C_6}{H_5}C{H_3},\\\,\,\,\,\,\,\,\,\,\,{\rm{I}}\end{array}$$\begin{array}{l}{C_6}{H_5}COOH,\\\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{II}}\end{array}$$\begin{array}{l}{C_6}{H_6}\\\,\,\,\,{\rm{III}}\end{array}$$\begin{array}{l}{C_6}{H_5}N{O_2}\\\,\,\,\,\,\,\,\,\,\,{\rm{IV}}\end{array}$
- A
$I > II > III > IV$
- ✓
$I > III > II > I$
- C
$II > III > IV > I$
- D
$III > I > II > IV$
AnswerCorrect option: B. $I > III > II > I$
b
(b)

View full question & answer→MCQ 3611 Mark
- A
Substitution of three acetylene molecules
- B
Addition of three ${C_2}{H_2}$ molecules
- ✓
Polymerisation of three ${C_2}{H_2}$ molecules
- D
Condensation of three ${C_2}{H_2}$ molecules
AnswerCorrect option: C. Polymerisation of three ${C_2}{H_2}$ molecules
c
(c) Polymerisation
$3CH \equiv CH\mathop {\xrightarrow{{{\text{heat}}}}}\limits_{Cu,\,{{500}\,^o}C} $

View full question & answer→MCQ 3621 Mark
In presence of light toluene on reaction with chlorine gives
Answerd
(d) Sidechain chlorination and bromination is favoured by high temperature, light and in absence of halogen carrie

View full question & answer→MCQ 3631 Mark
Which of the following is an electrophile
- A
${H_2}O$
- B
$N{H_3}$
- ✓
$AlC{l_3}$
- D
${C_2}{H_5}N{H_2}$
AnswerCorrect option: C. $AlC{l_3}$
c
$AlCl_3$ is an electron deficient compound.
Hence, act as an electrophile.
View full question & answer→MCQ 3641 Mark
In reaction ${C_6}{H_5}C{H_3}\xrightarrow[{{\text{Oxidation}}}]{}A\xrightarrow[{NaOH}]{}B\xrightarrow{{{\text{Sodalime}}}}C$ Then $C$ is
AnswerCorrect option: A. ${C_6}{H_6}$
a
(a) ${C_6}{H_5}C{H_3}\xrightarrow{{[O]}}\mathop {{C_6}{H_5}COOH}\limits_{[A]} \xrightarrow{{NaOH}}$
$\mathop {{C_6}{H_5}COONa}\limits_{[B]} \xrightarrow{{NaOH/CaO}}\mathop {{C_6}{H_6}}\limits_{[C]} $
View full question & answer→MCQ 3651 Mark
Which of the following will be easily nitrated
- ✓
- B
- C
$C{H_3}N{O_2}$
- D
${C_6}{H_5}N{O_2}$
Answera
(a) The presence of an electron-releasing groups ($+I$ group) e.g., $ - C{H_3}, - OH, - N{H_2}$ etc makes the process of nitration easier. So ${C_6}{H_3}C{H_3}$ will be easily nitrated.
View full question & answer→MCQ 3661 Mark
Chlorination of benzene is not possible in the following reaction
- A
${C_6}{H_6} + C{l_2}\xrightarrow{{FeC{l_3}}}$
- ✓
${C_6}{H_6} + HOCl\xrightarrow{{{H^ + }}}$
- C
${C_6}{H_6} + I - Cl\xrightarrow{{ZnC{l_2}}}$
- D
${C_6}{H_6} + C{l_2}\xrightarrow{{AlC{l_3}}}$
AnswerCorrect option: B. ${C_6}{H_6} + HOCl\xrightarrow{{{H^ + }}}$
b
(b) Reaction is called Gattermann-Koch synthesis, which is carried by catalyst $AlC{l_3}$.
View full question & answer→MCQ 3671 Mark
Which of the following is non-aromatic ?
View full question & answer→MCQ 3681 Mark
Identify anti aromatic compound ?
View full question & answer→MCQ 3691 Mark
product is ?

View full question & answer→MCQ 3701 Mark
Decide the correct order of reactivity of following compounds towards halogenation with $(Cl_2 + AlCl_3)$

- ✓
$I$ > $II$ > $III$ > $IV$
- B
$II$ > $III$ > $IV$ > $I$
- C
$III$ > $II$ > $IV$ > $I$
- D
$II$ > $III$ > $I$ > $IV$
AnswerCorrect option: A. $I$ > $II$ > $III$ > $IV$
View full question & answer→MCQ 3711 Mark
How many $\pi$ electron are there in the following species :

View full question & answer→MCQ 3721 Mark
Number of $\pi$ electrons present in naphthalene is :
View full question & answer→MCQ 3731 Mark
Which of the following is not the property of benzene:
View full question & answer→MCQ 3741 Mark
Benzene undergoes substitution reaction more easily than addition because:
- A
It has a cyclic structure
- B
It has three double bonds
- C
It has six hydrogen atoms
- ✓
View full question & answer→MCQ 3751 Mark
View full question & answer→MCQ 3761 Mark
Which of the following reagents and conditions convert benzene to chloro-benzene :
- A
$Cl_2,$ sunlight, heat
- B
$HCl,$ heat
- C
$HCl,$ sunlight, heat
- ✓
$Cl_2, AlCl_3,$ cold
AnswerCorrect option: D. $Cl_2, AlCl_3,$ cold
View full question & answer→MCQ 3771 Mark
Which order is correct for the decreasing reactivity to ring monobromination of the following compounds :
$(I) \,C_6H_5CH_3$
$(II)\, C_6H_5COOH$
$(III)\, C_6H_6$
$(IV) \,C_6H_5NO_2$
- A
$I > II > III > IV$
- ✓
$I > III > II > IV$
- C
$II > III > IV > I$
- D
$III > I > II > IV$
AnswerCorrect option: B. $I > III > II > IV$
View full question & answer→MCQ 3781 Mark
Benzene on treatment with a mixture of conc. $HNO_3$ and conc. $H_2SO_4$ at $90^o C$ gives :
- A
- ✓
$m-$ Dinitrobenzene
- C
$p-$ Dinitrobenzene
- D
$o-$ Dinitrobenzene
AnswerCorrect option: B. $m-$ Dinitrobenzene
View full question & answer→MCQ 3791 Mark
Which of the following structures correspond to the product expected, when excess of $C_6H_6$ reacts with $CH_2Cl_2$ in presence of anhydrous $AlCl_3$ :
View full question & answer→MCQ 3801 Mark
Which of the following group is divalent :
View full question & answer→MCQ 3811 Mark
$C_6H_6 + A \xrightarrow{{AlC{l_3}}} C_6H_5CONH_2$
$A$ in the above reaction is:
- A
$NH_2CONH_2$
- ✓
$ClCONH_2$
- C
$CH_3CONH_2$
- D
$CH_2(Cl)CONH_2$
AnswerCorrect option: B. $ClCONH_2$
View full question & answer→MCQ 3821 Mark
When benzene is heated with acetic anhydride in the presence of anhydrous aluminium chloride at $80^o C,$ the product formed is :
View full question & answer→MCQ 3831 Mark
${C_6}{H_6}\mathop {\xrightarrow{{C{H_3}COCl}}}\limits_{AlC{l_3}} A\mathop {\xrightarrow{{Zn - Hg}}}\limits_{HCl} B$
The end product in the above sequence is :
View full question & answer→MCQ 3841 Mark
The species responsible for nitration and sulphonation by nitric acid conc. $H_2SO_4$ and fuming $H_2SO_4$ are :
- A
$NO_2$ and $SO_3$
- ✓
$NO_2^+$ and $SO_3$
- C
$NO^+$ and $SO_2$
- D
$NO_2$ and $SO_2$
AnswerCorrect option: B. $NO_2^+$ and $SO_3$
View full question & answer→MCQ 3851 Mark
Reaction of $SO_3$ is easier in :
View full question & answer→MCQ 3861 Mark
If the mixture of the following four aromatic compounds on oxidation by strong oxidising agent gives :

AnswerCorrect option: C. Only $C_6H_5COOH$
View full question & answer→MCQ 3871 Mark
Methyl group attached to benzene can be oxidised to carboxyl group by reacting with :
- A
$Fe_2O_3$
- B
$AgNO_3$
- ✓
$KMnO_4$
- D
$CrO_3$
AnswerCorrect option: C. $KMnO_4$
View full question & answer→MCQ 3881 Mark
The reaction of benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ gives :
View full question & answer→MCQ 3891 Mark
The number of benzylic hydrogen atoms in ethylbenzene is :
View full question & answer→MCQ 3901 Mark
$X\xrightarrow{{C{l_2}}}$ Benzotrichloride $\xrightarrow{{Hydrolysis}}Y$
$X$ and $Y$ respectively are :
View full question & answer→MCQ 3911 Mark
Product obtained when benzoyl acetic acid is heated with soda-lime is :
View full question & answer→MCQ 3921 Mark
Etard reaction in the following is :
AnswerCorrect option: A. Oxidation of toluene to benzaldehyde by chromylchloride
View full question & answer→MCQ 3931 Mark
The highest yield of $m-$ product is possible by the electrophilic substitution of the following :
- A
$C_6H_5CH_3$
- B
$C_6H_5CH_2COOC_2H_5$
- C
$C_6H_5CH(COOC_2H_5)_2$
- ✓
$C_6H_5C(COOC_2H_5)_3$
AnswerCorrect option: D. $C_6H_5C(COOC_2H_5)_3$
View full question & answer→MCQ 3941 Mark
Which of the following is/are produced when a mixture of benzene vapour and oxygen is passed over $V_2O_5$ catalyst at $775\, K$ ?
View full question & answer→MCQ 3951 Mark
Which of the following is the least reactive in the case of bromination :
View full question & answer→MCQ 3961 Mark
No. of $\pi$ electrons in the following is :

View full question & answer→MCQ 3971 Mark
Which of the following is not an aromatic compound :
View full question & answer→MCQ 3981 Mark
Which of the following will undergo sulphonation at fastest rate ?
View full question & answer→MCQ 3991 Mark
Aniline under acidic medium, when chlorinated, produces :
- A
$o-$ chloro aniline
- ✓
$m-$ chloro aniline
- C
$p-$ chloro aniline
- D
Mixture of ortho and para-chloro aniline
AnswerCorrect option: B. $m-$ chloro aniline
View full question & answer→MCQ 4001 Mark
Which of the following undergoes chlorination at fastest rate ?
View full question & answer→MCQ 4011 Mark
Which of the following is most reactive towards sulphonation ?
- ✓
$m-$ Xylene
- B
$o-$ Xylene
- C
- D
$p-$ Xylene
AnswerCorrect option: A. $m-$ Xylene
View full question & answer→MCQ 4021 Mark
Which of the following undergoes sulphonation at fastest rate ?
- A
$C_6H_5NO_2$
- B
$C_6H_5CH_2NO_2$
- C
$C_6H_5CH_2CH_2NO_2$
- ✓
View full question & answer→MCQ 4031 Mark
Which of the following undergoes nitration fast?
View full question & answer→MCQ 4041 Mark
When sulphonilic acid $(p-H_2NC_6H_4SO_3H)$ is treated with excess of bromine, the product is :
View full question & answer→MCQ 4051 Mark
Ring nitration of dimethyl benzene results in the formation of only one nitro dimethyl benzene. The dimethyl benzene is
View full question & answer→MCQ 4061 Mark
If $p-$ methoxy toluene is nitrated, the major product is :
View full question & answer→MCQ 4071 Mark
If meta-nitroaniline is chlorinated, the major product is :
View full question & answer→MCQ 4081 Mark
An aromatic compound of molecular formula $C_6H_4Br_2$ was nitrated when three isomers of formula $C_6H_3Br_2NO_2$ were obtained. The original compound is :
- A
$o-$ dibromobenzene
- ✓
$m-$ dibromobenzene
- C
$p-$ dibromobenzene
- D
AnswerCorrect option: B. $m-$ dibromobenzene
View full question & answer→MCQ 4091 Mark
Which of the following carbocations is expected to be most stable?
View full question & answer→MCQ 4101 Mark
The number of disubstituted products of benzene is
View full question & answer→MCQ 4111 Mark
Which of the following species is expected to have maximum enthalpy in an electrophilic aromatic substitution reaction ?

- ✓
Species $(II)$
- B
Species $(III)$
- C
Species $(IV)$
- D
Species $(V)$
AnswerCorrect option: A. Species $(II)$
View full question & answer→MCQ 4121 Mark
For the electrophilic substitution reaction involving nitration, which of the following sequence regarding the rate of reaction is true ?
- A
${k_{{C_6}{H_6}}}\, > \,{k_{{C_6}{D_6}}}\, > \,{k_{{C_6}{T_6}}}$
- B
${k_{{C_6}{H_6}}}\, < \,{k_{{C_6}{D_6}}}\, < \,{k_{{C_6}{T_6}}}$
- ✓
${k_{{C_6}{H_6}}}\, = \,{k_{{C_6}{D_6}}}\, = \,{k_{{C_6}{T_6}}}$
- D
${k_{{C_6}{H_6}}}\, > \,{k_{{C_6}{D_6}}}\, < \,{k_{{C_6}{T_6}}}$
AnswerCorrect option: C. ${k_{{C_6}{H_6}}}\, = \,{k_{{C_6}{D_6}}}\, = \,{k_{{C_6}{T_6}}}$
View full question & answer→MCQ 4131 Mark
For the electrophilic substitution reaction involving sulphonation, which of the following sequence regarding the rate of reaction is true ?
- ✓
${k_{{C_6}{H_6}}}\, > \,{k_{{C_6}{D_6}}}\, > \,{k_{{C_6}{T_6}}}$
- B
${k_{{C_6}{H_6}}}\, < \,{k_{{C_6}{D_6}}}\, < \,{k_{{C_6}{T_6}}}$
- C
${k_{{C_6}{H_6}}}\, = \,{k_{{C_6}{D_6}}}\, = \,{k_{{C_6}{T_6}}}$
- D
${k_{{C_6}{H_6}}}\, > \,{k_{{C_6}{D_6}}}\, < \,{k_{{C_6}{T_6}}}$
AnswerCorrect option: A. ${k_{{C_6}{H_6}}}\, > \,{k_{{C_6}{D_6}}}\, > \,{k_{{C_6}{T_6}}}$
View full question & answer→MCQ 4141 Mark
The order of relative reactivity of the given halides towards $S_N1$ reaction is
- A
benzylchloride $> p-$ methoxybenzylchloride $> p-$ nitrobenzylchloride
- ✓
$p-$ methoxybenzylchloride $ > $ benzylchloride $ > p-$ nitrobenzylchloride
- C
$p-$ methoxybenzylchloride $ > p-$ nitrobenzylchloride $ > $ benzylchloride
- D
benzylchloride $ > p-$ nitrobenzylchloride $ > p-$ methoxybenzylchloride
AnswerCorrect option: B. $p-$ methoxybenzylchloride $ > $ benzylchloride $ > p-$ nitrobenzylchloride
View full question & answer→MCQ 4151 Mark
Which reaction is not named as Friedal Craft's reaction
View full question & answer→MCQ 4161 Mark
To prepare $A$ from $B$ the correct sequence of reagents can be

- A
$Cl_2\ /\ AlCl_3\ ;\ Mg(THF)\ ;\ O_2\ /\ H^+$
- B
$HNO_3\ +\ H_2SO_4\ ;\ Sn\ +\ HCl\ ;\ NaNO_2\ +\ HCl\ ;$ Steam
- C
$CH_3-CH=CH_2\ /\ H^+\ ;\ O_2\ /\ hv\ ;\ H^+$
- ✓
View full question & answer→MCQ 4171 Mark
Which of the following nonaromatic in nature
View full question & answer→MCQ 4181 Mark
Which of the following represents Huckle's rule
- A
$(4n)\pi \,{e^\Theta }$
- ✓
$(4n+2)\pi \,{e^\Theta }$
- C
$(4n+1)\pi \,{e^\Theta }$
- D
$(2n+2)\pi \,{e^\Theta }$
AnswerCorrect option: B. $(4n+2)\pi \,{e^\Theta }$
View full question & answer→MCQ 4191 Mark
Complete the following reactions and identify $A, B\,C$ respectively

- A
$A = Ni, B = H_2O\, (liquid), C = H_2O$
- ✓
$A = Zn, B = H_2O \,(steam), C = H_2 (Ni-Al\, alloy)$
- C
$A = Mg, B = H_2O \,(liquid), C = HCl$
- D
$A = Zn, B = H_2O \,(boiling), C = SnCl_2$
AnswerCorrect option: B. $A = Zn, B = H_2O \,(steam), C = H_2 (Ni-Al\, alloy)$
b

View full question & answer→MCQ 4201 Mark
In the ration,
$X$ and $Y$ respectively are :-

- ✓
$C_6H_5Cl$ and $C_6H_5SO_3H$
- B
$C_6H_5Cl$ and $C_6H_5OH$
- C
$C_6H_4Cl_2$ and $C_6H_5SO_2$
- D
$C_6H_5Cl$ and $C_6H_5CHO$
AnswerCorrect option: A. $C_6H_5Cl$ and $C_6H_5SO_3H$
View full question & answer→MCQ 4211 Mark
$Ca + C\xrightarrow[\Delta ]{}A\xrightarrow{{{H_2}O}}B\xrightarrow[{cyclic\,polymerisation}]{}C$
Product $B$ and $C$ are respectively
- A
$CH_4$ and polythene
- ✓
$C_2H_2$ and Benzene
- C
$C_2H_4$ and polythene
- D
$C_2H_4$ and Benzene
AnswerCorrect option: B. $C_2H_2$ and Benzene
View full question & answer→MCQ 4221 Mark
Which of the following reaction is called as wurtz fittig reaction ?
View full question & answer→MCQ 4231 Mark
Product $A$ in the reaction will be

View full question & answer→MCQ 4241 Mark
Above reaction is known as

Answerc
$(c)$ Aryl-halide is used.
$\therefore$ It is known as Wurtz fittig reaction
View full question & answer→MCQ 4251 Mark
Product $(B)$ in the above reaction is

Answerb
in forward direction

View full question & answer→MCQ 4261 Mark
Cycloalkane has the formula
- A
${C_n}{H_{2n + 2}}$
- B
${C_n}{H_{2n - 2}}$
- ✓
${C_n}{H_{2n}}$
- D
${C_{2n}}{H_2}$
AnswerCorrect option: C. ${C_n}{H_{2n}}$
View full question & answer→MCQ 4271 Mark
Which is the example of branch isomerization
- ✓
$\mathop {\mathop {\mathop {\mathop {C - C - C}\limits^| }\limits^C }\limits_{} }\limits_{} - C$ -C and $\mathop {\mathop {\mathop {\mathop {C - C - C}\limits^| }\limits^C }\limits_| }\limits_C $
- B
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C - C - C} \\
| \\
C
\end{array}$ and $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C - C} \\
| \\
C
\end{array}$
- C
- D
$C - C - C - C$ and $\begin{array}{*{20}{c}}
{C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C}
\end{array}$
AnswerCorrect option: A. $\mathop {\mathop {\mathop {\mathop {C - C - C}\limits^| }\limits^C }\limits_{} }\limits_{} - C$ -C and $\mathop {\mathop {\mathop {\mathop {C - C - C}\limits^| }\limits^C }\limits_| }\limits_C $
View full question & answer→MCQ 4281 Mark
The decreasing order of boiling points is
- ✓
$n-$ Pentane > iso-Pentane > neo-Pentane
- B
iso-Pentane > $ n-$ Pentane > neo-Pentane
- C
neo-Pentane > iso-Pentane >$ n-$ Pentane
- D
$n-$ Pentane > neo-Pentane > iso-Pentane
AnswerCorrect option: A. $n-$ Pentane > iso-Pentane > neo-Pentane
a
As the boiling point of an alkane depends on the surface area of a molecule, higher the surface is, higher the boiling point of alkane. The branched-chain isomer of an alkane has a lower surface area than that of its straight-chain isomer, so the branched-chain isomer of an alkane has a lower boiling point than its straight-chain isomer.
So, higher the branches, lower is the boiling point.
So, the order of boiling point of isomeric pentanes is $n -$ pentane $\,>\,$ iso $-$ pentane $\,>\,$ neo $-$ pentane.
View full question & answer→MCQ 4291 Mark
To prepare a pure sample of $n-$ hexane using sodium metal as one reactant, the other reactant will be
- ✓
$n-$ propyl bromide
- B
Ethyl bromide and $ n-$ butyl bromide
- C
Ethyl chloride and $ n-$ butyl chloride
- D
Methyl bromide and $ n -$ pentyl chloride
AnswerCorrect option: A. $n-$ propyl bromide
a
(a) According to wurtz reaction
$2C{H_3}C{H_2}C{H_2}Br + 2Na\xrightarrow{{ether}}$ $C{H_3}{(C{H_2})_4}C{H_3} + 2NaBr$
View full question & answer→MCQ 4301 Mark
Sodium acetate can be converted to ethane by
- A
Heating with $LiAl{H_4}$
- ✓
Electrolysing its aqueous solution
- C
- D
Heating with calcium acetate
AnswerCorrect option: B. Electrolysing its aqueous solution
b
(b) $\mathop {2C{H_3}COONa}\limits_{{\text{Sodium}}\,{\text{acetate}}} + 2{H_2}O\xrightarrow{{{\text{Electolysis}}}}\,C{H_3} - C{H_3} + 2C{O_2} + 2NaOH + {H_2}$
View full question & answer→MCQ 4311 Mark
Which of the following compounds is used in antiknock compositions to prevent the deposition of oxides of lead on spark plug, combustion chamber and exhaust pipe
- A
- B
- ✓
$1, 2-$ dibromoethane
- D
AnswerCorrect option: C. $1, 2-$ dibromoethane
c
(c) $Pb{({C_2}{H_5})_4} \overset {heat} \longrightarrow Pb + \mathop {4C{H_3}CH_2^{}}\limits_{{\rm{Ethyl}}\,{\rm{radical}}} $
$\begin{array}{*{20}{c}}
{C{H_2} - C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,} \\
{\,Br\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,}
\end{array}$ $ + Pb \to \mathop {C{H_2} = C{H_2}}\limits_{Ethene} + \mathop {PbB{r_2}}\limits_{Leadbromide} $
As leaded gasoline burns, lead metal gets deposited in the engine which is removed by adding ethylene dibromide. The lead bromide is volatile and is carried off with the exhaust gases from the engine
View full question & answer→MCQ 4321 Mark
Which of petroleum corresponds to kerosene oil
- A
${C_{15}} - {C_{18}}$
- ✓
${C_{10}} - {C_{12}}$
- C
${C_5} - {C_9}$
- D
${C_1} - {C_9}$
AnswerCorrect option: B. ${C_{10}} - {C_{12}}$
b
Kerosene is a mixture of hydrocarbons. The chemical composition depends on its source of isolation, usually, it consists of about $10$ different hydrocarbons, each containing $11$ to $16$ carbon atoms per molecule.
The main constituents are saturated straight-chain and branched-chain hydrocarbons which are also called as paraffin, as well as ring-shaped cycloparaffins which are also known as naphthenes. Kerosene is less volatile liquid than gasoline.
View full question & answer→MCQ 4331 Mark
In the reaction $C{H_3} - Br + 2Na + Br - C{H_3} \to $, the product called
Answera
Typically, you would react two alkyl halides to form an alkane that consists of their respective $R$ groups. So, as an example, you would have:
$CH _3 Br + CH _3 Cl \stackrel{ Na ( s )}{\longrightarrow} CH _3 CH _3$
(with loss of $NaCl$ and then $NaBr$ )
View full question & answer→MCQ 4341 Mark
Iodoethane reacts with sodium in the presence of dry ether. The product is
Answerd
(d) ${C_2}{H_5}I + 2Na + I{C_2}{H_5} \xrightarrow[Dry]{Ether} \mathop {}\limits_{{\rm}} \mathop {{C_2}{H_5} - {C_2}{H_5}}\limits_{{\rm{Butane}}} + 2NaI$
View full question & answer→MCQ 4351 Mark
Which of the following is oxidised by $KMn{O_4}$
Answerc
(c) ${(C{H_3})_3}CH \xrightarrow{KMnO_4} \,\,\,\mathop {{{(C{H_3})}_3}C - OH}\limits_{{\rm{tertiary \,butyl \,alcohol}}} $
View full question & answer→MCQ 4361 Mark
The most volatile compound is
- ✓
$2, 2-$ dimethyl propane
- B
$2-$ methyl butane
- C
- D
$n-$ pentane
AnswerCorrect option: A. $2, 2-$ dimethyl propane
a
The boiling point is inversely proportional to the branch in the compound. Therefore, $2,2$-dimethyl propane has more branching, higher boiling point.
View full question & answer→MCQ 4371 Mark
In Wurtz reaction, the reagent used is
- A
$Na$
- B
$Na$ / liquid $NH_3$
- ✓
$Na$ / Dry ether
- D
$Na$ / Dry alcohol
AnswerCorrect option: C. $Na$ / Dry ether
c
(c) $RCl + 2Na + RCl \xrightarrow[Ether]{Dry} \mathop {} 2NaCl + \mathop {R - R}\limits_{{\rm{Alkane}}} $
View full question & answer→MCQ 4381 Mark
Which of the following has highest octane number
AnswerCorrect option: D. $2, 2, 4-$ trimethyl pentane
d
(d) iso-octane i.e. $2,2,4-$ trimethyl pentane has highest octane number.
View full question & answer→MCQ 4391 Mark
The petrol having octane number $80$ has
- ✓
$20\%$ normal heptane + $80\%$ iso-octane
- B
$80\%$ normal heptane + $20\%$ iso-octane
- C
$20\%$ normal heptane + $80\%$ normal octane
- D
$80\%$ normal heptane + $20\%$ normal octane
AnswerCorrect option: A. $20\%$ normal heptane + $80\%$ iso-octane
a
Petrol, which has octane number $80$ contain $20 \,\%\, n$-heptane and $80\, \%$ isooctane.
View full question & answer→MCQ 4401 Mark
Which of the following reactions will not give propane
- A
$C{H_3}C{H_2}C{H_2}Cl\mathop {}\limits_{} $ $ \xrightarrow[H_2O]{Mg/ether} $
- ✓
$C{H_3}COCl\mathop {}\limits_{} $ $ \xrightarrow[H_2O]{CH_3MgX} $
- C
$C{H_3}CH = C{H_2}\mathop {}\limits_{} $ $ \xrightarrow[B_2h_6]{CH_3COOH} $
- D
$\begin{array}{*{20}{c}}
{C{H_3}CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,}
\end{array}$ $ \xrightarrow{P/HI} $
AnswerCorrect option: B. $C{H_3}COCl\mathop {}\limits_{} $ $ \xrightarrow[H_2O]{CH_3MgX} $
b
(b) With calculated amount of Grignard reagent, acetyl chloride forms ketones.

View full question & answer→MCQ 4411 Mark
Which of the following are produced from coal tar
Answerd
(d) Synthetic dyes, drugs, perfumes all are made from coal tar.
View full question & answer→MCQ 4421 Mark
In alkanes, the bond angle is.....$^o$
- ✓
${109.5}$
- B
${109}$
- C
${120}$
- D
${180}$
AnswerCorrect option: A. ${109.5}$
a
(a) In alkanes, hybridization is $s{p^3}$. Hence bond angle is ${109^o}.5'$.
View full question & answer→MCQ 4431 Mark
In the preparation of alkanes; a concentrated aqueous solution of sodium or potassium salts of saturated carboxylic acid are subjected to
Answerd
(d) $2C{H_3}COONa + 2{H_2}O\, \xrightarrow{Electrolysis} \,\,\,C{H_3} - C{H_3} + 2C{O_2} + 2NaOH + {H_2}$
View full question & answer→MCQ 4441 Mark
Halogenation of alkanes is an example of
- A
Electrophilic substitution
- B
Nucleophilic substitution
- ✓
Free-radical substitution
- D
AnswerCorrect option: C. Free-radical substitution
c
Halogenation of alkanes is carried out in the presence of photochemical conditions.
Under photochemical conditions, the halogens will break homolytically and forms radical. The halogen radical will abstract hydrogen from alkanes. Now the alkyl radical can combine with alkyl radical or it can also combine with halogen radical forming alkyl radicals.

View full question & answer→MCQ 4451 Mark
Propionic acid is subjected to reduction with hydroiodic acid in the presence of a little P, the product formed is
Answerb
(b) $\mathop {C{H_3} - C{H_2} - COOH}\limits_{{\rm{Propanoic}}\,{\rm{acid}}} + 6HI \,\,\xrightarrow{Red P} \,\,\mathop {C{H_3} - C{H_2} - C{H_3}}\limits_{{\rm{Propane}}} + 2{H_2}O + 3{I_2}$
View full question & answer→MCQ 4461 Mark
When ethyl iodide and propyl iodide react with $Na$ in the presence of ether, they form
Answerd
(d) $\mathop {C{H_3} - C{H_2} - C{H_3}}\limits_{{\rm{Propane}}} + 2{H_2}O + 3{I_2}$ $ \xrightarrow[Ether]{Dry} $ $\mathop {{C_2}{H_5} - {C_3}{H_7}}\limits_{{\rm{Pentane}}} + 2NaI$
${C_2}{H_5}I + 2Na + {C_2}{H_5}I\mathop {}\limits_{{\rm{}}} \xrightarrow[Ether]{Dry} \mathop {{C_2}{H_5} - {C_2}{H_5}}\limits_{{\rm{Butane}}} + 2NaI$
${C_3}{H_7}I + 2Na + {C_3}{H_7}I\mathop {\xrightarrow{{Dry}}}\limits_{Ether} \mathop {{C_3}{H_7} - {C_3}{H_7}}\limits_{{\text{Hexane}}} + 2NaI$
View full question & answer→MCQ 4471 Mark
The alkane that yields two isomeric monobromo derivatives is
Answerd
Two isomeric monochloro derivatives of Propane are:
$1$-chloro propane $( CH _3- CH _2-CH_2(Cl))$ and $2$-chloro propane $( CH _3 - CH ( Cl )- CH _3 \text { ) }$
View full question & answer→MCQ 4481 Mark
Answera
Kerosene is a thin, clear liquid formed from hydrocarbons obtained from the fractional distillation of petroleum between $150^{\circ} C$ and $275^{\circ} C$, resulting in a mixture with a density of $0.78-0.81\, g / cm ^3$.It is composed of carbon chains that typically contain between $6$ and $16$ carbon atoms per molecule. It is miscible in petroleum solvents but immiscible in water. Kerosene's major components are branched and straight chain alkanes and naphthenes (cycloalkanes), which normally account for at least $70 \,\%$ by volume.
View full question & answer→MCQ 4491 Mark
When petroleum is heated the vapours contain mainly
Answerb
Petroleum ether because due to it's lowest boiling point
View full question & answer→MCQ 4501 Mark
Iso-octane is mixed to the petrol
- A
To precipitate inorganic substances
- B
To prevent freezing of petrol
- C
To increase boiling point of petrol
- ✓
Answerd
One member of the octane family, isooctane, is used as a reference standard to benchmark the tendency of gasoline or $LPG$ fuels to resist self-ignition. For example, gasoline with the same knocking characteristics as a mixture of $90 \,\%$ iso-octane and $10 \,\%$ heptane would have an octane rating of $90$
View full question & answer→MCQ 4511 Mark
Tetraethyl lead is used as
Answerc
Tetraethyl lead is used as petroleum additive to prevent knocking of engine.
View full question & answer→MCQ 4521 Mark
Cyclohexane, a hydrocarbon floats on water because
- A
It is immiscible with water
- B
Its density is low as compared to water
- C
It is non-polar substance
- ✓
It is immiscible and lighter than water
AnswerCorrect option: D. It is immiscible and lighter than water
d
(d) Cyclohexane, is immiscible and lighter than water. Hence, floats on the surface of water.
View full question & answer→MCQ 4531 Mark
Natural gas contains mainly
- ✓
- B
$n-$ butane
- C
$n-$ octane
- D
Answera
(a) Methane is the main component of natural gas.
View full question & answer→MCQ 4541 Mark
The organic compound used as antiknock agent in petroleum is
- ✓
${({C_2}{H_5})_4}Pb$
- B
$TNT$
- C
$C{H_3}MgBr$
- D
${({C_2}{H_5})_2}Hg$
AnswerCorrect option: A. ${({C_2}{H_5})_4}Pb$
a
This abnormal combustion produces a specific type of sound, which we call knocking.
Knocking has adverse effects. It results in early wear-and-tear of the piston. Carbon is deposited in the inner part of the cylinders [Internal Combustion Engines have cylinders, inside which pistons move]. Also, Efficiency is reduced.
So we want to reduce knocking. We add something which can reduce it. Such substances are called Anti - knockingAgents.
A popular anti-knocking agent was Tetra Ethyl Lead (TEL) $\left( C _2 H _5\right)_4 Pb$.
View full question & answer→MCQ 4551 Mark
Which of the following statements is incorrect. The members of the homologous series of alkanes
AnswerCorrect option: A. Are all straight chain compounds
a
All the members of the homologous series of alkanes are not straight chain compounds they can be branched, but differ by $- CH _2$ group.
View full question & answer→MCQ 4561 Mark
A liquid hydrocarbon can be converted to gaseous hydrocarbon by
- ✓
- B
- C
- D
Distillation under reduced pressure
Answera
(a) $\underset{\text{Liquid}}{\mathop{\underset{\text{Hexane}}{\overset{{}}{\mathop{{{C}_{6}}{{H}_{14}}}}}\,}}\,\xrightarrow{\Delta }\underset{\text{Butane}}{\mathop{{{C}_{4}}{{H}_{10}}}}\,+\underset{\text{Gas}}{\mathop{\underset{\text{Ethene}}{\mathop{{{C}_{2}}{{H}_{2}}}}\,}}\,$
View full question & answer→MCQ 4571 Mark
Formation of alkane by the action of $Zn$ on alkyl halide is called
Answera
$(i)$ wurtz reaction
$2 RX +2 Na \stackrel{\text { Ether }}{\longrightarrow} \underset{\text { alkane }}{ R - R }$
$(ii)$ Kolbe's reaction
$RCOONa + H _2 O \stackrel{\text { Electrolysis }}{\longrightarrow} \underset{\text { alkane }}{ R - R }$
$(iii)$ Ulmann's reaction
$2 C _6 H _5 I +2 Cu \rightarrow \underset{\text { biphenyl } }{ C _6 H _5}- C _6 H _5$
$(iv)$ Frankland reaction
$\underset{\text { alkyl halide }}{2 RX }+ Zn \rightarrow \underset{\text { alkane }}{ R - R }$
View full question & answer→MCQ 4581 Mark
Which of the following compounds will form a hydrocarbon on reaction with Grignard reagent
- ✓
$C{H_3}C{H_2}OH$
- B
$C{H_3}CHO$
- C
$C{H_3}COC{H_3}$
- D
$C{H_3}C{O_2}C{H_2}$
AnswerCorrect option: A. $C{H_3}C{H_2}OH$
a
(a) Compounds having active hydrogen $\left( {ROH,{H_2}O,R - N{H_2}} \right)$ can form alkane when treated with Grignard’s reagent

View full question & answer→MCQ 4591 Mark
Name the hydrocarbon that is a liquid at $STP$
- A
- B
- C
$n-$ butane
- ✓
$n-$ pentane
AnswerCorrect option: D. $n-$ pentane
d
Lower hydrocarbons which contain up to $4$ carbon atoms are gases at room temperature whereas higher hydrocarbons are liquid at room temperature. Thus $N - P$ entane is liquid at room temperautre.
View full question & answer→MCQ 4601 Mark
Which statement is not true concerning alkanes
- ✓
Large number alkanes are soluble in water
- B
All alkanes have a lower density than water
- C
At room temperature some alkanes are liquids, some solids and some gases
- D
AnswerCorrect option: A. Large number alkanes are soluble in water
a
No alkanes are not soluble in water. Water is a polar solvent and has hydrogen bonding. For any compound to be soluble in water, it should be polar or have hydrogen bonding in it.
View full question & answer→MCQ 4611 Mark
Fischer Tropsch process is used for the manufacture of
Answera
The Fisher-Tropscgh process is used in the manufacturing of Syntheticpetrol. The Fischer-Tropsch process is a collection of chemical reactions that converts a mixture of carbon monoxide and hydrogen into liquid hydrocarbons.... In the usual implementation, carbon monoxide and hydrogen, the feedstocks for $FT$, are produced from coal, natural gas, or biomass in a process known as gasification.
View full question & answer→MCQ 4621 Mark
Which one of the following compounds cannot be prepared by Wurtz reaction
- ✓
$C{H_4}$
- B
${C_2}{H_6}$
- C
${C_3}{H_8}$
- D
${C_4}{H_{10}}$
AnswerCorrect option: A. $C{H_4}$
a
(a)It is not possible to prepare $C{H_4}$ by wurtz reaction.
View full question & answer→MCQ 4631 Mark
A fuel contains $25 \%$ $n-$ heptane and $75 \%$ iso-octane. Its octane number is
Answerb
(b) Octane number is the percentage by volume of is $o-$ octane in the mixture of iso- octane and $n-$ heptane which has the same antiknocking properties as the fuel under examination.
Given fuel ($25\%$ $n- $ heptane + $75\%$ iso- octane) Hence, octane number = $75$ (because iso octane is $75\%$)
View full question & answer→MCQ 4641 Mark
Which of the following has highest percentage of hydrogen
- ✓
$C{H_4}$
- B
${C_2}{H_4}$
- C
${C_6}{H_6}$
- D
${C_2}{H_2}$
AnswerCorrect option: A. $C{H_4}$
a
(a) $\%$ of hydrogen = $\frac{Mass\,\, of\,\, hydrogen}{Mass \,\,of\, \,compond} \times 100$
$C{H_4} = \frac{4}{{16}}\; \times \;100\; = \;25\% $.
View full question & answer→MCQ 4651 Mark
What is the molecular formula of the alkane, the $5.6 \,litre$ of which weight $11 \,g$ at $STP$
- A
${C_6}{H_{14}}$
- B
${C_4}{H_{10}}$
- ✓
${C_3}{H_8}$
- D
${C_2}{H_6}$
AnswerCorrect option: C. ${C_3}{H_8}$
c
(c) Molecular mass can be obtained by the victor mayer process
${\rm{Molecular}}\,\,{\rm{mass}} = \frac{{{\rm{Weight}}\,}}{{V\,ml.}} \times {\rm{22400}}$
$ = \frac{{{\rm{11}}}}{{{\rm{5600}}}} \times 22400 = 44$
View full question & answer→MCQ 4661 Mark
The reference compound `iso-octane' which is used in determining the octane number of gasoline has the structure
- A
$C{H_3} - CH(C{H_3}) - CH(C{H_3}) - CH(C{H_3}) - C{H_3}$
- ✓
$C{H_3} - C{(C{H_3})_2} - C{H_2} - CH(C{H_3}) - C{H_3}$
- C
$C{H_3} - C{(C{H_3})_2} - CH(C{H_3}) - C{H_2} - C{H_3}$
- D
$C{H_3} - C{(C{H_3})_2} - C{(C{H_3})_2} - C{H_3}$
AnswerCorrect option: B. $C{H_3} - C{(C{H_3})_2} - C{H_2} - CH(C{H_3}) - C{H_3}$
b
The octane number of gasoline is a way of knocking down its resistance. The characteristics of octane number one gasoline are compared by isoacetane ($2,2,4$-trimethylparnane) and heptane. Isooctane is assigned an octane number of $100$ . It is a highly branching compound that burns easily, with little knock.

View full question & answer→MCQ 4671 Mark
Petroleum ether can be used as
- ✓
Solvent for fat, oil, varnish and rubber
- B
- C
Both $(a)$ and $(b)$
- D
AnswerCorrect option: A. Solvent for fat, oil, varnish and rubber
a
(a)Solvent for fat, oil, varnish and rubber
View full question & answer→MCQ 4681 Mark
The order of appearance of the following with rising temperature during the refining of crude oil is
- A
Kerosene oil, gasoline, diesel
- B
Diesel, gasoline, kerosene oil
- C
Gasoline, diesel, kerosene oil
- ✓
Gasoline, kerosene oil, diesel
AnswerCorrect option: D. Gasoline, kerosene oil, diesel
d
(d) Gasoline, kerosene oil, diesel
View full question & answer→MCQ 4691 Mark
When sodium propionate is heated with soda lime, the main product is
Answera
(a) $C{H_3} - C{H_2} - COONa \xrightarrow[\Delta]{Soda lime} \mathop {}\limits C{H_3} - C{H_3}$
View full question & answer→MCQ 4701 Mark
Gasoline is a mixture of alkanes with the number of carbon atoms
- A
${C_3} - {C_5}$
- B
${C_5} - {C_6}$
- C
${C_6} - {C_8}$
- ✓
${C_7} - {C_9}$
AnswerCorrect option: D. ${C_7} - {C_9}$
d
(d) Gasoline or petrol composition ${C_7} - {C_{12}}$.
View full question & answer→MCQ 4711 Mark
The final product of complete oxidation of hydrocarbons is
AnswerCorrect option: C. ${H_2}O + C{O_2}$
c
(c) $\mathop {C{H_4}}\limits_{{\rm{Methane}}} + 2{O_2} \to C{O_2} + 2{H_2}O$
$\mathop {{C_2}{H_4}}\limits_{{\rm{Ethene}}} + 3{O_2} \to 2C{O_2} + 2{H_2}O$
All hydrocarbons saturated or unsaturated on complete combustion always produce $C{O_2}$ and ${H_2}O$.
View full question & answer→MCQ 4721 Mark
Which of the following represents the most oxidized form of hydrocarbon
- ✓
$C{O_2}$
- B
$RCHO$
- C
$RCOOH$
- D
$RCOOOH$
AnswerCorrect option: A. $C{O_2}$
a
(a) Hydrocarbons on complete oxidation produce $C{O_2}$ and water
$C{H_3} - C{H_3} + 3\frac{1}{2}{O_2} \to 2\,C{O_2} + 3{H_2}O$
View full question & answer→MCQ 4731 Mark
Name the reaction
${C_{10}}{H_{22}} \xrightarrow{900\,K} {C_4}{H_8} + {C_6}{H_{14}}$
Answerb
(b) $\mathop {{C_{10}}{H_{22}}}\limits_{{\rm{Decane}}} \mathop {}\limits_{{\rm{}}} \xrightarrow[Cracking]{900\,K} \mathop {{C_4}{H_8}}\limits_{{\rm{Butane}}} + \mathop {{C_6}{H_{14}}}\limits_{{\rm{Hexane}}} $
View full question & answer→MCQ 4741 Mark
How many types of carbon atoms are present in $ 2, 2, 3-$ trimethylpentane
View full question & answer→MCQ 4751 Mark
At room temperature solid paraffin is
- A
${C_3}{H_8}$
- B
${C_8}{H_{18}}$
- C
${C_4}{H_{10}}$
- ✓
${C_{20}}{H_{42}}$
AnswerCorrect option: D. ${C_{20}}{H_{42}}$
d
$n$-Icosane (the straight-chain structural isomer of icosane) $\left( C _{20} H _{42}\right)$ is the shortest compound found in paraffin waxes used to form candles.
View full question & answer→MCQ 4761 Mark
Which one of the following compounds does not give addition reactions
- A
- ✓
- C
- D
Alkynes(e)Ketones(f)All of these
Answerb
(b) Alkanes do not give addition reactions because multiple bond is absent.
View full question & answer→MCQ 4771 Mark
The inorganic origin of petroleum is indicated by the fact that
- A
Its constituents can be separated by fractional distillation
- ✓
Carbon and hydrocarbon can combine by absorption of solar energy to give hydrocarbons
- C
Petroleum contains traces of chlorophyll
- D
Oil fields are located with the help of seismograph
AnswerCorrect option: B. Carbon and hydrocarbon can combine by absorption of solar energy to give hydrocarbons
b
Abiogenesis-inorganic origin of petroleum is the oldest theory which suggests that petroleum comes from the underneath part of the mantle very long time ago before the existence of life on earth. Carbon and hydrocarbon can combine by absorption of solar energy to give hydrocarbons.
View full question & answer→MCQ 4781 Mark
Which of the following is a gemdihalide
AnswerCorrect option: D. $C{H_3}CHB{r_2}$
d
(d) In gemdihalide both the halogen atoms are present on the same carbon atom while in vicdihalide both the halogen atoms are present on adjacent carbon atoms.
$\mathop {C{H_3} - CHB{r_2}}\limits_{{\rm{Gemdihalide}}} $ $\mathop {\mathop {C{H_2}}\limits_{\mathop {|\,\,\,\,\,\,\,}\limits_{Br\,\,\,} } - \mathop {C{H_2}}\limits_{\mathop {|\,\,\,\,\,\,\,\,}\limits_{Br\,\,\,\,} } }\limits_{vic{\rm{ - }}{\rm{dihalide}}} $
View full question & answer→MCQ 4791 Mark
Which one of the following contain isopropyl group
AnswerCorrect option: B. $2-$methylpentane
b
(b) $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{{H_3}C - {H_2}C - C - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,C{H_3}}
\end{array}}\limits_{2,3,3,3 - tetramethylpen\tan e} $
$\mathop {{H_3}C - {H_2}C - \mathop {\mathop {{H_2}C - HC - C{H_3}}\limits^{\,\,\,\,|} }\limits^{\,\,\,\,\,\,\,\,\,C{H_3}} }\limits_{{\rm{isopropyl group 2 - methylpentane}}} $
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,C{H_{3\,}}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{{H_3}C - {H_2}C - HC - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{2,2,3 - trimethylpen\tan e} $
$\mathop {\mathop {\mathop {\mathop {\mathop {{H_3}C - {H_2}C - C - C{H_2} - C{H_3}}\limits^{\,\,|} }\limits^{\,\,\,\,\,\,\,\,C{H_3}} }\limits_{\,|} }\limits_{\,\,\,\,\,\,C{H_3}} }\limits_{{\rm{3, 3 - dimethylpentane}}} $
View full question & answer→MCQ 4801 Mark
By Wurtz reaction, a mixture of methyliodide and ethyliodide gives
- A
- B
- C
- ✓
A mixture of the above three
AnswerCorrect option: D. A mixture of the above three
d
(d) All-butane, Ethane and Propane are possible in this reaction.
View full question & answer→MCQ 4811 Mark
Isomerism in saturated hydrocarbons is due to
AnswerCorrect option: C. Formation of branches in the chain of $C$ atoms
c
(c) Formation of branches in the chain of $C$ atoms
$\mathop {C - C - C - C}\limits_{{\rm{straight chain}}} $ $\mathop {C - \mathop C\limits_{\mathop |\limits_C } - C}\limits_{{\rm{Branched chain}}} $
View full question & answer→MCQ 4821 Mark
Photochemical chlorination of alkane is initiated by a process of
Answerc
(c) Chlorination of alkane in photochemical reaction which takes place by free radical mechanism. Free radicals are formed by homolytic bond fission or homolysis.
View full question & answer→MCQ 4831 Mark
Which of the following is not linked with methane
Answerc
(c) Marsh gas, Natural gas and coal gas contains $C{H_4}$ but producer gas is a mixture of $CO$ and ${N_2}$
$ \underset {Coke \,Red \,hot} {2C} \, + \underbrace {O_2 \, + 4N_2}_\text {Air} \, \longrightarrow \, \underbrace {2CO \, + \,4N_2}_\text {Producer $\,$gas} $
View full question & answer→MCQ 4841 Mark
Which of the following has highest octane number
Answerc
An aromatic compound has the highest octane number. The octane number of aromatic hydrocarbons are exceptionally high.
View full question & answer→MCQ 4851 Mark
Most of the hydrocarbons from petroleum are obtained by
- ✓
- B
Fractional crystallization
- C
- D
Answera
(a) Fractional distillation is based on the difference in the boiling point of different components.
View full question & answer→MCQ 4861 Mark
In the dichlorination reaction of propane, mixture of products are obtained. How many isomers, the mixture contains
Answerc
The mixture will contains $4$ isomers.
View full question & answer→MCQ 4871 Mark
Grignard reagent is not prepared in aqueous medium but prepared; in ether medium because the reagent
- ✓
- B
- C
Is highly reactive in ether
- D
Becomes inactive in water
Answera
Grignard reagent is not prepared in aqueous medium. It is prepared in ether medium because the reagent reacts with water. Slight traces of moisture will prevent the reaction.
View full question & answer→MCQ 4881 Mark
A sample of petrol is a mixture of $30\%$ $n-$heptane and $70\%$ iso-octane. The sample has octane number
Answerb
(b) Petrol sample $30\%$ $n-$heptane + $70\%$ iso-octane since iso-octane is $70\%$. Hence, octane no. is $70$.
View full question & answer→MCQ 4891 Mark
For the reduction of ketones to hydrocarbon, the appropriate agent is
- A
$HI$
- ✓
$Zn - Hg/HCl$
- C
- D
${H_2}S{O_4}$
AnswerCorrect option: B. $Zn - Hg/HCl$
b
Clemmensen reduction aldehydes and ketones are reduced to the corresponding alkanes by means of amalgamated $Zn - Hg$ and $HCl$.
View full question & answer→MCQ 4901 Mark
Heating of alkanes with fuming sulphuric acid or oleum at high temperature, which forms sulphonic acid, is called
Answerc
Heating of alkanes with fuming sulphuric acid or oleum at high temperature, which form sulphonic acid, is called Sulphonation.
$H _2 S _2 O _7 \text { (Oleum) } \rightarrow H _2 SO _4+ SO _3$
$R - H + SO _3 \rightarrow R - SO _2 OH$

View full question & answer→MCQ 4911 Mark
Daily use candles (paraffin wax) contain
- ✓
Higher saturated hydrocarbon
- B
Lower saturated hydrocarbon
- C
Higher unsaturated hydrocarbon
- D
Lower unsaturated hydrocarbon
AnswerCorrect option: A. Higher saturated hydrocarbon
a
Candles consist of paraffin wax which generally contains saturated hydrocarbons of length more than $C _{24}$.
View full question & answer→MCQ 4921 Mark
Normal butane convert into isobutane by
- A
$LiAl{H_4}$
- ✓
$AlC{l_3}$
- C
$NaB{H_4}$
- D
$Zn / HCl$
AnswerCorrect option: B. $AlC{l_3}$
b
(b) $\mathop {C{H_3}C{H_2}C{H_2}C{H_3}}\limits_{n - {\rm{butane}}} \xrightarrow[\Delta]{Anhyd AlCl_3} \mathop {C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{\,\,C{H_3}} } - C{H_3}}\limits_{{\rm{iso}}\,{\rm{butane}}} $
View full question & answer→MCQ 4931 Mark
Aluminium carbide on reacting with water gives
Answera
(a) $A{l_4}{C_3} + 6{H_2}O \to \mathop {3C{H_4}}\limits_{{\rm{Methane}}} + 2A{l_2}{O_3}$
View full question & answer→MCQ 4941 Mark
The marsh gas detector used by minerals works on the principle of
- ✓
Difference in the rates of diffusion of gases
- B
- C
Gay-Lussac's law of gaseous volumes
- D
AnswerCorrect option: A. Difference in the rates of diffusion of gases
a
The marsh gas detector used by miners works on the principle of Difference in the rates of diffusion of gases.
A marsh gas detector is a device that detects the presence of gases in an area, often as part of a safety system. This type of equipment is used to detect a gas leak or other emissions and can interface with a control system so a process can be automatically shut down. This type of device is important because there are many gases that can be harmful to organic life, such as humans or animals.
View full question & answer→MCQ 4951 Mark
Octane number can be changed by
Answerd
(d) The octane numbers of Fuel can be improved by increasing the percentage of branched chain alkanes, alkenes and aromatic hydrocarbon. Thus octane number can be changed by isomerisation (reforming), alkylation and aromatisation (cyclisation) etc.
View full question & answer→MCQ 4961 Mark
- A
${C_8} - {C_{12}}$
- B
${C_2} - {C_5}$
- ✓
${C_6} - {C_{11}}$
- D
AnswerCorrect option: C. ${C_6} - {C_{11}}$
c
(c) The approximate composition of gasoline is ${C_6} - {C_{11}}$ at boiling point $70-200\,^oC$ and is used in motor fuel, dry cleaning, petrol gas etc.
View full question & answer→MCQ 4971 Mark
The complete combustion of $C{H_4}$ gives
- A
$CO + {H_2}$
- B
$CO + {N_2}$
- ✓
$C{O_2} + {H_2}O$
- D
$CO + {N_2}O$
AnswerCorrect option: C. $C{O_2} + {H_2}O$
c
(c) $C{H_4} + {O_2} \to C{O_2} + 2{H_2}O$
View full question & answer→MCQ 4981 Mark
Which one of the following compounds gives methane on treatment with water
- ✓
$A{l_4}{C_3}$
- B
$Ca{C_2}$
- C
$VC$
- D
$SiC$(e)${B_4}C$
AnswerCorrect option: A. $A{l_4}{C_3}$
a
(a) $A{l_4}{C_3} + 12{H_2}O \to 3C{H_4} + 4Al{(OH)_3}$
$Ca{C_2} + 2{H_2}O \to {C_2}{H_2} + Ca{(OH)_2}$
View full question & answer→MCQ 4991 Mark
Pick out the alkane which differs from the other members of the group.
- A
$2,2-$dimethyl propane
- B
- C
$2-$methyl butane
- ✓
$2,2-$dimethyl butane
AnswerCorrect option: D. $2,2-$dimethyl butane
d
(d) Except $2,2$ dimethyl butane rest compound contain $5$ carbon i.e., pantane while $2,2 $ dimethyl butane contain $6$ carbon i.e., Hexane
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - C{H_2} - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
View full question & answer→MCQ 5001 Mark
The product obtained on reaction of ${C_2}{H_5}Cl$ with hydrogen over palladium carbon is
- A
${C_3}{H_8}$
- B
${C_4}{H_{10}}$
- ✓
${C_2}{H_6}$
- D
${C_2}{H_4}$
AnswerCorrect option: C. ${C_2}{H_6}$
c
(c) ${C_2}{H_5}Cl + {H_2} \xrightarrow{Pd/c} {C_2}{H_6} + HCl$
This reaction is used for the preparation of pure alkanes.
View full question & answer→