Hence, $2$ chiral compounds are formed in the above reaction.

$\begin{array}{*{20}{c}}
  {C{H_3} - C{H_2} - \mathop C\limits^* H - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$ $\xrightarrow{{C{l_2}}}$ $\mathop {\begin{array}{*{20}{c}}
  {C{H_3}C{H_2} - \mathop C\limits^* H - C{H_2}Cl} \\ 
  {|\,\,} \\ 
  {\,\,\,\,\,C{H_3}} 
\end{array}}\limits_{(I)} $ $\mathop {\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} 
\end{array}} \\ 
  { + \,C{H_3}C{H_2} - C - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}}\limits_{(II)} $ $\mathop { + \,\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,Cl}\,\,\,\, \\ 
  | \,\,\,\,
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - \mathop C\limits_* H - CH - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}}\limits_{(III)} $ $ + \,\mathop {\begin{array}{*{20}{c}}
  {C{H_2}C{H_2} - CH - C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,} \\ 
  {Cl\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,} 
\end{array}}\limits_{(IV)} $