Hence, \(2\) chiral compounds are formed in the above reaction.
\(\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - \mathop C\limits^* H - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}\) \(\xrightarrow{{C{l_2}}}\) \(\mathop {\begin{array}{*{20}{c}}
{C{H_3}C{H_2} - \mathop C\limits^* H - C{H_2}Cl} \\
{|\,\,} \\
{\,\,\,\,\,C{H_3}}
\end{array}}\limits_{(I)} \) \(\mathop {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,}
\end{array}} \\
{ + \,C{H_3}C{H_2} - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{(II)} \) \(\mathop { + \,\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,Cl}\,\,\,\, \\
| \,\,\,\,
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - \mathop C\limits_* H - CH - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{(III)} \) \( + \,\mathop {\begin{array}{*{20}{c}}
{C{H_2}C{H_2} - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,}
\end{array}}\limits_{(IV)} \)

${CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} \xrightarrow[\Delta]{\mathrm{KOH}_{(a k)}} \mathrm{A} \xrightarrow{\mathrm{HBr}} \mathrm{B} \xrightarrow[\mathrm{KOH}_{(a) i}]{\Delta} \mathrm{C}$
$(I)\,C{H_3}C{H_2}C{H_2}Cl$ $(II)\,C{H_2} = CH - CH(Cl)C{H_3}$
$(III)\,C{H_3}C{H_2}CH(Cl)C{H_3}$

