MCQ
$2 \pi-\left(\sin ^{-1} \frac{4}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{16}{65}\right)$ is equal to
  • A
    $\frac{7 \pi}{4}$
  • B
    $\frac{5 \pi}{4}$
  • $\frac{3 \pi}{2}$
  • D
    $\frac{\pi}{2}$

Answer

Correct option: C.
$\frac{3 \pi}{2}$
c
$2 \pi-\left(\sin ^{-1}\left(\frac{4}{5}\right)+\sin ^{-1}\left(\frac{5}{13}\right)+\sin ^{-1}\left(\frac{16}{65}\right)\right)$

$=2 \pi-\left(\tan ^{-1}\left(\frac{4}{3}\right)+\tan ^{-1}\left(\frac{5}{12}\right)+\tan ^{-1}\left(\frac{16}{63}\right)\right)$

$=2 \pi-\left(\tan ^{-1}\left(\frac{63}{16}\right)+\tan ^{-1}\left(\frac{16}{63}\right)\right)$

$=2 \pi-\frac{\pi}{2}=\frac{3 \pi}{2}$

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