2 ^ -1 1 3 + ^ -1 1 7 = - Vidyadip

MCQ

$2 \tan ^{-1} \frac{1}{3}+\tan ^{-1} \frac{1}{7}=$

A
$\tan ^{-1} \frac{4}{5}$
B
$\frac{\pi}{2}$
C
1
✓
$\frac{\pi}{4}$

✓

Answer

Correct option: D.

$\frac{\pi}{4}$

(d) $\frac{\pi}{4}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Trigonometric Functions→Trigonometric Functions — all question types→Maths STD 12 Science question papers→Maharashtra Board STD 12 Science question papers→Maharashtra Board question paper generator→

Similar questions

If $\text{f(x)}=\begin{cases}\frac{\sin(\cos\text{x})-\cos\text{x}}{(\pi-2\text{x})^2},&\text{x}\neq\frac{\pi}{2}\\\text{k},&\text{x}=\frac{\pi}{2}\end{cases}$ is continuous at $\text{x}=\frac{\pi}{2},$ then $k$ is equal to:

If $|\bar{a}|=3,|\bar{b}|=4$, then the value of $\lambda$ for which $\bar{a}+\lambda \bar{b}$ is perpendicular to $\bar{a}-\lambda \bar{b}$ is

If the determinant $\begin{vmatrix}\text{a}&\text{b}&2\text{a}\alpha+3\text{b}\\\text{b}&\text{c}&2\text{b}\alpha+3\text{c}\\2\text{a}\alpha+ 3\text{b}&2\text{b}\alpha+3\text{c}&0\end{vmatrix}=0,$ then:

The eqution of the plane contaning the two lines $\frac{\text{x}-1}{2}=\frac{\text{y}+1}{-1}=\frac{\text{z}-0}{3}$ and $\frac{\text{x}}{-2}=\frac{\text{y}-2}{-3}=\frac{\text{z}+1}{-1}$ is:

If $\bar{a} \cdot \hat{i}=\bar{a} \cdot(\hat{i}+\hat{j})=\bar{a} \cdot(\hat{i}+\hat{j}+\hat{k})$, then $\bar{a}$ is equal to

The value of objective function is maximum under linear constraints

The area bounded by the parabola $y^2=32 x$ the $X$-axis and the latus rectum is ____ sq.units

If $\text{P(A)}=\frac{3}{10},\text{P(B)}=\frac{2}{5}$ and $\text{P}(\text{A}\cap\text{B}=\frac{3}{5,}$ then $P(A|B) + P(B|A)$ equals

If one side of a triangle is double the other and the angles opposite to these sides differ by $60^{\circ}$, then the triangle is