- A$2$
- B$3$
- ✓$1$
- D$4$
$Ca ( OH )_2+2 HCl \rightarrow CaCl _2+2 H _2 O$
Volume of $Ca ( OH )_2=10 ml$
Volume of $HCl =20 ml$
Concentration of $HCl =0.5 M$.
No. of milli moles of $HCl =10$
No. of milli moles of $Ca ( OH )_2=5$.
$\text { i.e. }M _{ Ca ( OH )_2}=\frac{\text { no. of milli moles }}{ V ( ml )}=\frac{5}{10}$
$=0.5\,M.$
Reaction with $H _2 SO _4$
$Ca ( OH )_2+ H _2 SO _4 \rightarrow CaSO _4+2 H _2 O$
No. of milli moles of $Ca ( OH )_2=20 \times 0.5$
$=10$
i.e. no. of milli moles of $H _2 SO _4=10$
$\Rightarrow M _{ H _2 so }=\frac{\text { no. of mil lim oles }}{ V ( ml )}$
$=\frac{10}{10}$
$=1\,M$
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