$20\,\mu A$ current flows for $30$ seconds in a wire, transfer of charge will be
A$2 \times {10^{ - 4}}\,C$
B$4 \times {10^{ - 4}}\,C$
C$6 \times {10^{ - 4}}\,C$
D$8 \times {10^{ - 4}}\,C$
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C$6 \times {10^{ - 4}}\,C$
c (c) $ Q = it = 20 \times {10^{ - 6}}\,C \times 30 = 6 \times {10^{ - 4}}\,C$
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