$21.5\ g$ of sodium chloride dissolves in $60\ g$ of water at $25^\circ\ C$. Calculate the solubility of sodium chloride at that temperature.
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$21.5\ g$ of $NaCl$ dissolves in $60g$ of water.
So, amount of $NaCl$ which gets dissolved in $100\ g$ of water $=\frac{21.5\times 100}{60}=35.8\text{g}$
Thus, the solubility of $NaCl$ is $35.8\ g$ at $25^\circ\ C$
So, amount of $NaCl$ which gets dissolved in $100\ g$ of water $=\frac{21.5\times 100}{60}=35.8\text{g}$
Thus, the solubility of $NaCl$ is $35.8\ g$ at $25^\circ\ C$
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