\(\therefore \,\,\,\,0 = 0.591 - 0.0591\,\,\,\log \,{K_c}\)
\(\therefore \frac{{0.591}}{{0.0591}} = \log \,{K_c}\,\,\,\,\therefore \,\,\,10 = \log \,{K_c}\,\)
\(\,\therefore \,\,\,{K_c} = {10^{10}}\)
$M/M^+ | | N^+/N$
${{\text{E}}^o }{\text{C}}{{\text{u}}^{{\text{2}} + }}{\text{/Cu = + 0}}{\text{.34 V, E}}_{{\text{F}}{{\text{e}}^{ + {\text{2}}}}/Fe}^o = \,\,{\text{ - 0}}{\text{.44 V}}$