$25\,^oC$ તાપમાને $AgI$ નો દ્રાવ્યતા ગુણાકાર $1.0 \times {10^{ - 16}}\,mo{l^2}\,{L^{ - 2}}$ છે. તો $25\,^oC$ તાપમાને $KI$ ના ${10^{ - 4}}\,N$ દ્રાવણમાં $AgI$ ની દ્રાવ્યતા $(mol \, {L^{ - 1}})$ આશરે ..... થશે.

Question

A$1.0 \times {10^{ - 8}}$
B$1.0 \times {10^{ - 16}}$
C$1.0 \times {10^{ - 12}}$
D$1.0 \times {10^{ - 10}}$

AIPMT 2003, Medium

Download our app for free and get started

Solution

c
(c) $AgI$ $ \rightleftharpoons $ $\mathop {A{g^ + }}\limits_{(s)} + \mathop {{I^ - }}\limits_{(s)\,\,} $; ${K_{sp}} = {S^2} = {10^{ - 4}} \times S$

$S = \frac{{1.0 \times {{10}^{ - 16}}}}{{{{10}^{ - 4}}}} = 1 \times {10^{ - 12}}\frac{{mo{l^2}}}{{{l^2}}}$

ઍસિડ	$K_a$
$HCN$	$6.2\times 10^{-10}$
$HF$	$7.2\times 10^{-4}$
$HNO_2$	$4.0\times 10^{-4}$

Download our app
and get started for free

Similar Questions

Download our appand get started for free

Similar Questions

Download our app
and get started for free