Question
$2(5x - 3) - 3(2x - 1) = 9$
✓
Answer
We have $2(5x - 3) - 3(2x - 1) = 9$
Expanding the brackets, we get
$2 \times 5x - 2 \times 3 - 3 \times 2x + 3 \times 1 = 9 10x - 6 - 6x + 3 = 9 10x - 6x - 6 + 3 = 9 4x - 3 = 9$
Adding 3 to both sides, we get $4x - 3 + 3 = 9 + 3 4x = 12$
Dividing both sides by $4$, we get
$\frac{4\text{x}}{4}=\frac{12}{4}$
Thus, $x = 3$. Verification: Substituting $x = 3$ in $L.H.S$., we get
$= 2(5 \times 3 - 3) - 3(2 \times 3 - 1) = 2 \times 12 - 3 \times 5 = 24 - 15 = 9 $
$L.H.S. = R.H.S.$
Hence, verified.
Expanding the brackets, we get
$2 \times 5x - 2 \times 3 - 3 \times 2x + 3 \times 1 = 9 10x - 6 - 6x + 3 = 9 10x - 6x - 6 + 3 = 9 4x - 3 = 9$
Adding 3 to both sides, we get $4x - 3 + 3 = 9 + 3 4x = 12$
Dividing both sides by $4$, we get
$\frac{4\text{x}}{4}=\frac{12}{4}$
Thus, $x = 3$. Verification: Substituting $x = 3$ in $L.H.S$., we get
$= 2(5 \times 3 - 3) - 3(2 \times 3 - 1) = 2 \times 12 - 3 \times 5 = 24 - 15 = 9 $
$L.H.S. = R.H.S.$
Hence, verified.
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