Question
Simplify the following: $4+\frac{1}{5}\Big[\big\{-10\times(25-\overline{13-3})\big\}\div(-5)\Big]$
✓
Answer
$4+\frac{1}{5}\Big[\big\{-10\times(25-\overline{13-3})\big\}\div(-5)\Big]$
$=4+\frac{1}{5}\big[\{-10\times(25-10)\}\div(-5)\big]$
$=4+\frac{1}{5}\big[\{-10\times(15)\}\div(-5)\big]$
$=4+\frac{1}{5}\big[(-150)\div(-5)\big]$
$=4+\frac{1}{5}\big[30\big]$
$=4+6$
$=10$
$\therefore\ 4+\frac{1}{5}\Big[\big\{-10\times(25-\overline{13-3})\big\}\div(-5)\Big]=10$
$=4+\frac{1}{5}\big[\{-10\times(25-10)\}\div(-5)\big]$
$=4+\frac{1}{5}\big[\{-10\times(15)\}\div(-5)\big]$
$=4+\frac{1}{5}\big[(-150)\div(-5)\big]$
$=4+\frac{1}{5}\big[30\big]$
$=4+6$
$=10$
$\therefore\ 4+\frac{1}{5}\Big[\big\{-10\times(25-\overline{13-3})\big\}\div(-5)\Big]=10$
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